如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Sketch Coloring Page

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Template

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Sofie Emilie Valentin Jeske
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tomski如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 coloring

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

正三棱锥的高是多� 百度经验 sketch template

正三棱锥 知乎 sketch template

三棱锥图片直观图 千图� sketch template

一个三棱锥，如果它的底面是直角三角形，那么它的三个侧面（） A．必定都不是直角三角形 B．至多有一个直角三角形 C．至多有两个直角三 百度教育 sketch template

三棱锥专题 Word文档在线阅读与下载免费文档 sketch template

一个三棱锥的各个面均为正三角形以每个面的中心为顶点构成一个新三棱锥若新三棱锥体积为2求原三棱锥体百度知道 sketch template

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

高中数学第一册上棱锥 Word文档在线阅读与下载无忧文档 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

1． 棱锥的定义正棱锥的定义底面是正多边形顶点在底面上的射影是底面的中心——青夏教育精英家教�—— sketch template

下面有四个�题1各个侧面都是等腰三角形的棱锥是正棱锥2三条侧棱都相等的棱锥是正棱锥3底面是正三角形的棱锥是正三棱锥4 sketch template

81 基本立体图形1 棱柱、棱锥、棱台湛江贵哥讲数学博客园 sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

15．三棱锥P ABC的四个顶点在同一球面上若PA⊥底面ABC底面ABC是直角三角形PA＝2AC＝BC＝1则此球的表面积为——青夏 sketch template

11．底面边长为2的正三棱锥P ABC中E是BC的中点若 PAE的面积为则侧棱PA与底面所成角的正切值是 A．1 B． C． D．——青 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图三棱锥P ABC的底面ABC是以AC为斜边的直角三角形且顶点P在底面的射影是 ABC外心设PB=AB=1BC=2．1求证面 sketch template

已知正三棱柱ABC A1B1C1的底面边长为2高为4过BC作一截面截面与底面ABC成600角则截面面积是 A．4 B． C． D sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图已知正三棱柱 的底面边长为2侧棱长为点E在侧棱上点F在侧棱上且 I 求证 II 求直线与平面的夹角题目和参考 sketch template

如图四棱锥P ABCD的底面ABCD为一直角梯形侧面PAD是等边三角形其中BA⊥ADCD⊥ADCD=2AD=2AB=2平面PAD⊥ sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

$如图所示四棱锥P ABCD中PA⊥平面ABCDPB与底面所成的角为$frac{π}{4}$底面ABCD为直角梯形∠ABC=∠BAD sketch template$

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA=PD=AD=2EF分别为PCBD的中点．Ⅰ sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

19．如图所示四棱锥P ABCD中底面ABCD为直角梯形点E在棱PA上且PE=2EA 1 求异面直线PA与CD所成的角 2 sketch template

如图所示，四棱锥的底面为矩阵，其中一条棱垂直于底面，那么该四棱锥的俯视图最有可能是：【2025广东0 星光公考公务�考试公考 2025 sketch template

如图四棱锥P ABCD中底面四边形ABCD是正方形侧面PDC是边长为a的正三角形且平面PDC⊥底面ABCDE为PC的中点 ——青夏 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

11．如图四棱锥P ABCD的底面ABCD是边长为2的正方形侧面PAB是正三角形且与底面垂直E为PD中点过直线BC和点E的平面与侧棱 sketch template

如图，在四棱锥中，底面是梯形，，侧面是等边三角形，侧面是等腰直角三角形， sketch template

如图已知四棱锥S ABCD的侧面SCD⊥底面ABCDBC∥ADBC⊥SC且SC=SD=CD=BC=2AD =2P为SB的中点求 sketch template

如图，已知六棱锥的底面是正六边形，则下列结论正确的是 A． B． C．直线∥ D．直线所成的角为45°——青夏教育精英家教�—— sketch template

19． 如图四棱锥E ABCD中底面ABCD为正方形EC⊥平面ABCDAB=CE=1G为AC与BD交点F为EG中点 Ⅰ求证 sketch template

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