已知如图以rt abc的三边为斜边分别�外作等腰直角三角形．若斜边ab＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— Sketch Coloring Page

已知如图以rt abc的三边为斜边分别�外作等腰直角三角形．若斜边ab＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #5267

anonymous

anonymous
sketch #5267

sketch #4852

anonymous

anonymous
sketch #4852

sketch #2678 Portrait by Jocelyn Alejandra Rantul

Jocelyn Alejandra Rantul
sketch #2678 Portrait by Jocelyn Alejandra Rantul

sketch #1118 easy zombie

anonymous

anonymous
sketch #1118 easy zombie

sketch #937

anonymous

anonymous
sketch #937

sketch #2283 Head in a shoe

anonymous

anonymous
sketch #2283 Head in a shoe

sketch #5149 Daenerys Targaryen by Jorge Valero

anonymous

anonymous
sketch #5149 Daenerys Targaryen by Jorge Valero

sketch #1168

anonymous

anonymous
sketch #1168

sketch #5084 Harry Potter by Enrique L. Manly

anonymous

anonymous
sketch #5084 Harry Potter by Enrique L. Manly

sketch #5135 &#;Hypno Colorfull&#; by Lars Tunebo

anonymous

anonymous
sketch #5135 &#;Hypno Colorfull&#; by Lars Tunebo

sketch #2337

anonymous

anonymous
sketch #2337

sketch #4834 Aayla Secura by Nînâ Yämâhä

anonymous

anonymous
sketch #4834 Aayla Secura by Nînâ Yämâhä

sketch #3298

Hank Henry Armstrong
sketch #3298

sketch #1045

anonymous

anonymous
sketch #1045

sketch #5313 Katy Perry by Monalisa Theresia

anonymous

anonymous
sketch #5313 Katy Perry by Monalisa Theresia

sketch #4984 Zombie by London Waterlilly

anonymous

anonymous
sketch #4984 Zombie by London Waterlilly

sketch #4087 Stewie by Leon Soria Ricardo

anonymous

anonymous
sketch #4087 Stewie by Leon Soria Ricardo

sketch #3734

Goran Djordjevic
sketch #3734

sketch #5346

anonymous

anonymous
sketch #5346

sketch #798

Laura Agapi Asnicar
sketch #798

sketch #4724 Turtwig by Mark Robson

anonymous

anonymous
sketch #4724 Turtwig by Mark Robson

sketch #3617 D from Gorillaz by Joselyne Angel Gormaz

anonymous

anonymous
sketch #3617 D from Gorillaz by Joselyne Angel Gormaz

sketch #3643

anonymous

anonymous
sketch #3643

sketch #2772 Merry Christmas from Victor Montecinos Jose Rondon

Jose Rondon
sketch #2772 Merry Christmas from Victor Montecinos Jose Rondon

sketch #5268 Harley Quinn by 조바다

anonymous

anonymous
sketch #5268 Harley Quinn by 조바다

sketch #2625 Dragon by sketchmaster

sketchmaster
sketch #2625 Dragon by sketchmaster

sketch #4012 Owl sketch

anonymous

anonymous
sketch #4012 Owl sketch

sketch #1219

anonymous

anonymous
sketch #1219

sketch #3174 John Snow Helga Fon Stein

anonymous

anonymous
sketch #3174 John Snow Helga Fon Stein

sketch #4191

anonymous

anonymous
sketch #4191

tomski已知如图以rt abc的三边为斜边分别�外作等腰直角三角形．若斜边ab＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— coloring

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— sketch template

已知如图以Rt ABC的三边为斜边分别�外作等腰直角三角形．若斜边AB＝3则图中阴影部分的面积为 ．——青夏教育精英家教�—— sketch template

如图，已知以 ABC的边AB、AC分别�外作等腰Rt ABD与等腰Rt ACE，其中∠BAD=∠CAE=90°，连接BE、CD，BE和CD相交 sketch template

已知如图�Rt ABC中∠ACB=90°AC=BC点DE在斜边AB上且∠DCE=45°AB=4．1在图中找出两对相似三角形 sketch template

如图已知Rt ABC中∠ACB=90°∠B＞∠A在 ABC内找一点E使得 EBC和 ABC相似小聪的做法是取AB边上的中线CD sketch template

21． 已知如图Rt ABC≌Rt ADE∠ABC＝∠ADE=900试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段 sketch template

