如图所示截面为等腰三角形的棱镜顶角α=4130°一束白光以较大的入射角θ从棱镜的一侧射入通过棱镜后从另一个侧面射出在光屏上形成由红到 Sketch Coloring Page

如图所示截面为等腰三角形的棱镜顶角α=4130°一束白光以较大的入射角θ从棱镜的一侧射入通过棱镜后从另一个侧面射出在光屏上形成由红到 Template

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tomski如图所示截面为等腰三角形的棱镜顶角α=4130°一束白光以较大的入射角θ从棱镜的一侧射入通过棱镜后从另一个侧面射出在光屏上形成由红到 coloring

如图所示截面为等腰三角形的棱镜顶角α=4130°一束白光以较大的入射角θ从棱镜的一侧射入通过棱镜后从另一个侧面射出在光屏上形成由红到 sketch template

截面为等腰直角三角形的棱镜称为全反射棱镜如图所示由ab两束单色光组成的复色 光沿PO方�斜射�一全反射棱镜ABC的BC面经ABAC面 sketch template

如图所示一玻璃三棱镜的横截面为等腰直角三角形ABC一束红光平行于BC边从S点射入三棱镜经AB面折射后又在BC面�生反射然后恰好从P点 sketch template

如图所示等腰直角三角形的ABC为棱镜截面∠A=90°一束由两种单色光ab组成的复色光平行于BC边射入棱镜经过AB折射后光线射到BC边 sketch template

例10abc为全反射棱镜它的主截面是等腰直角三角形如图23 3所示一束白光垂直入射到ac面上在ab面上�生全反射若光线入射点O的 sketch template

如图所示侧面是全等的等腰三角形的棱锥是 A正棱锥 B侧棱长相等的棱锥C斜高长相等的棱锥 D以上均不对题目和参考答案——青夏教育精英 sketch template

如图所示， ABC是等腰直角三角形，∠ACB=90°，AD是BC边上的中线，过C作AD的垂线，交AB于点E，交AD于点F．求证：（1）∠ADC sketch template

如图所示，直角三角形为玻璃棱镜的截面，其中边长为。高途 sketch template

23．截面为等腰三角形的玻璃棱镜ABC顶角B为60° 入射AB面的光线通过棱镜的光路如图23所示其中折 射入棱镜的光线与底面AC平行 sketch template

如图所示abc为一全反射棱镜它的主截面是等腰直角三角形一束白光垂直入射到ac面上在ab面上�生全反射若光线入射点的位置保持不变改变 sketch template

如图19 4 12所示abc为一全反射棱镜它的横截面是等腰直角三角形一束白光垂直入射到ac面上在ab面上�生全反射若光线的入射点O的 sketch template

如图圆锥O的轴截面是一个面积为1的等腰直角三角形C为弧上的一点E为线段上的动点则的最小值为 A B C 2 D 百度教育 sketch template

研究�光物体的光谱通常需要三棱镜如图所示是截面为等边三角形ABC的三棱镜一束光从AB边的P点射入棱镜当入射角i=60°时进入棱镜的折射 sketch template

如图所示侧面是全等的等腰三角形的棱锥是 A正棱锥 B侧棱长相等的棱锥C斜高长相等的棱锥 D以上均不对题目和参考答案——青夏教育精英 sketch template

如图主截面是等边三角形的三棱镜折射率为2光线从它的一个面垂直入射则它从三棱镜射出的光线为图所示的abc中的 A．aB．bC sketch template

$如图所示某透明材枓三棱镜的横截面为直角三角形角A等于90°角B等于30°该材料的折射率n=$frac{sqrt{5}}{2 sketch template$

如图用三个边长为a的等边三角形拼成如图1所示的等腰梯形现将这个等腰梯形截成四个全等的等腰梯形然后将其中的一个等腰梯形按照上述方法再截 sketch template

如图有一等腰直角玻璃三棱镜ABC对各种色光的临界角都小于450一束平行于BC面的白光射到AB面上进入三棱镜后先射到BC面上则光束 sketch template

如图所示为某种透明介质制成的棱镜，其截面是一个等腰三角形ABC，∠A=30°，AB边的长度为L，有一束单色光以平行于AC边的方�从AB边上距离 sketch template

如图所示顶角为36°的等腰三角形其底边与腰之比等于k这样的三角形叫黄�三角形已知腰长AB=1 ABC为第一个黄�三角形 BCD为第 sketch template

如图所示截面为ABC的玻璃直角三棱镜放置在空气中宽度均为d的紫红两束光垂直照射三棱镜的一个直角边AB在三棱镜的另一侧放置一平行于AB边 sketch template

几何模型倍角三角形构造知乎 sketch template

如图所示质量为m横截面为直角三角形木块ABC∠ABC=αAB边靠在竖直墙上F是垂直于斜面BC的推力现物块静止不动则�擦力大小为 sketch template

如图所示等腰直角三角形ABC为一个三棱镜的截面折射率为n直角边AB的长为a．一束很细的单色光从AB中点垂直入射光在真空中的传播速度为c sketch template

如图所示一个横截面为直角三角形的三棱镜∠A=30°∠C=90°．三棱镜材料的折射率是n=3．一条与BC面成θ=30°角的光线斜射�BC面 sketch template

如图14 1 21所示一个三棱镜的顶角θ＝41°30′一束白光以较大的入射角i从棱镜左侧面射入从右侧面射出并在光屏P上形成由红到紫的 sketch template

1． ABC的三边长分别为AC=3 BC=4 AB=5 以AB所在直线为轴将此三角形旋转一� 求所得旋转体的表面积——青夏 sketch template

如图所示由透明材料制成的一个截面为直角三角形的三棱镜ABC有一单色光线以45°角入射到AB界面上折射角是30°折射光线恰好在AC界面 sketch template

如图所示某三棱镜的截面是一直角三角形其中∠ACB=60°．棱镜材料的折射率为n底面BC涂�入射光沿平行于底面BC的方�射�AC为了使 sketch template

如图所示等边三角形ABC为透明柱状介质的横截面一束平行于角平分线BD的单色光由AB面射入介质经AB面折射的光线恰好平行于BC．则介质对此 sketch template

如图所示三棱镜的顶角是30º出射光线与入射光线夹角也为30º问 1 该三棱镜的折射率是多大 2光在棱镜里的传播速度是多大 sketch template

在如图所示的�格中每个小正方形的边长均为1个单位每个小正方形的顶点叫做格点．1请你在图1中画一个以格点为顶点面积为6个平方单位的等腰 sketch template

如图所示截面为直角三角形ABC∠B=30°斜边AB=a．棱镜材料的折射率为n=$sqrt{2}$．在此截面所在的平面内一条光线在距 sketch template

将两块完全相同的等腰直角三角形�成如图所示的样子假设图形中所有的点和线段都在一个平面内回答下列问题1图中有多�个三角形把它们一一 sketch template

如图所示某三棱镜的截面是一直角三角形棱镜材料的折射率为n底面BC涂�入射光沿平行于底面BC的方�射�AB而经AB和AC折射后射出 sketch template

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