如图，已知六棱锥的底面是正六边形，则下列结论正确的是 A． B． C．直线∥ d．直线所成的角为45°——青夏教育精英家教�—— Sketch Coloring Page

如图，已知六棱锥的底面是正六边形，则下列结论正确的是 A． B． C．直线∥ d．直线所成的角为45°——青夏教育精英家教�—— Template

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tomski如图，已知六棱锥的底面是正六边形，则下列结论正确的是 a． b． coloring

已知六棱锥P ABCDEF其中底面ABCDEF是正六边形点P在底面的投影是正六边形的中心底面边长为2cm侧棱长为3cm求六棱锥P sketch template

正六棱锥图片直观图正六棱锥直观图正六棱锥直观图怎么画第4页大山谷图库 sketch template

有一个正六棱锥底面为正六边形侧面为全等的等腰三角形的棱锥底面边长为3cm高为3cm画出这个正六棱锥的直观图．题目和参考答案——青 sketch template

如图，已知六棱锥的底面是正六边形，则下列结论正确的是 A． B． C．直线∥ D．直线所成的角为45°——青夏教育精英家教�—— sketch template

高中数学第一册上棱锥 Word文档在线阅读与下载无忧文档 sketch template

六棱锥立体图 千图� sketch template

已知正六棱锥底面边长为4高为3求它的侧棱长．题目和参考答案——青夏教育精英家教�—— sketch template

已知正三棱锥P－ABC的底面边长为6，其内切球的半径为1，则此三棱锥的高为． sketch template

六棱锥素描步骤解析教程普画� sketch template

如图所示，四棱锥的底面是正方形，每条侧棱的长都是底 高途 sketch template

深入浅出数学系列立体几何（4）：球的切接问题（上）知乎 sketch template

6．四棱锥P ABCD的底面为正方形PD底面ABCDPD＝AD＝1设点C到平面PAB 的距离为点B到平面PAC的距离为则 A sketch template

如图正四棱锥S ABCD 的底面是边长为a正方形O为底面对角线交点侧棱长是底面边长的2倍P为侧棱SD上的点．Ⅰ求证AC⊥SD sketch template

如图所示，四棱锥的底面是正方形，每条侧棱的长都是底 高途 sketch template

如图所示四棱锥P ABCD中底面ABCD是正方形PA⊥底面ABCDPA=AB=2点F是PB的中点点E在棱BC上移动．1当E为 sketch template

81 基本立体图形1 棱柱、棱锥、棱台湛江贵哥讲数学博客园 sketch template

如图已知四棱锥的底面是边长为4的正方形在底面上的射影落在正方形内的长为到的距离分别为和是的中点． Ⅰ求证平面底面 Ⅱ设 sketch template

如图所示四棱锥P ABCD的底面ABCD是边长为a的正方形侧棱PA=a PB=PD=a则它的5个面中互相垂直的面有对——青夏教育 sketch template

已知三棱锥P ABC中顶点P在底面的射影O是三角形ABC的内心关于这个三棱锥有三个�题�侧棱PA=PB=PC�侧棱PAPBPC两两 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图，在四棱锥P ABCD中，侧面PAD⊥ 底面ABCD，侧棱PA=PD=√2，底面ABCD为直角梯形，其中BC//AD，AB⊥ AD，AD sketch template

81 基本立体图形1 棱柱、棱锥、棱台湛江贵哥讲数学博客园 sketch template

如图已知四棱锥S ABCD的侧面SCD⊥底面ABCDBC∥ADBC⊥SC且SC=SD=CD=BC=2AD =2P为SB的中点求 sketch template

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA=PD=AD=2EF分别为PCBD的中点．Ⅰ sketch template

如图已知六棱锥的底面是正六边形平面 则下列结论正确的是 直线∥平面平面平面直线与平面所成的角为——青夏教育精英家教�—— sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图所示四棱锥P ABCD中底面ABCD是正方形PA⊥底面ABCDPA=AB=2点F是PB的中点点E在棱BC上移动．1当E为 sketch template

如图在底面是菱形的四棱锥 P ABCD中∠ABC=60°PA⊥平面ABCD点EFG分别为CDPDPB的中点．PA=AD=2 sketch template

如图，在底面是菱形的四棱锥P ABCD中，∠ABC=60°，PA=AC=1，PB=PD= 2 ，点E在PD上，且百度教育 sketch template

如图，在四棱锥P ABCD中，底面ABCD是平行四边形，∠BCD=120°，侧面PAB⊥底面ABCD，PB=2√6，AB=AC=PA=2√3 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

已知正三棱柱ABC A1B1C1的底面边长为2高为4过BC作一截面截面与底面ABC成600角则截面面积是 A．4 B． C． D sketch template

四棱锥P ABCD的底面是边长为3的正方形PD⊥平面ABCD．异面直线AD与PB所成角为60°E为线段PC上一点PE=2EC．求二面角P sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

已知四棱锥P ABCD它的底面是边长为a的菱形且∠ABC＝120°PC⊥平面ABCD又PC＝aE为PA的中点． 1求证平面 sketch template

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