如图点e在bc的延长线上下列四个条件中不能判定ab∥cd的是 A∠1＝∠2 b∠b＝∠dce C∠3＝∠4 D∠d ∠dab Sketch Coloring Page

如图点e在bc的延长线上下列四个条件中不能判定ab∥cd的是 A∠1＝∠2 b∠b＝∠dce C∠3＝∠4 D∠d ∠dab Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #1221 səhər
abbasova
gözəi
qız
hamı
məni çox
seve
anam da
çox
sevir

anonymous

anonymous
sketch #1221 səhər abbasova gözəi qız hamı məni çox seve anam da çox sevir

sketch #5361 Emma Watson by Glynis June Williams

anonymous

anonymous
sketch #5361 Emma Watson by Glynis June Williams

sketch #5058

anonymous

anonymous
sketch #5058

sketch #5163

anonymous

anonymous
sketch #5163

sketch #5228 Rin & Len by Mark Phillips

anonymous

anonymous
sketch #5228 Rin & Len by Mark Phillips

sketch #4209 bushy

anonymous

anonymous
sketch #4209 bushy

sketch #3298

Hank Henry Armstrong
sketch #3298

sketch #817

Laura Agapi Asnicar
sketch #817

sketch #5130 Batman by Kamal Ahmed Tantawy

anonymous

anonymous
sketch #5130 Batman by Kamal Ahmed Tantawy

sketch #3285 Spongebob by Abbie Hayman

anonymous

anonymous
sketch #3285 Spongebob by Abbie Hayman

sketch #1846 zay

anonymous

anonymous
sketch #1846 zay

sketch #5351

anonymous

anonymous
sketch #5351

sketch #1972 Boogaloo @Memphis

anonymous

anonymous
sketch #1972 Boogaloo @Memphis

sketch #645

Tom Kelly
sketch #645

sketch #5215

anonymous

anonymous
sketch #5215

sketch #5284

anonymous

anonymous
sketch #5284

sketch #2910 Harley Quinn Germaine Hoens

anonymous

anonymous
sketch #2910 Harley Quinn Germaine Hoens

sketch #1216

anonymous

anonymous
sketch #1216

sketch #3360

anonymous

anonymous
sketch #3360

sketch #5052 Gorillaz by Rafał Dawid

anonymous

anonymous
sketch #5052 Gorillaz by Rafał Dawid

sketch #687 Buddha Peace

anonymous

anonymous
sketch #687 Buddha Peace

sketch #5272

anonymous

anonymous
sketch #5272

sketch #119

Johnny B. Goode
sketch #119

sketch #5112

anonymous

anonymous
sketch #5112

sketch #3149 Dude with a sword by Elio Hernandez

anonymous

anonymous
sketch #3149 Dude with a sword by Elio Hernandez

sketch #5054 Angelina Jolie by Hailey So Pretty

anonymous

anonymous
sketch #5054 Angelina Jolie by Hailey So Pretty

sketch #2672

Fabio Sala
sketch #2672

sketch #5202 The Woman by Céline Chalois

anonymous

anonymous
sketch #5202 The Woman by Céline Chalois

sketch #3247 Thor by Juvenilia Alexandrino

anonymous

anonymous
sketch #3247 Thor by Juvenilia Alexandrino

sketch #1463

Laura Agapi Asnicar
sketch #1463

tomski如图点e在bc的延长线上下列四个条件中不能判定ab∥cd的是 a∠1＝∠2 b∠b＝∠dce coloring

如图点E在BC的延长线上下列四个条件中不能判定AB∥CD的是 A∠1＝∠2 B∠B＝∠DCE C∠3＝∠4 D∠D ∠DAB sketch template

如图点E在BC的延长线上下列四个条件中不能判定AB∥CD的是 A∠1＝∠2 B∠B＝∠DCE C∠3＝∠4 D∠D ∠DAB sketch template

题目如图在 ABC中AC=BC∠ACB=90°AD平分∠BAC与BC相交于点F过点B作BE⊥AD于点D交AC延长线于点E过 sketch template

如图已知在 ABC中AD是BC边上的中线E是AD上一点且BE=AC延长BE交AC于点F。求证AF=EF。百度教育 sketch template

如图所示，在a、b两点固定着两个带等量异种电荷的点电荷，c、d两点将a、b两点的连线三等分，e、f是a、b两点连线的中垂线上的两点，且e、f到 sketch template

