14．如图rt abc中ac=8bc=6∠c=90°⊙i分别切acbcab于def求rt abc的内心i与外心o之间的距离 Sketch Coloring Page

14．如图rt abc中ac=8bc=6∠c=90°⊙i分别切acbcab于def求rt abc的内心i与外心o之间的距离 Template

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anonymous

anonymous
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anonymous
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anonymous

anonymous
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anonymous

anonymous
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anonymous

anonymous
sketch #4971 Rhianna by Isaiah Fantisy Godlike

sketch #3429 Another try of Miku xD

Chelley
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anonymous
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Saifa Mahmud
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anonymous

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sketch #1855 MAGIC DANCE

anonymous

anonymous
sketch #1855 MAGIC DANCE

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Raisa Mahmud
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anonymous

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sketch #828 Were Fools

anonymous

anonymous
sketch #828 Were Fools

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anonymous

anonymous
sketch #3157 umpa lumpa

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anonymous

anonymous
sketch #3107 Hitman by Miguel Edgardo Montes Cuaresma

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sketch #2715 Angelina

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sketchmaster
sketch #2476 Asuna from SAO by sketchmaster

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anonymous

anonymous
sketch #3499 Alien Laura Gutierrez Hinojosa

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anonymous

anonymous
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tomski14．如图rt abc中ac=8bc=6∠c=90°⊙i分别切acbcab于def求rt abc的内心i与外心o之间的距离 coloring

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

如图，在Rt ABC中，∠ C=90°，AC=8，BC=6，点P是AC边上一点，将 ACB沿着过点P的一条直线翻折，使得点A落在边AB上的点Q sketch template

如图在Rt ABC中∠ACB=90°DE分别为ABAC边上的中点连接DE将 ADE绕点E旋转180°得到 CFE连接AFAC sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图在 ABC中DE分别是边ABAC的中点BC=8则DE=．题目和参考答案——青夏教育精英家教�—— sketch template

如图1，在Rt ABC中，∠ACB=90°，AC=BC，点D、E分别在AC、BC边上，DC=EC，连接DE、AE、BD，点M、N、P分别是AE sketch template

题目如图Rt ABC中∠ACB＝90°AC＝3BC＝4D是AB上一动点过点D作DE⊥AC于点EDF⊥BC于点F连结EF则 sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图在Rt ABC中∠BAC=90°AB=AC分别过点BC坐过点A的直线的垂线BDCE若BD=4CE=3则DE=A1B sketch template

题目如图在Rt ABC中AC=BC∠ACB=90°点D为边AB上一点CD绕点D顺时针旋转90°至DECE交AB于点G．已知AD sketch template

14．如图在 ABC中∠B=90°两直角边AB=5BC=12三角形内有一点P到各边的距离相等求点P到各边的距离——青夏教育精英家教�—— sketch template

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

已知Rt ABC中∠ACB=90°AC=6BC=8 Word文档免费下载文档大全 sketch template

百度教育 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图6在Rt ABC中 ∠C＝90°BD是∠ABC的平分线交AC于D若CD＝4AB＝8则 ABD的面积是 sketch template

河南中考第14题汇总 Word文档在线阅读与下载免费文档 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图Rt ABC中∠ABC=90°BA=BC=2分别过AC作平面ABC的垂线AA′和CC′AA′=h1CC′=h2且h1＞h2 sketch template

如图在Rt ABC中∠ACB=Rt∠AC=2tan2A Tan2B= ∠A>∠B点P在斜边AB上移动连结PC设AP为x sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图所示在等腰Rt ABC中AC=BC以斜边AB为一边作等边 ABD使点CD在AB的同侧再以CD为一边作等边 ECD使点CE在 sketch template

5．如图在Rt ABC中CD是斜边AB上的高则图中的相似三角形共有 3对 D4对提示考�Rt ABC与Rt ACD sketch template

百度教育 sketch template

如图Rt ABC沿直角边BC所在直线�右平移到Rt DEF则下列结论中错误的是ABE=ECBBC=EFCAC=DFD ABC≌ sketch template

如图所示在三角形ABC中∠ABC=45°CD⊥AB与点DBE平分∠ABC 且BE⊥AC于点E与CD相交于点FH是BC边的中点 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图在Rt ABC中∠ABC=90°AB=3AC=5点E在BC上将 ABC沿AE折叠使点B落在AC边上的点B′处则BE的长为 sketch template

如图Rt ABC中∠D=90°∠B=45°∠ACD=60°BC=10cm求AD的长．题目和参考答案——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠C=90°DE⊥ABAC=BE=15BC=20则四边形ACED的面积为 75 96——青夏教育精英家教�—— sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

如图Rt ABC中∠A=60°将 ABC绕点C顺时针旋转得到 A1B1C斜边A1B1与CB相交于点D且DC=AC则旋转角∠ACA1 sketch template

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