如图所示已知∠1=∠2∠b=60°∠acb=80°求∠bcd的度数．题目和参考答案——青夏教育精英家教�—— Sketch Coloring Page

如图所示已知∠1=∠2∠b=60°∠acb=80°求∠bcd的度数．题目和参考答案——青夏教育精英家教�—— Template

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tomski如图所示已知∠1=∠2∠b=60°∠acb=80°求∠bcd的度数．题目和参考答案——青夏教育精英家教�—— coloring

如图已知∠1=40°那么∠2= ．——青夏教育精英家教�—— sketch template

如图所示已知∠1=∠2∠3=∠4∠C=32°∠D=28°求∠P的度数——青夏教育精英家教�—— sketch template

1如图1量一量∠1= ∠2= 2如图2画一画 题目和参考答案——青夏教育精英家教�—— sketch template

初中数学之平行线拐点模型知乎 sketch template

看图已知∠1=75 求∠2∠3和∠4的度数． 题目和参考答案——青夏教育精英家教�—— sketch template

如图所示∠1 ∠2 ∠3 ∠4 ∠5 ∠6等于度．——青夏教育精英家教�—— sketch template

如图在 ABC中∠1=∠2∠C＞∠BE为AD上一点且EF⊥BC于F．1试探索∠DEF与∠B∠C的等量关系2如图所示当点 sketch template

题目如图已知∠1=∠2∠B=∠C可推得AB∥CD．理由如下 ∵∠1=∠2且∠1=∠4∴∠2=∠4∴CE∥BF∴∠=∠ sketch template

如图所示已知∠1=∠2∠3=∠4∠C=32°∠D=28°求∠P的度数——青夏教育精英家教�—— sketch template

如图已知∠BOC=2∠AOCOD平分∠AOB且∠COD=20°求∠AOB的度数． 题目和参考答案——青夏教育精英家教�—— sketch template

一副三角板按如图所示的方式�放，且∠1比∠2大50°，则∠2的度数为 A．20° B．50° C．70° D．30°——青夏教育精英家教�—— sketch template

用两种方法证明“圆的内接四边形对角互补”．已知：如图�，四边形ABCD内接于⊙O．求证：∠B＋∠D＝180°．证法1：如图�，作直径DE交⊙ sketch template

20．如图已知∠1=70°∠2=110°∠3=55°求∠4度数——青夏教育精英家教�—— sketch template

如图已知∠1=20°∠2=25°∠A=35°则∠BDC的度数为 ——青夏教育精英家教�—— sketch template

如图所示AB=ADAC=AE∠1=∠2求证 ABC≌ ADE． 题目和参考答案——青夏教育精英家教�—— sketch template

如图所示，∠1和∠2是对顶角的是 ——青夏教育精英家教�—— sketch template

15．如图所示已知∠AOB=165°∠AOC=∠BOD=90°求∠COD．——青夏教育精英家教�—— sketch template

3．如图已知∠1＝180°∠2＝100°∠BAC＝60° 1直线AB与CD平行吗 2求∠C的度数——青夏教育精英家教�—— sketch template

如图所示ABCDEF交于点O∠1=20°∠BOC=80°求∠2的度数——青夏教育精英家教�—— sketch template

将一直角三角形与两边平行的纸条如图所示放置下列结论�∠1＝∠2�∠3＝∠4�∠2 ∠4＝900�∠4 ∠5＝1800其中正确的有 sketch template

如图1已知AB是⊙O的直径弦CD⊥AB于点E点M在⊙O上∠M=∠D1判断BC与MD的位置关系并说明理由2若AE=8BE sketch template

11．如图8已知AB＝AD∠1＝∠2要使 ABC≌ ADE还需添加的条件是 ——青夏教育精英家教�—— sketch template

题目如图已知点O在直线AB上将一副直角三角板的直角顶点放在点O处其中∠OCD=60°∠OEF=45°．边OCOE在直线AB上 sketch template

如图∠1=60°∠2=30°∠3=120° 题目和参考答案——青夏教育精英家教�—— sketch template

如图所示∠1=72°∠2=72°∠3=60°求∠4的度数——青夏教育精英家教�—— sketch template

题目用两种方法证明“圆的内接四边形对角互补．已知如图�四边形ABCD内接于⊙O．求证∠B ∠D＝180°．证法1如图�作直径 sketch template

18．如图11CD⊥AB于DDE∥BC∠1＝∠2则FG与AB的位置关系是 ——青夏教育精英家教�—— sketch template

如图5所示已知∠AOB=64°OA1平分∠AOBOA2平分∠AOA1OA3 平分∠AOA2OA4平分∠AOA3则∠AOA4的大小为 sketch template

如图所示的图形是由12个有公共顶点O的直角三角形拼成的∠AOB=∠BOC= ∠LOM=30°．你能从图中找出与 ABO位似的图形吗它们的位 sketch template

15．如图所示已知∠AOB=165°∠AOC=∠BOD=90°求∠COD．——青夏教育精英家教�—— sketch template

已知如图CD⊥ABBE⊥AC垂足分别为DEBECD相交于O点 ∠1=∠2图中全等的三角形共有A．1对 B．2对 C．3对 D sketch template

如图所示已知三角形ABC中∠BAC为钝角． 1画出点C到AB的垂线段 2过A点画BC的垂线 3点B到AC的距离是多� sketch template

如图所示三角形DEF平移得到三角形ABC已知∠B=45°∠C=65°AB=2cm则∠DFE=65度DE=2cm． 题目和参考答案 sketch template

如图所示点E在AC的延长线上下列条件中不能判断AC∥BD的是A∠3=∠4B∠D ∠ACD=180°C∠D=∠DCED∠1=∠2 sketch template

如图O是等边 ABC内的一点已知∠AOB=110°∠COD=60°∠BOC=α BOC≌ ADC．1求证 COD是等边三角形 sketch template

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