24．如图甲四边形是等腰梯形由个这样的等腰梯形可以拼出图乙所示的平行四边形 1求四边形四个内角的度数 2试探究四边形四条边 Sketch Coloring Page

24．如图甲四边形是等腰梯形由个这样的等腰梯形可以拼出图乙所示的平行四边形 1求四边形四个内角的度数 2试探究四边形四条边 Template

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sketch #4300 República, comunismo, libertad

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sketch #4300 República, comunismo, libertad

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sketch #4640 Serj Tankian by Dav Guzman Mendoza

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sketch #2359 imazighen amazigh flag

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sketch #4751 Ruko by Rodrigo Marcos

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sketch #2884 Robot Shimun Yeyo Ahmed

tomski24．如图甲四边形是等腰梯形由个这样的等腰梯形可以拼出图乙所示的平行四边形 1求四边形四个内角的度数 coloring

24．如图甲四边形是等腰梯形 由个这样的等腰梯形可以拼出图乙所示的平行四边形 1求四边形四个内角的度数 2试探究四边形四条边 sketch template

如图用三个边长为a的等边三角形拼成如图1所示的等腰梯形现将这个等腰梯形截成四个全等的等腰梯形然后将其中的一个等腰梯形按照上述方法再截 sketch template

已知如图四边形ABCD是等腰梯形AB＝CD AD∥BC DE∥CA交BA的延长线于点E 求证ED·AB＝EA·BD——青夏教育 sketch template

如图等腰梯形ABCD中AD∥BCMN分别是ADBC的中点EF分别是BMCM的中点 1求证四边形MENF是菱形 2 sketch template

已知如图在等腰梯形ABCD中AD∥BCMN分别为ADBC的中点EF分别是BMCM的中点．求证四边形MENF是菱形．题目和 sketch template

中点四边形 知乎 sketch template

如图EFGH分别是四边形ABCD的边ABBCCDDA的中点顺次连接EFGH所得的四边形EFGH显然是平行四边形．1当 sketch template

一组对边相等且一组对角线被平分的四边形是平行四边形吗知乎 sketch template

这道题运用的知识很多，两类三角形的性质和平行四边形的判定知乎 sketch template

图中的三个图形分别是平行四边形等腰三角形和半圆先判断哪些图形是轴对称图形哪些不是再画出轴对称图形的对称轴．——青夏教育精英家教�—— sketch template

4．如图已知四边形ABCD是平行四边形点P是平面 ABCD外的一点则在四棱锥P ABCD中M是PC 的中点在DM上取一点G过G和 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

百度教育 sketch template

如图�们把依次连接任意四边形ABCD各边中点所得四边形EFGH叫中点四边形．1若四边形ABCD是菱形则它的中点四边形EFGH一定是 sketch template

定义到凸四边形一组对边距离相等到另一组对边距离也相等的点叫凸四边形的准内心．如图1PH=PJPI=PG则点P就是四边形ABCD的准 sketch template

如图所有的四边形都是正方形所有三角形都是直角三角形其中最大的正方形的边长是a则图中四个小正方形ABCD的面积之和是 ．题目和 sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

如图在等腰直角三角形ABC中∠ACB=90°AC=BC=4D是AB的中点EF分别是ACBC上的点且AE=CF连接EF并取EF sketch template

如图四边形ABCD是长方形长AD等于7厘米宽AB等于5厘米四边形CDEF是平行四边形．如果BH的长是3厘米那么图中阴影部分面积是多� sketch template

如图四边形ABCD中对角线相交于点OEFGH分别是ABBDBCAC的中点．求证四边形EFGH是平行四边形．题目和参考答案 sketch template

如图正方体ABCD A1B1C1D1的棱长为1P为BC的中点Q为线段CC1上的动点过点APQ的平面截该正方体所得的截面记为S则 sketch template

18．如图四边形ABCD和四边形A′B′C′D′ 位似位似比四边形A′B′C′D′和四边形A″B″C″D″位似位似比．四边形A″B″C sketch template

如图四边形ABCD是平行四边形对角线ACBD交于点O过点O画直线EF分别交ADBC于点EF求证OE＝OF——青夏教育精英家教�—— sketch template

如图小亮用六块形状大小完全相同的等腰梯形拼成一个四边形则图中∠α 的度数是A．60° B．55° C．50° D．45°——青夏教育精英 sketch template

如图不等长的两对角线ACBD相交于O点且将四边形ABCD分成甲乙丙丁四个三角形．若OAOC=OBOD=12则此四个三角形的 sketch template

题目定义有一组对边相等目这一组对边所在直线互相垂直的凸四边形叫做“等垂四边形 ．1如图�四边形与四边形都是正方形求证四边形是 sketch template

如图点EF为线段BD的两个三等分点四边形AECF是菱形．1试判断四边形ABCD的形状并加以证明2若菱形AECF的�长为20 sketch template

如图四边形ABCD的对角线ACBD相交于O且将这个四边形分成��四个三角形．若OAOC=0BOD则下列结论中一定正确的是 sketch template

如图6四边形ABCD中∠A=135°∠B=∠D=90°BC=2AD=2则四边形ABCD的面积是 A4 B4 C4 D sketch template

四边形ABCD中AD∥BC要判别四边形ABCD是平行四边形还需满足条件A∠A ∠C=180°B∠B ∠D=180°C∠A ∠B sketch template

图中平行四边形被分成甲乙丙三个三角形甲的面积比丙多24平方厘米乙的面积与丙的比是35这个平行四边形的面积是 平方厘米．题目和 sketch template

如图ABCD是平行四边形E是BC的中点AF是AE的13三角形ADF 的面积是8cm2三角形ABE的面积是1212cm2．——青夏教育 sketch template

如图已知四边形ABCD中∠B=90°AB=3BC=4CD=12AD=13 求四边形ABCD的面积——青夏教育精英家教�—— sketch template

如图在平行四边形ABCD中被分成甲乙丙三个三角形已知甲比丙多12平方厘米乙与丙的比是34那么平行四边形ABCD的面积是 平方 sketch template

如图所示的图形中 是四边形 是平行四边形．题目和参考答案——青夏教育精英家教�—— sketch template

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