如图所示已知 Abc和 Dce都是等边三角形图中的三角形可以通过旋转相互得到的是a Ace和 Bcdb Abf和 Cfdc Abc Sketch Coloring Page

如图所示已知 Abc和 Dce都是等边三角形图中的三角形可以通过旋转相互得到的是a Ace和 Bcdb Abf和 Cfdc Abc Template

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sketch #4269 dragón

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sketch #5165 Marceline by Marvin Chrome

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sketch #5049

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sketch #3429 Another try of Miku xD

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sketch #3667

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sketch #2087 zay lin

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sketch #933 mts

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sketch #4405 Cat by Nizamuddin Shuja

anonymous

anonymous
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sketch #4918 Mike Wazowsky by George Andres Crowther Castillo

anonymous

anonymous
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tomski如图所示已知 abc和 dce都是等边三角形图中的三角形可以通过旋转相互得到的是a coloring

如图所示已知 ABC和 DCE都是等边三角形图中的三角形可以通过旋转相互得到的是A ACE和 BCDB ABF和 CFDC ABC sketch template

10．如图所示已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点OAE与CD交于点GAC与BD交于点F sketch template

如图所示已知 ABC和 DCE都是等边三角形图中的三角形可以通过旋转相互得到的是A ACE和 BCDB ABF和 CFDC ABC sketch template

如图， ABC是等边三角形，D是BC边上一点，且满足∠ADE=60∘，DE交等边三角形ABC的外角平分线CE所在直线于点E，试探究AD与DE的 sketch template

如图已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点O与CD交于点GAC与BD交于点F连接OC．求证 sketch template

10．如图所示已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点OAE与CD交于点GAC与BD交于点F sketch template

如图，已知 ABC是等边三角形，延长BA至E，延长BC至D，使AE=BD，求证：EC=ED．百度教育 sketch template

如图所示在等边 ABC中点DE分别在边BCAB上且BD=AEAD与CE交于点F则∠DFC的度数为 A．60°B．45°C sketch template

6．如图已知ΔABC和ΔABD都是⊙O的内接三角形AC和BD相交于点E则与ΔADE相似的三角形是 A．ΔBCE B．ΔABC C sketch template

如图．已知点BCD在同一条直线上． ABC和 CDE都是等边三角形BE交AC于FAD交CE于H1求证 BCE≌ ACD2 sketch template

已知如图 ABC和 ADE都是等边三角形图中哪个三角形与 ABD全等证明你的结论——青夏教育精英家教�—— sketch template

如图所示已知等边三角形ABC的边长为1按图中所示的规律用2011个这样的等边三角形镶嵌而成的四边形的�长是 ．题目和参考答案——青夏 sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

已知如图 ABC内接于O AB=ACAO⊥BC于D 1求证 ABC是等边三角形 2若AB＝1P是劣弧BC上的一个动点 sketch template

如图 ABC和 DBE均为等边三角形已知AB=6BD=23现把 DBE绕点B逆时针旋转所得三角形记为 D′BE′连接AE′当∠ sketch template

如图， ABC和 DEF是两个全等的等腰直角三角形，∠ BAC=∠ EDF=90°， DEF的顶点E与 ABC的斜边BC的中点重合，将 DEF sketch template

百度教育 sketch template

已知如图延长 ABC的各边使得BF=ACAE=CD=AB顺次连接DEF得到 DEF为等边三角形．求证 1 AEF≌ sketch template

三角形名称图片三角形的名称和三角形分类及图片大山谷图库 sketch template

百度教育 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

15．如图所示已知等腰直角三角形ABC中∠ACB=90°直线L经过点C AD ⊥LBE⊥L垂足分别为DE． 1证明 ACD sketch template

如图在等边 ABC的边BC上任取一点D作∠ADE=60°DE交∠C的外角平分线于E则 ADE是 三角形．题目和参考答案——青夏教育 sketch template

如图所示已知边长为3的等边 ABC点F在边BC上CF=1点E是射线BA上一动点以线段EF为边�右侧作等边 EFG直线EGFG交 sketch template

如图所示已知AE为⊙O的直径AD为 ABC的BC边上的高求证AD·AE=AB·AC——青夏教育精英家教�—— sketch template

1如图�所示已知C是线段AB上一点分别以ACBC为边长在AB的同侧作等边 ADC和 CBE连接AE和DB证明AE=DB2 sketch template

已知A点坐标为且 ABC为等边三角形．1求C点坐标2求 ABC的�长和面积．题目和参考答案——青夏教育精英家教�—— sketch template

如图所示已知点D在 ABC的边AB上连结CD∠1=∠BAD=4AC=5 求 BD的长——青夏教育精英家教�—— sketch template

如图所示已知 ABC的�长是21OBOC分别平分∠ABC和∠ACBOD⊥BC于D且OD=3则 ABC的面积是多� 题目和参考答案 sketch template

如图所示已知 ABC和 BDE都是等边三角形且ABD三点共线．下列结论�AE=CD�BF=BG�HB平分∠AHD�∠AHC sketch template

如图所示等边三角形ABC边长为L在顶点AB处有等量同种点电荷QAQBQA=QB= Q求在顶点C处的正点电荷QC所受的静电力 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图所示已知DE分别是 ABC的边BCAB上的点ADCE交FBFDE交于G过G作BC的平行线MN交ABCEAC于MH sketch template

如图所示，分别以 ABC的边AB、AC为边，�三角形的外侧作正方形ABDE和正方形ACFG，点M为BC中点，1求证：AM⊥EG．2求证 sketch template

如图所示已知在 ABC中∠BAC＝70°AC=6AD是 ABC的角平分线则∠BAD= BE是 ABC的中线则AE=CE= CF sketch template

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