5．如图在rt abc中cd是斜边ab上的高则图中的相似三角形共有 3对 D4对提示考�rt abc与rt Acd Sketch Coloring Page

5．如图在rt abc中cd是斜边ab上的高则图中的相似三角形共有 3对 D4对提示考�rt abc与rt Acd Template

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sketch #2866 Soul Eater by Ani Chachua

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sketch #2866 Soul Eater by Ani Chachua

sketch #5130 Batman by Kamal Ahmed Tantawy

anonymous

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sketch #5130 Batman by Kamal Ahmed Tantawy

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sketch #2309

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sketch #4279 Winnie the Pooh by Douglas Dalmora

anonymous

anonymous
sketch #4279 Winnie the Pooh by Douglas Dalmora

sketch #1846 zay

anonymous

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sketch #1846 zay

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sketch #1061 garota ao vento

Ariel Fernando
sketch #1061 garota ao vento

sketch #1964 愛鼠繪

愛君
sketch #1964 愛鼠繪

sketch #2560

anonymous

anonymous
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sketch #2668 Butterfly by Loai Issa

Loai Issa
sketch #2668 Butterfly by Loai Issa

sketch #4874 Milla Jovovich by Kimmy Kitty Perry Priemus

anonymous

anonymous
sketch #4874 Milla Jovovich by Kimmy Kitty Perry Priemus

sketch #5270 Fresh prince by Fatér Szilvia

anonymous

anonymous
sketch #5270 Fresh prince by Fatér Szilvia

sketch #859 meyvalar

anonymous

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sketch #859 meyvalar

sketch #3908 Rawr! by Timothy Palfreyman

anonymous

anonymous
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sketch #2144

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tomski5．如图在rt abc中cd是斜边ab上的高则图中的相似三角形共有 3对 coloring

题目如图在Rt ABC中∠A=90°AB=6cmAC=8cm以斜边BC上距离B点6cm的点P为中心把这个三角形按逆时针方�旋转 sketch template

如图CD是Rt ABC斜边上的高则图中相似三角形的对数有 A0对B1对C2对D3对 题目和参考答案——青夏教育精英家教�—— sketch template

5．如图在Rt ABC中CD是斜边AB上的高则图中的相似三角形共有 3对 D4对 提示考�Rt ABC与Rt ACD sketch template

题目如图Rt ABC中∠BAC=90°AB=3AC=6点DE分别是边BCAC上的动点则DA DE的最小值为．题目和参考 sketch template

如图已知Rt ABC中∠ACB=90°∠B＞∠A在 ABC内找一点E使得 EBC和 ABC相似小聪的做法是取AB边上的中线CD sketch template

如图，在Rt ABC中，∠ C=90°，AC=8，BC=6，点P是AC边上一点，将 ACB沿着过点P的一条直线翻折，使得点A落在边AB上的点Q sketch template

如图在Rt ABC中∠BAC=90°AB=AC分别过点BC坐过点A的直线的垂线BDCE若BD=4CE=3则DE=A1B sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图在Rt ABC中∠ACB=90°CD⊥AB于D设AC=bBC=aCD=hAB=c下面有3个�题11a2 1b2 sketch template

题目1问题如图1在Rt ABC中∠BAC＝90°AB＝ACD为BC边上一点不与点BC重合将线段AD绕点A逆时针旋转90 sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为．——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ABC=90°BA=BC点D是AB的中点连接CD过点B作BG⊥CD分别交CDCA于点EF与过点A且 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

线段AE将长方形ABCD分成两部分已知空白部分比阴影部分的面积小18平方厘米求阴影部分的面积．题目和参考答案——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠C=90°．1根据要求用尺规作图过点C作斜边AB边上的高CD垂足为D不写作法只保留作图痕迹2证明 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

5．如图在Rt ABC中∠C=90°∠A=30°BD是∠ABC的平分线若BD=10则CD=——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ACB=90°CD⊥AB于D．1若AC=3AB=5求tan∠BCD．2若BD=1AD=3求tan∠ sketch template

题目已知如图在Rt ABC中∠ACB=90°D是边AB的中点CE=CBCD=5求1BC的长．2tanE的值 sketch template

如图在Rt ABC中∠BAC=90°AB=5AC=12P为边BC上一动点PE⊥AB于EPF⊥AC于FM为EF中点则AM的取值 sketch template

题目已知如图在Rt ABC和Rt ACD中AC=BC∠ACB=90°∠ADC=90°CD=2点AB分别在直线CD的左右 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图等腰Rt ABC中AC=BC以AC为直径作⊙O交AB于D点E为CD上的一个动点过E作AE的垂线交BC的延长线于点F连接AE sketch template

如图在Rt ABC中∠C=90°D为AC上一点且DA=DB=5又 DAB的面积为10那么DC的长是 A4 B3 C5 sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

题目如图在Rt ABC中∠C＝90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于MN的 sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为．——青夏教育精英家教�—— sketch template

如图，在Rt ABC中，∠ACB=90°，M为AB边的中点，将Rt ABC绕点M旋转，使点A与点C重合得到 CED，连接M A 若∠B=26 sketch template

如图在等腰Rt ABC中AC=BC以斜边AB为一边作等边 ABD使点CD在AB的同侧再以CD为一边作等边 CDE使点CE落在 sketch template

中线（几何概念）百度百� sketch template

题目已知在Rt ABC中∠ACB＝90°AC＝BC点D在直线AB上连接CD并把CD绕点C逆时针旋转90°到CE．1如图1 sketch template

如图在Rt ABC中∠ACB=90°AB=5BC=3过点C作CD⊥AB取AC的中点E连接DE则 DEC的�长是 A．2 sketch template

如图在Rt ABC中∠BAC=90°D为BC的中点连接ADE为AB上一点过E作EF∥BC交AD于F．1求证EF=AF．2 sketch template

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