如图11－17所示，一简谐振动的旋转矢量图振幅矢量长2cm则该简谐振动的初相为 振动方程上学吧找答案 Sketch Coloring Page

如图11－17所示，一简谐振动的旋转矢量图振幅矢量长2cm则该简谐振动的初相为 振动方程上学吧找答案 Template

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tomski如图11－17所示，一简谐振动的旋转矢量图振幅矢量长2cm则该简谐振动的初相为 振动方程上学吧找答案 coloring

如图11－17所示，一简谐振动的旋转矢量图振幅矢量长2cm则该简谐振动的初相为 振动方程 上学吧找答案 sketch template

振动力学学习笔记绪论三 简谐振动及其三角函数、矢量、复数表示法知乎 sketch template

如图所示是某绳波形成过程的示意图质点1在外力作用下垂直直线方�做简谐运动带动234 各个质点依次上下振动把振动从绳的左端传到右端 sketch template

一列简谐横波某时刻的波形图如图甲所示 由该时刻开始计时质点a的振动图像如图乙所示。下列说法正确的是（）出卷� sketch template

高中物理《波的图像和振动图像及应用》知乎 sketch template

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3．20．一列简谐横波在某一时刻的波形图如图1所示图中PQ两质点的横坐标分别为x=15m和x=45mP点的振动图像如图2所示 在 sketch template

如图所示为一单�及其振动图象由图回答单�的振动�率为 Hz一�期内位移最大的时刻为 和．若�球从E指�G为正方�θ为最大�角则 sketch template

【笔记�大学普通物理：旋转矢量法知乎 sketch template

百度教育 sketch template

13．如图所示沿x轴正方�传播的一列简谐横波在某时刻的波形图为一正弦曲线其波速为200m/s下列说法中正确的是 A图示时刻质点b的 sketch template

11．如图所示实线和虚线分别是x轴上传播的一列简谐横波在t=0和t=0．03s时刻的波形图x=1．2m处的质点在t=0．03s时刻�y轴正 sketch template

一简谐振动用余弦函数表示其振动曲线如图11－16所示则此简谐振动的三个特征量为A= 上学吧找答案 sketch template

如图7–2–4所示沿x轴方�的一条细绳上有Oabc四点Oa=abbc=5ab质点O在垂直于x轴方�上做简谐运动沿x轴传播形成 sketch template

一简谐横波以4m/s的波速沿x轴正方�传播已知t=0时的波形如图所示则 A．波的�期为1s B．x=0处的质点在t=0时�y轴负�运动 C sketch template

如图所示是一列沿x轴正方�传播的简谐横波在t＝0时刻的波形图已知波的传播速度v＝2m/s．试回答下列问题�写出x＝05 M处的质点做简谐 sketch template

图5所示为简谐横波在某一时刻的波形图已知此时质点A正�上运动如箭头所示由此可断定此横波 A�右传播且此时质点B正�上运动 sketch template

如左图所示是利用沙�演示简谐运动图象的装置当盛沙的漏斗下面的薄木板被水平匀速拉出时做简谐运动的漏斗漏出的沙在板上形成的曲线显示出沙�的振动 sketch template

弹簧振子做简谐运动其位移x与时间t的关系如图所示由图可知A．在t＝1 S时速度为负�最大加速度为零 B．在t＝2 S时位移为正�最大 sketch template

11．弹簧振子做简谐运动的图线如下图所示在t1至t2这段时间内 A．振子的速度方�和加速度方�都不变 B．振子的速度方�和加速度方�都 sketch template

一简谐横波沿x轴正�传播t＝0时刻的波形如图 A所示x＝030 M处的质点的振动图线如图b所示该质点在t＝0时刻的运动方�沿y sketch template

如图所示为一列简谐横波某时刻的波形图波传播的速度为20m/s若以此时刻之后01s开始计时则a点的振动图象应是图中的 A．B．C．D sketch template

如图11 1 5所示是某质点做简谐运动的振动的图象根据图象中的信息回答下列问题 图11 51质点离开平衡位置的最大距离有多大 sketch template

4．一列简谐横波沿着x轴正方�传播某一时刻的波形图象如图3所示下列判断不正确的是 A．这列波的波长是8m B．此时刻x =3m处质点正沿y sketch template

百度教育 sketch template

如图33所示一列简谐横波沿x轴正方�传播从波传到x=5m的M点时开始计时已知P点相继出现两个波峰的时间间隔为04s下面说法中正确的是 sketch template

一个质点做简谐运动的图象如图5所示下述正确的是 A质点振动�率为4赫兹 B在10 S内质点经过的路程是20 Cm C在5 S末 sketch template

一列简谐横波沿x轴正方�传播t=0时刻的波形如图中的实线所示t=02s时刻的波形如图中的虚线所示则 A．t=02s时刻质点P�右 sketch template

一列沿x轴传播的简谐横波某时刻的波形图象如图甲所示．若从此时刻开始计时则图乙表示abcd中哪个质点的振动图象 A．若波沿x轴正方� sketch template

21．如图所示是一列沿x轴正方�传播的简谐横波在t＝0时刻的波形图已知波的传播速度v＝2m/s．试回答下列问题 1该波的波长为多大 sketch template

一质点做简谐运动的图象如图所示下列说法正确的是A．质点振动�率是4Hz B．在10s内质点经过的路程是20cm C．第4s末质点的速度是零 sketch template

如图所示实线是沿x轴传播的一列简谐横波在t=0时刻的波形图质点P恰在平衡位置虚线是这列波在t=02s时刻的波形图．已知该波的波速是0 sketch template

一列简谐横波在t=0时的波形图如图所示．介质中x=2m处的质点P沿y轴方�做简谐运动的表达式为y=10sincm．关于这列简谐波下列说法正确 sketch template

8．如图所示为一弹簧振子作简谐运动的振动图象根据图象可以判断 A．从t1时刻到t3时刻振子经过的路程为2A B．t2时刻和t3时刻振子的速度 sketch template

如图所示一列简谐横波在t时刻的波形图象已知波的传播速度为2m/sabc是三个振动的质点．以下列说法中正确的是 A．振源的振动�率 sketch template

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