如图1已知在等边 ABC中当点D在BC边上点E在AC边上且BD=CE连接ADBE交于点F．等边三角形3条边相等每个角都是60 sketch template

如图点P是正方形ABCD的对角线BD上一点PE⊥BCPF⊥CD垂足分别为点EF连接APEF给出下列四个结论�AP=EF�∠ sketch template

题目如图Rt ACB中∠ACB=90° ABC的角平分线ADBE相交于点P过P作PF⊥AD交BC的延长线于点F交AC于点H则 sketch template

如图在平面直角坐标系中抛物线y=ax2 Bx C与x轴交于点A与y轴交于点C顶点为D对称轴为直线x=1有下列四个判断�关于x的一 sketch template

百度教育 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图ABC三点在同一直线上1用上述字母表示的不同线段共有条2用上述字母表示的不同射线共有条——青夏教育精英家教�—— sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

题目如图正方形ABCD中AB=6点E在边AB上且BE=2AE．将 ADE沿ED对折至 FDE延长EF交边BC于点G连结DG sketch template

如图等腰Rt ABC中AC=BC以AC为直径作⊙O交AB于D点E为CD上的一个动点过E作AE的垂线交BC的延长线于点F连接AE sketch template

题目如图点AOB在同一直线上射线OD和射线OE分别平分∠AOC和∠BOC1当∠BOE=25°时求∠AOD的度数2在图中 sketch template

如图点EF分别在平行四边形ABCD的边ABCD的延长线上点EF的连线交对角线AC于点O．试问线段BEDF满足什么条件时四边形 sketch template

如图在 ABC中∠ABC和∠ACB的平分线相交于点O过点O作EF∥BC交AB与E交AC于F过点O作OD⊥AC于D下列四个结论其中 sketch template

如图四边形ABCD中点E在边CD上连结AEBE给出下列五个关系式�AD∥BC�DE＝CE�∠1＝∠2�∠3＝∠4�AD sketch template

如图DE分别为 ABC的边ABAC上的点BE与CD相交于O点现有四个条件�AB＝AC�OB＝OC�∠ABE＝∠ACD sketch template

如图：在三角形ABC中，若AC CD=AB，∠ ADC=70^° ，∠ ACB=80^° ，求∠ B？百度教育 sketch template

如图在 ABC中AD是∠BAC的平分线AD的垂直平分线交AB于点E交AC于点G交BC的延长线于点F连接AFDE下列结论� sketch template

如图边长为2L的等边三角形区域abc内部的匀强磁场垂直纸面�里b点处于x轴的坐标原点O一与三角形区域abc等高的直角闭合�属线框ABC sketch template

24．12分如图所示，绝缘光�轨道ABCD竖直放在与水平方�成θ＝45°的匀强电场中，其中BCD部分是半径为R的半圆环，轨道的水平部分与 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图D是半径为R的⊙O上一点过点D作⊙O的切线交直径AB的延长线于点C下列四个条件�AD=CD�∠A=30°�∠ADC=120 sketch template

如图所示已知DE平行BCEF平分角AED角1=角2角1=3x 20°，角ACB=（40x 20）°，求角ACB的度数百度知道 sketch template

如图AB是的直径交BC的中点于D于E连接�DE是的切线则下列结论正确的个数是A．1个 B．2个 C．3个 D．4个——青夏 sketch template

如图为圆O的直径在圆O上取异于AB的一点C并连接．若想在上取一点P使得P与直线BC的距离等于长判断下列四个作法何者正确 A sketch template

如图在 ABC中∠BAC和∠ABC的平分线相交于点O过点O作EF∥AB交BC于F交AC于E过点O作OD⊥BC于D下列四个结论�∠ sketch template

在三角形ABC中∠B＝60°BA＝24cmBC＝16cm现有动点P从点A出�沿射线AB�点B方�运动动点Q从点C出�沿射线CB sketch template

如图 ABC≌ ADE∠E=∠DAB找出图中平行的两条线段并说明理由．题目和参考答案——青夏教育精英家教�—— sketch template

如图在 ABC中AB＝AC点DEF分别在ABBCAC边上且BE＝CFBD＝CE．1求证 DEF 是等腰三角形2当 sketch template

如图在 ABC中∠ABC和∠ACB的平分线相交于点O过点O作EF∥BC交AB与E交AC于F过点O作OD⊥AC于D下列四个结论其中 sketch template

如图在 ABC中点DEF分别在ACABBC边上且四边形CDEF是正方形AC=3BC=2求 ADE EFB ACB的�长 sketch template

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