已知如图以rt Abc的三边为斜边分别�外作等腰直角三角形．若斜边ab＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— Sketch Coloring Page

已知如图以rt Abc的三边为斜边分别�外作等腰直角三角形．若斜边ab＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— Template

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sketch #1041 strawberries

anonymous

anonymous
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anonymous

anonymous
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sketch #3727 Stitch by Louis Tradieu

anonymous

anonymous
sketch #3727 Stitch by Louis Tradieu

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anonymous

anonymous
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sketch #1133 vinks

anonymous

anonymous
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sketch #21085 Tobirama by Enrique L. Manly

anonymous

anonymous
sketch #21085 Tobirama by Enrique L. Manly

sketch #3516

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sketch #2636 Robitina by sketchmaster

sketchmaster
sketch #2636 Robitina by sketchmaster

sketch #5249 Adele - Skyfall by Mert Arda Yiğit

anonymous

anonymous
sketch #5249 Adele - Skyfall by Mert Arda Yiğit

sketch #249 Rocket

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anonymous

anonymous
sketch #4653 Kero by Indike Liyanage

sketch #5117

anonymous

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sketch #1450

anonymous

anonymous
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sketch #2881 Mickey Mouse by Michael Angcay

anonymous

anonymous
sketch #2881 Mickey Mouse by Michael Angcay

sketch #3575 Stitch by Laura Gutierrez Hinojosa

anonymous

anonymous
sketch #3575 Stitch by Laura Gutierrez Hinojosa

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Chris Shrimp Lonsdale
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sketch #5173 Super Meat Boy by Zorka Edding Giustinianovic

anonymous

anonymous
sketch #5173 Super Meat Boy by Zorka Edding Giustinianovic

sketch #3197 Dragon by Yuryi Zambrano

anonymous

anonymous
sketch #3197 Dragon by Yuryi Zambrano

sketch #3321 Baby Mirella Flowers

anonymous

anonymous
sketch #3321 Baby Mirella Flowers

sketch #3939

anonymous

anonymous
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sketch #779 Gol D Roger

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sketch #2813 Stan from South Park by Amer Amimer

Amer Amimer
sketch #2813 Stan from South Park by Amer Amimer

sketch #2937 Spongebob by Kalana Namikaze

anonymous

anonymous
sketch #2937 Spongebob by Kalana Namikaze

sketch #3581 Dante

anonymous

anonymous
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sketch #5225 The Friendship by Annabelle Bourget

anonymous

anonymous
sketch #5225 The Friendship by Annabelle Bourget

tomski已知如图以rt abc的三边为斜边分别�外作等腰直角三角形．若斜边ab＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— coloring

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— sketch template

已知如图在Rt ABC中∠ACB=90°点D在边AC上点E是BD的中点CE的延长线交边AB于点F且∠CED=∠A．1求证 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示则不难证明S1=S2 S3．1如图�分别以直角 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示 1 如图�分别以直角三角形ABC三边为 sketch template

百度教育 sketch template

如图已知Rt ABC中∠ACB=90°∠B＞∠A在 ABC内找一点E使得 EBC和 ABC相似小聪的做法是取AB边上的中线CD sketch template

如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB=4则图中阴影部分的面积为 ．题目和参考答案——青夏教育精英家教�—— sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— sketch template

如图，已知以 ABC的边AB、AC分别�外作等腰Rt ABD与等腰Rt ACE，其中∠BAD=∠CAE=90°，连接BE、CD，BE和CD相交 sketch template

已知如图�Rt ABC中∠ACB=90°AC=BC点DE在斜边AB上且∠DCE=45°AB=4．1在图中找出两对相似三角形 sketch template

21． 已知如图Rt ABC≌Rt ADE∠ABC＝∠ADE=900试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段 sketch template

25．已知如图在Rt ABC中∠C=90°∠1=∠2CD=15BD=25求AC的长——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ACB=90°CD⊥AB于D设AC=bBC=aCD=hAB=c下面有3个�题11a2 1b2 sketch template

如图已知Rt ABC中∠B=90°tanC=05AB=1在 ABC内有一系列正方形求所有这些正方形面积之和题目和参考答案 sketch template

图� 图� 1 已知如图�Rt ABC中∠ACB=90°AC=BC——青夏教育精英家教�—— sketch template

已知如图在Rt ABC中∠ACB＝900AD平分∠CAB交BC于点D过点C作CE⊥AD垂足为ECE的延长线交AB于点F过点E作 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

如图所示已知Rt ABC中AH为斜边BC上的高M为BC中点O为 ABC外心OB交AH于D．求证AD=2DH．题目和参考答案——青 sketch template

如图，在Rt ABC中，∠ACB=90°，M为AB边的中点，将Rt ABC绕点M旋转，使点A与点C重合得到 CED，连接M A 若∠B=26 sketch template

24．．如图已知以Rt ABC的直角边AB为直径作⊙O与斜边AC交于点DE为BC边上的中点连结DE 1 如图所示观察猜想DE sketch template

如右图在Rt ABC中如果已知两个元素ab分别为∠A∠B的对边c为斜边如果已知两个元素a∠B就可以求出其余三个元素bc∠A sketch template

题目已知如图在Rt ABC和Rt ACD中AC=BC∠ACB=90°∠ADC=90°CD=2点AB分别在直线CD的左右 sketch template

如图等腰Rt ABC的直角边ABAC分别与圆O相切于点EDAD=3DC=5直线FG与ACBC分别交于点FG且∠CFG=60 sketch template

如图M为Rt ABC斜边BC的中点PQ分别在边ABBC上且BP=5CQ=3PM⊥QM则PQ= ．题目和参考答案——青夏教育 sketch template

如图在Rt ABC中∠C=90°D为AC上一点且DA=DB=5又 DAB的面积为10那么DC的长是 A4 B3 C5 sketch template

已知如图Rt ABC≌Rt ADE∠ABC＝∠ADE=90°试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段满足相等 sketch template

25．如图Rt AB ¢C ¢ 是由Rt ABC绕点A顺时针旋转得到的连结CC 交斜边于点ECC 的延长线交BB 于点F sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

如图⊙O是Rt ABC的外接圆∠ABC=90°点P是圆外一点PA切⊙O于点A且PA=PB．1求证PB是⊙O的切线2已知 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

如图已知Rt ABC的斜边AB=8cmAC=4cm．1以点C为圆心作圆当半径为多长时直线AB与⊙C相切为什么2以点C为圆心 sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4将边AC沿CE翻折使点A落在AB上的点D处再将边BC沿CF翻折使点B落在 sketch template

如图已知Rt ABC≌Rt DEF∠C=∠F=90°AC=DF=3BC=EF=4 DEF绕着斜边AB的中点D旋转DEDF分别交 sketch template

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