如图∠bca=90°pc⊥面abc则在三角形abc三角形pac的边所在的直线中 1与pc垂直的直线有acabbc 2与 Sketch Coloring Page

如图∠bca=90°pc⊥面abc则在三角形abc三角形pac的边所在的直线中 1与pc垂直的直线有acabbc 2与 Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #3385

anonymous

anonymous
sketch #3385

sketch #5438

anonymous

anonymous
sketch #5438

sketch #4632

anonymous

anonymous
sketch #4632

sketch #4755

anonymous

anonymous
sketch #4755

sketch #2616 Green Day by sketchmaster

sketchmaster
sketch #2616 Green Day by sketchmaster

sketch #4766 The Little Mermaid by Zizou Aiman

anonymous

anonymous
sketch #4766 The Little Mermaid by Zizou Aiman

sketch #1255 something

anonymous

anonymous
sketch #1255 something

sketch #4475 Daft Punk by Reggie Garcia

anonymous

anonymous
sketch #4475 Daft Punk by Reggie Garcia

sketch #5306 Katarina by Mirnes Sinanovic

anonymous

anonymous
sketch #5306 Katarina by Mirnes Sinanovic

sketch #2309

anonymous

anonymous
sketch #2309

sketch #5269

anonymous

anonymous
sketch #5269

sketch #126

Chris Shrimp Lonsdale
sketch #126

sketch #3174 John Snow Helga Fon Stein

anonymous

anonymous
sketch #3174 John Snow Helga Fon Stein

sketch #2892 Joker by Frank Aguiar Au

anonymous

anonymous
sketch #2892 Joker by Frank Aguiar Au

sketch #4549

anonymous

anonymous
sketch #4549

sketch #1545

anonymous

anonymous
sketch #1545

sketch #4471 Brother Bear by Samuel Roberto

anonymous

anonymous
sketch #4471 Brother Bear by Samuel Roberto

sketch #3604 Falling Manipati Surya

anonymous

anonymous
sketch #3604 Falling Manipati Surya

sketch #5020 Stitch by Hina Ali

anonymous

anonymous
sketch #5020 Stitch by Hina Ali

sketch #4974 Eminem by Juan Garcia

anonymous

anonymous
sketch #4974 Eminem by Juan Garcia

sketch #5207 Gorilla by Jean-Benoit Renaud

anonymous

anonymous
sketch #5207 Gorilla by Jean-Benoit Renaud

sketch #1041 strawberries

anonymous

anonymous
sketch #1041 strawberries

sketch #4264 oh yeah

anonymous

anonymous
sketch #4264 oh yeah

sketch #2881 Mickey Mouse by Michael Angcay

anonymous

anonymous
sketch #2881 Mickey Mouse by Michael Angcay

sketch #5011

anonymous

anonymous
sketch #5011

sketch #5159 Frank Briones Silvia Haynes

anonymous

anonymous
sketch #5159 Frank Briones Silvia Haynes

sketch #1503 L 'Algérie

AbdouGt Zizou
sketch #1503 L 'Algérie

sketch #1043 Deadoo..

Cherie N Patanao
sketch #1043 Deadoo..

sketch #3815

Emin AltınKöprü
sketch #3815

sketch #1034 what ever you want it to be

anonymous

anonymous
sketch #1034 what ever you want it to be

tomski如图∠bca=90°pc⊥面abc则在三角形abc三角形pac的边所在的直线中 1与pc垂直的直线有acabbc 2与 coloring

如图∠BCA=90°PC⊥面ABC则在三角形ABC三角形PAC的边所在的直线中 1与PC垂直的直线有ACABBC 2与 sketch template

如图∠BCA=90°PC⊥面ABC则在三角形ABC三角形PAC的边所在的直线中 1与PC垂直的直线有ACABBC 2与 sketch template

如图在四边形ABCD中∠ABC=∠ADC=90°AB=BC=10AD=2DC连对角线ACBD相交于点E1�求证BD平分∠ sketch template

如图在四棱锥P ABCD中底面ABCD为直角梯形AD∥BC∠ADC=90°平面PAD⊥底面ABCDQ为AD的中点PA=PD=2 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图，D为圆锥的顶点，O是圆锥底面的圆心，AE为底面直径，AE=AD． ABC是底面的内接正三角形，P为DO上一点，PO=√6/6DO sketch template

如图所示在四棱锥S―ABCD中SA⊥底面ABCD∠BAD=∠ABC= 90°SA=AB=AD=BC=1E为SD中点． 1若F为底 sketch template

在 ABC和 DEC中，AC=BC，DC=EC，∠ACB=∠ECD=90°（1）如图1，当点A、C、D在同一条直线上时，求证：AF⊥BD sketch template

