如图1，在rt abc中，∠acb=90°，ac=bc，点d、e分别在ac、bc边上，dc=ec，连接de、ae、bd，点m、n、p分别是ae Sketch Coloring Page

如图1，在rt abc中，∠acb=90°，ac=bc，点d、e分别在ac、bc边上，dc=ec，连接de、ae、bd，点m、n、p分别是ae Template

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tomski如图1，在rt abc中，∠acb=90°，ac=bc，点d、e分别在ac、bc边上，dc=ec，连接de、ae、bd，点m、n、p分别是ae coloring

如图已知Rt ABC中∠ACB=90°∠B＞∠A在 ABC内找一点E使得 EBC和 ABC相似小聪的做法是取AB边上的中线CD sketch template

如图在Rt ABC中∠ACB=90°DE分别为ABAC边上的中点连接DE将 ADE绕点E旋转180°得到 CFE连接AFAC sketch template

如图1，在Rt ABC中，∠ACB=90°，AC=BC，点D、E分别在AC、BC边上，DC=EC，连接DE、AE、BD，点M、N、P分别是AE sketch template

初二下（八下）数学期末压轴题训练—勾股定理（合集1）知乎 sketch template

如图，在Rt ABC中，∠ C=90°，AC=8，BC=6，点P是AC边上一点，将 ACB沿着过点P的一条直线翻折，使得点A落在边AB上的点Q sketch template

如图在 Rt ABC 中 ∠C = 90 °点 D 大学搜题酱 sketch template

如图在Rt ABC中∠BAC=90°AB=AC分别过点BC坐过点A的直线的垂线BDCE若BD=4CE=3则DE=A1B sketch template

题目如图在 Rt ABC 中∠ACB＝90°．1用直尺和圆规作∠A的平分线交 BC 于点 P保留作图的痕迹不写作法2当 sketch template

如图已知在Rt ABC中∠ACB=90° CD⊥AB于DAD＝pDB＝q则AC2＝ BC2＝ CD2 sketch template

如图1，在Rt ABC中，∠ACB=90°，AC=BC，点D、E分别在AC、BC边上，DC=EC，连接DE、AE、BD，点M、N、P分别是AE sketch template

如图在等腰Rt ABC中∠BAC=90°BC=2点E为线段AB上任意一点以CE为斜边作等腰Rt CDE连接AD下列结论�∠ sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

如图，在Rt ABC中，∠ACB=90°，AC=3，BC=1，将 ABC绕点A逆时针方�旋转90°，得到 AB′C′．连接BB′，交AC于点D sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

百度教育 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径作⊙O交AB于点DE为BC的中点连接DE并延长交AC的延长线于点F．1求证DE sketch template

题目如图在Rt ABC中∠C＝90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于MN的 sketch template

如图在Rt ABC中∠C=90°AC=6∠A的平分线交BC于点DDE⊥AB于点E且BE=4求DE的长．题目和参考答案——青夏 sketch template

题目如图 1在 Rt ABC 中∠ACB＝90°AC＝BCD 是 BC 上的一点过点 D 作 DE⊥AB垂足为点 EF 为 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4以点C为圆心CA为半径的圆与AB交于点D则AD的长为 A． B． C sketch template

题目如图 在Rt ABC中∠ACB＝90°AC＝6BC＝8将边AC沿CE翻折使点A落在AB上的点D处再将边BC沿CF翻折使 sketch template

在Rt ABC中∠ACB等于90°∠ABC等于30°AC=1将 ABC绕点A逆时针旋转至 AB′C′使得点AC′恰好落在斜边AB上 sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

如图．在Rt ABC中．∠ACB=90°．∠ABC=30°AB=6．点D是BC边上一动点连接AD．将 ACD沿AD折叠．点C落在点C1处 sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

如图，在Rt ABC中，∠ACB=90°，M为AB边的中点，将Rt ABC绕点M旋转，使点A与点C重合得到 CED，连接M A 若∠B=26 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠C=90°DE⊥ABAC=BE=15BC=20则四边形ACED的面积为 75 96——青夏教育精英家教�—— sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图在Rt ABC中∠ACB=90°AB的垂直平分线DE交AC于E交BC的延长线于F若∠F=30°DE=1则BE的长是 ．题目 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图Rt ABC中∠ABC=90°BA=BC=2分别过AC作平面ABC的垂线AA′和CC′AA′=h1CC′=h2且h1＞h2 sketch template

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