11.下图为某家庭的遗传系谱图正确的判断是 A.Ⅰ1个体的基因型是aaxbxb或aaxbxb b.Ⅰ2个体是白化病基因携带者的概率是12 Template




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tomski11.下图为某家庭的遗传系谱图正确的判断是 a.Ⅰ1个体的基因型是aaxbxb或aaxbxb b.Ⅰ2个体是白化病基因携带者的概率是12 coloring