百度教育 sketch template

如图已知以 ABC的三边为边在BC的同侧分别作等边三角形ABDBCE和ACF．1求证四边形ADEF是平行四边形2 ABC满足 sketch template

如图已知Rt ABC中∠B=90°tanC=05AB=1在 ABC内有一系列正方形求所有这些正方形面积之和题目和参考答案 sketch template

如图，Rt ABC中，∠ACB=90°，AC=BC，点D为AB边上的一个动点（不与点A，B及AB中点重合），连接CD，点A关于直线CD的对称点 sketch template

已知如图在Rt ABC中∠ACB=90°∠B=60°CD⊥AB．求证AB=4DB．题目和参考答案——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠ACB=90°CD⊥AB于D设AC=bBC=aCD=hAB=c下面有3个�题11a2 1b2 sketch template

图� 图� 1 已知如图�Rt ABC中∠ACB=90°AC=BC——青夏教育精英家教�—— sketch template

如图Rt ABC中已知∠C=90°∠B=48°点D在边BC上BD=2CD把Rt ABC绕点D逆时针旋转m度后如果点B恰好落在初始 sketch template

如图在Rt ABC中∠A=90°AB=6AC=8点MN分别为ABAC边的中点点D为BC边的中点动点P从点A出�沿射线AB sketch template

如图，在Rt ABC中，∠ACB=90°，M为AB边的中点，将Rt ABC绕点M旋转，使点A与点C重合得到 CED，连接M A 若∠B=26 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图所示已知Rt ABC中AH为斜边BC上的高M为BC中点O为 ABC外心OB交AH于D．求证AD=2DH．题目和参考答案——青 sketch template

题目已知如图在Rt ABC和Rt ACD中AC=BC∠ACB=90°∠ADC=90°CD=2点AB分别在直线CD的左右 sketch template

25．如图Rt AB ¢C ¢ 是由Rt ABC绕点A顺时针旋转得到的连结CC 交斜边于点ECC 的延长线交BB 于点F sketch template

如图以AD为直径的半圆O经过Rt ABC的斜边AB的两个端点交直角边AC于点E．BE是半圆弧的三等分点弧BE的长为则图中阴影部分的 sketch template

如图在Rt ABC中∠C=90°D为AC上一点且DA=DB=5又 DAB的面积为10那么DC的长是 A4 B3 C5 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示则不难证明S1=S2 S3．1如图�分别以直角 sketch template

如图分别以ABAC为边� ABC形外作正方形ABDE 正方形ACGFMN PQ分别是EFBCEBFC的中点 1猜想 sketch template

如图在Rt ABC中∠B=90°AB=6cmBC=12cm点P从点A出�沿AB边�点B以1cm/s的速度移动同时点Q从点B出�沿 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

已知如图Rt ABC≌Rt ADE∠ABC＝∠ADE=90°试以图中标有字母的点为端点连结两条线段如果你所连结的两条线段满足相等 sketch template

如图以Rt ABC的直角边AC和斜边AB为边分别作Rt ADC和正方形ABEF再以AD作正方形ADGH．已知∠ACB=90°正方形 sketch template

已知如图在Rt ABC中∠ACB＝900AD平分∠CAB交BC于点D过点C作CE⊥AD垂足为ECE的延长线交AB于点F过点E作 sketch template

如图分别以Rt ABC三边为边�外作三个正方形其面积分别用S1S2S3表示容易得出S1S2S3之间有的关系式．题目和参考答案 sketch template

如图在Rt ABC中∠ACB=90°AB=5BC=3过点C作CD⊥AB取AC的中点E连接DE则 DEC的�长是 A．2 sketch template

如图M为Rt ABC斜边BC的中点PQ分别在边ABBC上且BP=5CQ=3PM⊥QM则PQ= ．题目和参考答案——青夏教育 sketch template

如图已知Rt ABC≌Rt DEF∠C=∠F=90°AC=DF=3BC=EF=4 DEF绕着斜边AB的中点D旋转DEDF分别交 sketch template

如图�分别以直角三角形ABC三边为直径�外作三个半圆其面积分别用S1S2S3表示 1 如图�分别以直角三角形ABC三边为 sketch template

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