如图 abc为等边三角形延长bc到点d延长ba到点e使ae＝bd连接cede．求证ce＝de．题目和参考答案——青夏教育精英 Sketch Coloring Page

如图 abc为等边三角形延长bc到点d延长ba到点e使ae＝bd连接cede．求证ce＝de．题目和参考答案——青夏教育精英 Template

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sketch #5232 Avril by Teresa Temacha

anonymous

anonymous
sketch #5232 Avril by Teresa Temacha

sketch #2646 Buzzy bee on flowers

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anonymous

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sketch #2636 Robitina by sketchmaster

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anonymous

anonymous
sketch #5020 Stitch by Hina Ali

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sketch #5371 Senorita by Adrian Matosek

anonymous

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sketch #5371 Senorita by Adrian Matosek

sketch #5059 Edward Hopper&#;s &#;Nighthawks&#; by Rosanne Zammit

anonymous

anonymous
sketch #5059 Edward Hopper&#;s &#;Nighthawks&#; by Rosanne Zammit

sketch #5169 Iron Man by Hannah Kellogg

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sketch #5169 Iron Man by Hannah Kellogg

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sketch #288 RK

anonymous

anonymous
sketch #288 RK

sketch #1219

anonymous

anonymous
sketch #1219

sketch #4264 oh yeah

anonymous

anonymous
sketch #4264 oh yeah

sketch #5351

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sketch #5180

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sketch #3296

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anonymous
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anonymous

anonymous
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anonymous

anonymous
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sketch #3014 Fancy

James Forest
sketch #3014 Fancy "S "

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anonymous

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anonymous

anonymous
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anonymous

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sketch #5079 SketchToy Pencil by Sarah Prieto

anonymous

anonymous
sketch #5079 SketchToy Pencil by Sarah Prieto

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sketch #2904 Pinky and the Brain by Tim Poole

anonymous

anonymous
sketch #2904 Pinky and the Brain by Tim Poole

tomski如图 abc为等边三角形延长bc到点d延长ba到点e使ae＝bd连接cede．求证ce＝de． coloring

如图， ABC是等边三角形，D是BC边上一点，且满足∠ADE=60∘，DE交等边三角形ABC的外角平分线CE所在直线于点E，试探究AD与DE的 sketch template

如图，已知 ABC是等边三角形，延长BA至E，延长BC至D，使AE=BD，求证：EC=ED．百度教育 sketch template

1如图1 ABC为等边三角形点D为BC边上一点作DE∥AC交AB于点E说明 BDE也是等边三角形．2如图2 ABC为等边三角 sketch template

如图已知 ABC为等边三角形点D由点C出�在BC的延长线上运动连结AD以AD为边作等边三角形ADE连结CE．1请写出ACCD sketch template

如图所示，边长为2的等边三角形中，D点在边上运动（不与B、C重合），点E在边的延长线上，点F在边的延长线上，．点D在边上从B至C的运动过程 sketch template

如图1等边三角形ABC的边长为8点P由点B开始沿BC以每秒1个单位长的速度作匀速运动到点C后停止运动点Q由点C开始沿C A B以每 sketch template

如图已知 ABC为等边三角形点D由点C出�在BC的延长线上运动连结AD以AD为边作等边三角形ADE连结CE．1请写出ACCD sketch template

如图1等边三角形ABC的边长为8点P由点B开始沿BC以每秒1个单位长的速度作匀速运动到点C后停止运动点Q由点C开始沿C A B以每 sketch template

如图已知 ABC为等边三角形CF∥AB点P为线段AB上任意一点点P不与AB重合过点P作PE∥BC分别交ACCF于GE．1 sketch template

如图， ABC为等边三角形，以BC为斜边�下作等腰直角三角形BDC，连接AD交BC于点O．E为线段AC上一动点（不与A，C重合），连接BE sketch template

已知 ABC为边长为10的等边三角形D是BC边上一动点 �如图1点E在AC上且BD=CEBE交AD于F当D点�动时∠AFE的大小 sketch template

如图， ABC是等边三角形，它的面积为1，延长BC至D，使BD=2BC，延长CA至E，使CE=3CA，延长AB至F，使AF=4AB，求 DEF sketch template

题目已知如图 ABC和 CDE均为等边三角形BCD三点在同一条直线上连接线段BEAD交于点F连接CF1求证∠FBC sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

已知 ABC中AB=AC∠BAC=α DBC为等边三角形．1如图1∠ABD= 2如图2若∠BCE=150°∠ABE=60 sketch template

如图，三角形ABC三角形CDE为等边三角形，BCD在一条线上，等边三角形ABC等 60813 趣�几何数学天地 33IQ sketch template

人教版初中数学八年级上册等边三角形的性质和判定公开课优质课课件教案视� 知乎 sketch template

如图等边三角形ABC中AB=5延长BC至点P使CP=3将 ABC绕点B顺时针旋转a角得到 DBE连接DPEP则当 DPE为 sketch template

如图，在四边形ABCD中，AD∥BC，E为CD的中点，连结AE，BE，延长AE交BC的延长线于点F。 sketch template

如图在等边 ABC中D是AC的中点延长BC到点E使CE=CDAB=10cm．1求BE的长2 BDE是什么三角形为什么 sketch template

如图等边三角形ABC的边长为6A、B、A1三点在一条直线上且 ABC≌ A1BC1若D为线段BC1上一动点则AD CD的最小值是 sketch template

已知 ABC是等边三角形以BC为直径的半圆O与边AB相交于点DDE⊥AC垂足为点E．1判断DE与⊙O的位置关系并证明你的结论2 sketch template

如图 ABC为等边三角形DE分别是BCAC上的一点且BD=CEAD和BE交于点P求∠APE的度数．题目和参考答案——青夏教育 sketch template

如图D为等边三角形ABC的边BC上的一点以AD为边作等边三角形ADE连接BE．1求证BE=CD2分别取BECD的中点MN sketch template

ABC为等边三角形D为射线BC上一点∠ADE=60°DE与∠ACB的外角平分线交于点E．1如图1点D在BC上求证CA=CD sketch template

如图 ABC为等边三角形DE分别是ACBC上的点且AD=CEAE与BD相交于点PBF⊥AE于点FBP=8则PF= ．题目和 sketch template

如图，在等边三角形ABC的三边上，分别取点D，E，F，使得 DEF为等边三角形，求证：AD＝BE＝CF．——青夏教育精英家教�—— sketch template

如图 ABC是等边三角形分别延长CAABBC到A′B′C′使AA′=BB′=CC′=AC若 ABC的面积为1则 A′B′C sketch template

如图已知ABC为等边三角形DF分别是BCAB上的点且CD=BF以AD为边作等边三角形ADEDACD≌DCBF．试问当点D在线段 sketch template

如图所示 ABC为等边三角形BD平分∠ABCDE⊥BC于EEC＝1则BC＝题目和参考答案——青夏教育精英家教�—— sketch template

如图等边三角形ABC的边长为4P是三角形内角任意一点过点P作三边的垂线PDPEPF垂足分别为DEF．则PD PE PF sketch template

如图 ABC和 DBE均为等边三角形已知AB=6BD=23现把 DBE绕点B逆时针旋转所得三角形记为 D′BE′连接AE′当∠ sketch template

如图， ABC和 DEF是两个全等的等腰直角三角形，∠ BAC=∠ EDF=90°， DEF的顶点E与 ABC的斜边BC的中点重合，将 DEF sketch template

已知如图 ABC为等边三角形D是BC延长线上一点连接AD以AD为边作等边三角形ADE连接CE．1探究线段CACDCE的 sketch template

百度教育 sketch template

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