如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Sketch Coloring Page

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Template

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tomski如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 coloring

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

4．如图已知三棱锥的底面是直角三角形直角边长分别为3和4 过直角顶点的侧棱长为4且垂直于底面该三棱锥的正视图是 ——青夏教育精英 sketch template

正三棱锥的高是多� 百度经验 sketch template

三棱锥图片直观图 千图� sketch template

一个三棱锥，如果它的底面是直角三角形，那么它的三个侧面（） A．必定都不是直角三角形 B．至多有一个直角三角形 C．至多有两个直角三 百度教育 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

已知三棱锥P ABC中顶点P在底面的射影O是三角形ABC的内心关于这个三棱锥有三个�题�侧棱PA=PB=PC�侧棱PAPBPC两两 sketch template

下面有四个�题1各个侧面都是等腰三角形的棱锥是正棱锥2三条侧棱都相等的棱锥是正棱锥3底面是正三角形的棱锥是正三棱锥4 sketch template

如图，已知正三棱锥P ABC的侧面是直角三角形，PA=6，顶点P在平面ABC内的正投影为点D，D在平面PAB内的正投影为点E，连接PE并延长交 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图，在四棱锥中，底面是梯形，，侧面是等边三角形，侧面是等腰直角三角形， sketch template

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

如图所示四棱锥P ABCD的底面ABCD是边长为a的正方形侧棱PA=a PB=PD=a则它的5个面中互相垂直的面有对——青夏教育 sketch template

如图在四棱锥P ABCD中底面ABCD为直角梯形AD∥BC∠ADC=90°平面PAD⊥底面ABCDQ为AD的中点PA=PD=2 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

题目如图四棱锥的底面是矩形点为的中点与交于点Ⅰ求异面直线与所成角的余弦值Ⅱ求证Ⅲ求直线与平面所成角的正弦值 sketch template

如图已知四棱锥S ABCD的底面是直角梯形AB∥DC∠DAB=90°SA⊥底面ABCD且SA=AD=DC=12AB=1M是SB的中点 sketch template

如图三棱锥P ABC的底面ABC是以AC为斜边的直角三角形且顶点P在底面的射影是 ABC外心设PB=AB=1BC=2．1求证面 sketch template

已知四棱锥P ABCD的底面为直角梯形AB∥DC∠DAB=90°PA⊥底面ABCD且PA=AD=DC=12AB=1．Ⅰ证明面 sketch template

如图，在四棱锥P ABCD中，底面ABCD是平行四边形，∠BCD=120°，侧面PAB⊥底面ABCD，PB=2√6，AB=AC=PA=2√3 sketch template

如图在四棱锥P ABCD中PA⊥平面ABCD底面ABCD为直角梯形AB⊥ADAB∥CDCD=AD=2AB=2AP．1求证平面 sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

19．如图四棱锥S ABCD的底面是直角梯形∠ABC＝∠BCD＝90°AB＝BC＝SB＝SC＝2CD＝2侧面SBC⊥底面ABCD sketch template

如图在四棱锥P ABCD中PA⊥平面ABCD底面ABCD为平行四边形且AB=1BC=2EF分别为ADBC的中点．I求证 sketch template

如图在底面是直角梯形的四棱锥S ABCD中面ABCD SA=AB=BC=1AD= Ⅰ求四棱锥S ABCD的体积 Ⅱ求面SCD sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图已知四棱锥P ABCD的底面为直角梯形AB∥CD∠DAB=90°PA⊥底面ABCD且PA=AD=DC=12AB=1M是PB的 sketch template

如图，四棱锥的底面是直角梯形，，平面是的中点，与平面交于点 sketch template

如图已知四棱锥S ABCD的底面是直角梯形AB∥DC∠DAB=90°SA⊥底面ABCD且SA=AD=DC=12AB=1M是SB的中点 sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

如图四棱锥P ABCD中PA⊥平面ABCD底面ABCD是直角梯形且AB∥CD∠BAD=90°PA=AD=DC=2AB=4．1 sketch template

练题本立体几何9 副本 Word文档在线阅读与下载免费文档 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

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