如图已知∠b=∠c则∠adc与∠aeb的大小关系是a∠adc＞∠aeb B∠adc＜∠aeb C∠adc=∠aeb D大小关系不 Sketch Coloring Page

如图已知∠b=∠c则∠adc与∠aeb的大小关系是a∠adc＞∠aeb B∠adc＜∠aeb C∠adc=∠aeb D大小关系不 Template

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tomski如图已知∠b=∠c则∠adc与∠aeb的大小关系是a∠adc＞∠aeb b∠adc＜∠aeb c∠adc=∠aeb coloring

如图已知∠B=∠C则∠ADC与∠AEB的大小关系是A∠ADC＞∠AEB B∠ADC＜∠AEB C∠ADC=∠AEB D大小关系不 sketch template

如图已知AB∥CDAD与BC相交于点EEF平分∠BED若∠A=30°∠C=40°则∠DEF的度数为 A．70°B．50°C sketch template

如图点DE分别是ABAC上的点连BECD若∠B＝∠C则∠AEB与∠ADC的大小关系是 A∠ADC＞AEB B∠ADC sketch template

题目如图1将两个完全相同的三角形纸片ABC和A′B′C重合放置其中∠C=90°∠B=∠B′=30°AC=AC′=2．1如图2 sketch template

如图D在AB上E在AC上且∠B=∠C则下列条件中无法判定 ABE≌ ACD的是 A．AD=AEB．AB=ACC．BE=CDD．∠ sketch template

如图ABC是⊙O上的三点且∠BOC=90°则 ∠BAC的大小是A 60° B 45° C 30° D 15°——青夏教育精英 sketch template

如图Rt ABC中∠C=90°AC=6BC=3PQ=AB点P与点Q分别在AC和AC的垂线AD上移动则当AP=3或6时 ABC和 sketch template

如图 ABC与 A′B′C′关于直线l对称则∠B的度数为A．30°B．50°C．90°D．100°——青夏教育精英家教�—— sketch template

如图D是 ABC的BC边上一点∠B=∠BAD ∠ADC=70°∠BAC=60° 求∠C的度数——青夏教育精英家教�—— sketch template

如图所示要说明 ABC≌ BAD1已知∠1=∠2若要以SAS为依据则可添加一个条件是 2已知∠1=∠2若要以AAS为依据 sketch template

8．如图已知AB∥CD∠A=60°∠C =25°则∠E等于 A 60° B 25° C 35° D 45°——青夏教育精英家教�—— sketch template

如图，在四边形ABCD中，AB=AC，∠ ABD=60°，∠ ADB=78°，∠ BDC=24°，则∠ DBC= A18°B20 sketch template

几何模型 “8”字模型知乎 sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4以点C为圆心CA为半径的圆与AB交于点D则AD的长为 A． B． C sketch template

如图点ABC在⊙O上若则∠AOB的度数为A．B．C．D．题目和参考答案——青夏教育精英家教�—— sketch template

$如图已知 ABC与 ADE中则∠C=∠E∠DAB=∠CAE∠D=∠B$frac{AF}{AC}$=$frac{AD}{AB sketch template$

如图3已知AB∥CD∠B=1200∠D=1500则∠O等于 A500 B600 C800 D900——青夏教育精英家教�—— sketch template

如图4ABC是⊙O上的三点∠AOB° 则∠ACB的度数是——青夏教育精英家教�—— sketch template

如图AB是半圆⊙O的直径 ABC的两边ACBC分别交半圆于DE且E为BC的中点已知∠BAC=50°则∠C= A 55 sketch template

如图，已知点A、B、C在同一直线上， ABD和 BCE都是等边三角形．则在下列结论中：�AP=DQ，�EP=EC，�PQ=PB，�∠AOB=∠ sketch template

如图已知∠BDE=∠DEF∠DFE=∠B试说明∠CFD ∠C=180° 解∵∠BDE=∠DEF∴ ∥ ∴∠DFE=∠ADF sketch template

题目如图∠MON=90°点AB分别在OMON上运动不与点O重合． 1如图�BC是∠ABN的平分线BC的反方�延长线与∠ sketch template

如图已知∠1=∠2∠3=∠4∠5=∠A求证BE∥CF．题目和参考答案——青夏教育精英家教�—— sketch template

8．如图已知a∥b∠2=140°则∠1= °——青夏教育精英家教�—— sketch template

8．如图已知a∥b∠2=140°则∠1= °——青夏教育精英家教�—— sketch template

如图6 80 ABC中∠B=55°∠C=63°DE∥AB则∠DEC等于 A63° B62° C55° D118°——青 sketch template

8．如图已知AB∥CD∠A=60°∠C =25°则∠E等于 A 60° B 25° C 35° D 45°——青夏教育精英家教�—— sketch template

如图AB是⊙O的直径C D E都是⊙O上的点则∠1 ∠2 = ——青夏教育精英家教�—— sketch template

如图AB是⊙O的直径CD是圆上的两点不与AB重合已知BC＝1 An∠ADC＝则AB＝．题目和参考答案——青夏教育精英家教�—— sketch template

题目已知∠α的两边分别与∠β的两边垂直且∠α=20°则∠β的度数为 A．20° B．160° C．20°或160° D．70 sketch template

11．如图5⊿ABC≌⊿ADE若∠B=40°∠EAB=80° ∠C=45°则∠EAC= ∠D= ∠DAC= ——青夏教育精英 sketch template

如图在 ABC中∠B=∠CD为BC边上的一点E点在AC边上∠ADE=∠AED若∠BAD=20°则∠CDE= A．10°B sketch template

如图已知O是等边 ABC内的一点∠AOB=110° 将 BOC绕点C按顺时针方�旋转60°得 ADC 连接OD 1当∠BOC sketch template

已知如图AC=AB点DE分别在ABAC上且DCBE交于K点又∠B=∠C．1找出除条件给出以外的相等线段小题的相等线段中 sketch template

如图Rt ABC中∠A=60°将 ABC绕点C顺时针旋转得到 A1B1C斜边A1B1与CB相交于点D且DC=AC则旋转角∠ACA1 sketch template

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