已知四棱锥的底面是矩形底面点分别是棱中点则 �棱与所在直线垂直 �平面与平面垂直 �的面积大于的面积 �直线与直线是异面直线以上结论 Sketch Coloring Page

已知四棱锥的底面是矩形底面点分别是棱中点则 �棱与所在直线垂直 �平面与平面垂直 �的面积大于的面积 �直线与直线是异面直线以上结论 Template

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tomski已知四棱锥的底面是矩形底面点分别是棱中点则 �棱与所在直线垂直 �平面与平面垂直 coloring

12．如图所示在四棱锥P ABCD中底面ABCD是矩形PA＝AB＝2BC＝a又侧棱PA⊥底面ABCD 1当a为何值时BD⊥ sketch template

四棱锥的底面是矩形，顶点在底面内的射影是矩形对角线的交点，且四棱锥及其三视图如下（垂直于主视图投影平面）．则四棱锥的侧面积是 sketch template

已知四棱锥的底面是矩形底面点分别是棱中点则 �棱与所在直线垂直 �平面与平面垂直 �的面积大于的面积 �直线与直线是异面直线 以上结论 sketch template

18．在四棱锥P ABCD中底面ABCD是矩形侧棱 PA⊥底面ABCDAB=1直线PB与底面ABCD所成的角为45°四棱锥P sketch template

是不是底面是正方形的四棱锥就是正四棱锥？知乎 sketch template

题目如图四棱锥的底面是矩形点为的中点与交于点Ⅰ求异面直线与所成角的余弦值Ⅱ求证Ⅲ求直线与平面所成角的正弦值 sketch template

18．在四棱锥P ABCD中底面ABCD是矩形侧棱 PA⊥底面ABCDAB=1直线PB与底面ABCD所成的角为45°四棱锥P sketch template

正四棱锥图册 360百� sketch template

已知四棱锥P ABCD的底面ABCD是边长为2的正方形PD⊥底面ABCDEF分别为棱BCAD的中点．Ⅰ求证DE∥平面PFBⅡ sketch template

18．在四棱锥P ABCD中底面ABCD是矩形侧棱 PA⊥底面ABCDAB=1直线PB与底面ABCD所成的角为45°四棱锥P sketch template

19．如图四棱锥E ABCD中底面ABCD为正方形EC⊥平面ABCDAB=CE=1G为AC与BD交点F为EG中点 Ⅰ求证 sketch template

19．已知四棱锥P ABCD的底面ABCD的边长为1的正方形 PD⊥底面ABCD且PD=1 1求证BC//平面PAD 2若 sketch template

在四棱锥中其底面是正方形一条侧棱垂直于底面不通过此棱的一个侧面与底面所成的二面角为45°且最长的侧棱长为15cm则棱锥的高为 sketch template

如图在底面是矩形的四棱锥P ABCD中PA⊥面ABCDPA=ADMN分别是PCAB的中点 1求直线PD与面ABCD所成的角 sketch template

已知四棱锥P ABCD中 底面ABCD为平行四边形 点MNQ分别在PABDPD上且PMMA=BNND=PQQD 求证 sketch template

10．四棱锥P ABCD中底面ABCD是矩形AB＝1cmAD＝cm并且PA平面ABCD PA＝2cm点Q是平面PCD上一个动点则 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

18．四棱锥P ABCD中侧面PAD底面ABCD底面ABCD是矩形BC=2CD=2又PA=PDEG分别是BCPE的中点 1 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图已知在四棱锥P ABCD中底面ABCD是边长为4的正方形 PAD是正三角形EFG分别是PDPCBC的中点．1求证直线 sketch template

如图四棱锥P ABCD中底面四边形ABCD是正方形侧面PDC是边长为a的正三角形且平面PDC⊥底面ABCDE为PC的中点 ——青夏 sketch template

已知四棱锥S ABCD中AB=BC=CD=DA=SA=2底面ABCD是正方形SD=SB=22．I在该四棱锥中是否存在一条侧棱垂直于 sketch template

已知四棱锥P ABCD的底面为直角梯形AB∥DC∠DAB=90°PA⊥底面ABCD且PA=AD=DC=12AB=1．Ⅰ证明面 sketch template

已知四棱锥S ABCD中AB=BC=CD=DA=SA=2底面ABCD是正方形SD=SB=22．I在该四棱锥中是否存在一条侧棱垂直于 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图在四棱锥P ABCD中底面ABCD是矩形侧棱PA垂直于底面EF分别是ABPC的中点 1求证CD⊥PD 2求证 sketch template

四棱锥 360百� sketch template

已知四棱锥P ABCD的底面是边长为6的正方形侧棱PA⊥底面ABCD且PA=8则该四棱锥的体积是 A．288B．96C．48D sketch template

已知正四棱锥底面正方形的边长为4cm高与斜面的夹角为30°如图所示求正四棱锥的侧面积和表面积单位cm2．题目和参考答案——青夏 sketch template

如图是一个四棱柱被一个平面所截的几何体，底面是正方形，M是的中点， sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

8．已知四棱锥P ABCD中底面ABCD是边长为1的菱形∠ABC = 60°PA⊥底面ABCDPA 1则异面直线AB与PD所成的 sketch template

20． 已知直四棱柱ABCD A1B1C1D1底面是矩形又A1A=ABEF分别是BD1和AD中点 1求异面直线CD1EF所成的角 sketch template

19．已知四棱锥P ABCD的底面ABCD的边长为1的正方形 PD⊥底面ABCD且PD=1 1求证BC//平面PAD 2若 sketch template

如图已知直四棱柱ABCD A1B1C1D1的底面边长和侧棱长均为1且满足∠BAD=60°O1为A1C1的中点．1求证BD⊥A1C sketch template

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