21． 已知如图rt abc≌rt Ade∠abc＝∠ade=900试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段 Sketch Coloring Page

21． 已知如图rt abc≌rt Ade∠abc＝∠ade=900试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段 Template

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sketch #3484 Red Hot Chili Peppers by Nik Zulqarnain

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sketch #5200 Kristen Stewart by Rhemzkian Esturco

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tomski21． 已知如图rt abc≌rt coloring

21． 已知如图Rt ABC≌Rt ADE∠ABC＝∠ADE=900试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段 sketch template

已知如图Rt ABC≌Rt ADE∠ABC＝∠ADE=90°试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段满足相等 sketch template

如图在Rt ABC与Rt DCB中已知∠A=∠D=90°请你添加一个条件使Rt ABC≌Rt DCB你添加的条件是AB=DC．题目 sketch template

21如图，已知等腰直角三角形ABC，点P是斜边BC上一点不与B，C重合，PE是 ABP的外接圆⊙O的直径．1求证： APE是等腰直角 sketch template

已知如图Rt ABC≌Rt ADE∠ABC＝∠ADE=90°试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段满足相等 sketch template

百度教育 sketch template

如图，Rt ABC中，∠C=90°，AC=3，BC=4分别以AB，AC，BC为边在AB的同侧作正方形ABEF，ACPQ，BCMN，四块阴影 sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为．——青夏教育精英家教�—— sketch template

已知Rt ABC中AB=AC∠BAC=90°点D为直线BC上的一动点以AD为边作Rt ADEAD=AE连接CE．1�现问题如 sketch template

如图�，Rt ABC中，∠ACB=90°，点D为边AC上一点，DE⊥AB于点E，点M为BD中点，点N为CM中点，CM的延长线交AB于点F sketch template

图� 图� 1 已知如图�Rt ABC中∠ACB=90°AC=BC——青夏教育精英家教�—— sketch template

如图若要用“HL 证明Rt ABC≌Rt ABD则还需补充条件 A∠BAC=∠BADBAC=AD或BC=BDCAC=AD且BC sketch template

已知Rt ABC中AB=AC∠BAC=90°点D为直线BC上的一动点以AD为边作Rt ADEAD=AE连接CE．1�现问题如 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图以Rt ABC的直角边AC和斜边AB为边分别作Rt ADC和正方形ABEF再以AD作正方形ADGH．已知∠ACB=90°正方形 sketch template

如图已知Rt ABC≌Rt DEF∠C=∠F=90°AC=DF=3BC=EF=4 DEF绕着斜边AB的中点D旋转DEDF分别交 sketch template

21． 如图点EC在线段BF上BE=CF请在下列四个等式中�AB＝DE�∠ACB＝∠F �∠A＝∠D�AC＝DF．选出两个作为 sketch template

已知如图Rt ABC中AC=2BC∠ABC=90°将Rt ABC绕点C按顺时针方�旋转使顶点B落在AC上的点E处得到 DEC再 sketch template

Artemis I Orbital Route Coloring Sheet Natural Inquirer sketch template

صورة من Http//wwwhonkingdonkeycom/activity Pages/alphabet/ABC sketch template

已知如图在 ABC中∠C=90°∠B=30°AC=6点D在边BC上AD平分∠CABE为AC上的一个动点EF⊥AB垂足为F sketch template

如图 ABC≌ CDAADBC交于点P∠BCA=40°则∠APB=80度．题目和参考答案——青夏教育精英家教�—— sketch template

已知Rt ABC中∠C=90°若a B=14cmc=10cm则Rt ABC的面积是 A24cm2B36cm2C48cm2D sketch template

已知如图BDCE是 ABC的高且BD=CE．求证∠BCE=∠CBD．题目和参考答案——青夏教育精英家教�—— sketch template

已知如图AB=ADCB⊥ABCD⊥ADEF分别是BCDC的中点求证AE=AF．题目和参考答案——青夏教育精英家教�—— sketch template

题目已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 A 9 B 3 C sketch template

如图已知 ABC中∠C=90°点E在边AB上请过点E作一条直线与 ABC的其他边相交于一点D使得以点AED为顶点的三角形与 sketch template

如图Rt ABC中∠BAC=90°将 ABC绕点C逆时针旋转旋转后的图形是 A′B′C点A的对应点A′落在中线AD上且点A′是 sketch template

已知如图在Rt ABC中∠C=90°点O在AB上以O为圆心OA长为半径的圆与ACAB分别交于点DE且∠CBD=∠A．1 sketch template

如图已知 ABC≌ ADE∠C=∠EBC=DE 其它的对应边有对应角有想一想 ∠ BAD= CAE吗为什么 sketch template

2．已知如图∠1=∠2=∠3求证 ABC∽ ADE．——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ACB=90°BD平分∠ABC若CD=3BC AB=16则 ABC的面积为．题目和参考答案——青夏教育 sketch template

如图在 ABE中已知AB=AEAD=AC∠1=∠2．求证 ABC≌ AED．题目和参考答案——青夏教育精英家教�—— sketch template

如图Rt ABC中∠ACB=90°．1分别以ABAC为边�外作等边三角形ABD和等边三角形ACE连接CE交AB于点F若∠BAC sketch template

如图Rt ABC中∠ACB=90°．1分别以ABAC为边�外作等边三角形ABD和等边三角形ACE连接CE交AB于点F若∠BAC sketch template

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