已知斜三棱柱ABC A1B1C1∠BCA=90°AC=BC=2A1在底面ABC上的射影恰为AC的中点D又知BA1⊥AC1．1求证 sketch template

如图，在三棱锥S－ABC中，∠SAB＝∠SAC＝∠ABC＝90°，SA＝AB，SB＝BC （Ⅰ）证明：平面SBC⊥平面SAB；（Ⅱ）求百度教育 sketch template

$如图四棱锥P ABCD中侧面PAD为等边三角形且垂直于底面ABCDAB=BC=$frac{1}{2}$AD∠BAD=∠ABC=90 sketch template$

18．如图所示在四棱锥P ABCD中底面ABCD是一直角梯形∠BAD=90° AD∥BC AB = BC A AD 2a sketch template

18． 如图在三棱锥P ABC中AB⊥BCAB＝BC＝kPA点OD分别是ACPC的中点OP⊥底面ABC． Ⅰ求证OD∥平面 sketch template

如图，在三棱锥P ABC中，平面PAC⊥ 平面ABC，∠ PCA=90°， ABC是边长为4的正三角形，PC=3，M是AB边上的一动点，则PM sketch template

如图在三棱锥PABC中AC = BC 2∠ACB 90°AP BP ABPC⊥AC． 1 求证PC⊥AB sketch template

如图在Rt ABC中∠C=90°点D在边BC上过点D作DE⊥AD交AB于点E且DE=BE．1求证 ABC∽ DAC 2若 sketch template

如图三棱锥P ABC中PB⊥底面ABC∠BCA=90°PB=BC=CA=4E为PC的中点M为AB的中点点F在PA上且AF sketch template

18．如图已知斜三棱柱ABC A1B1C1中∠BCA=90°AC=BC=a点A1在底面ABC上的射影恰为AC的中点DBA1⊥AC1 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数知乎 sketch template

18．如图已知斜三棱柱ABC A1B1C1中∠BCA=90°AC=BC=a点A1在底面ABC上的射影恰为AC的中点DBA1⊥AC1 sketch template

如图在三棱锥P ABC中面PAC⊥面ABCAB⊥BCAB=BC=PA=PC=2MN为线段PC上的点若MN=$sqrt{2 sketch template

如图在三棱柱ABC A1B1C1中∠BAC=90°AB=AC=2AA1=4A1在底面ABC的射影为BC的中点ED是B1C1的中点 sketch template

如图在 ABC中∠C=90°AC=BCAD是角平分线DE⊥AB．垂足为E．求证BE=DE=CD．题目和参考答案——青夏教育精英家教�—— sketch template

三棱锥P ABC中∠ABC=90°PA=PB=PC则下列说法正确的是 A平面PAC⊥平面ABCB平面PAB⊥平面PBCCPB⊥ sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=221求证平面ABC⊥平面APC2求直线PA与平面PBC所成 sketch template

如图在扇形OAB中∠AOB=90°点C是AB上的一个动点OD⊥BCOE⊥AC垂足分别为DE．若DE=1则扇形OAB的面积为 sketch template

如图在四面体ABCD中AB⊥面BCD面ABC⊥面ACD且∠ACB=∠CBD=45°1求证BC⊥CD2求直线AC与平面 sketch template

$如图已知在Rt ABC中∠ACB=90°AB=5sinA=$frac{4}{5}$点P是边BC上的一点PE⊥AB垂足为E以点 sketch template$

如图所示在直角三角形ABC中∠BAC=90°AD⊥BCBE平分∠ABC交AD于EEF∥AC则下列结论不一定成立的是 A．∠1 sketch template

如图在等腰直角三角形中∠BAC=90°AB=AC点D是AC上一点过点A作AF⊥BD过点C作CE⊥AC的延长线于E说明AE=BD sketch template

如图已知 ABC中∠C=90°点E在边AB上请过点E作一条直线与 ABC的其他边相交于一点D使得以点AED为顶点的三角形与 sketch template

如图Rt ABC中∠ACB=90°．1分别以ABAC为边�外作等边三角形ABD和等边三角形ACE连接CE交AB于点F若∠BAC sketch template

吉林省长春外国语学校七年级数学下册 911 认识三角形学案 Word文档在线阅读与下载无忧文档 sketch template

探究1如图1在ABC与ADE中AB=ACAD=AE∠BAC=∠DAE=90°连结BDCE．请写出图1中所有全等的三角形 sketch template

如图在 ABC中AC=BC∠C=90°AD是 ABC的角平分线DE⊥AB垂足为E．1若CD=5求AC的长．2求证AB sketch template

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