如图所示在三棱锥p abc中pa⊥平面abc E为ac的中点 1求异面直线be与pc所成角的余弦值 2求二面角p Be C Sketch Coloring Page

如图所示在三棱锥p abc中pa⊥平面abc E为ac的中点 1求异面直线be与pc所成角的余弦值 2求二面角p Be C Template

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tomski如图所示在三棱锥p abc中pa⊥平面abc e为ac的中点 coloring

如图，在三棱锥P−ABC中，AB=BC=2√2，PA=PB=PC=AC=4，O为AC的中点．证明：PO⊥平面ABC．百度教育 sketch template

9．如图在三棱锥P – ABC中PA = PB PC BC 2且则PA与底面ABC所成角为 A．30° B．60 sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

如图所示正三棱锥 P−ABC 中， M 是 PC 上一点， PM=2MC ，且 PB⊥AM ， AB=2 ，则三棱锥 的外接球的 sketch template

如图所示在三棱锥P ABC中PA⊥平面ABC E为AC的中点 1求异面直线BE与PC所成角的余弦值 2求二面角P BE C sketch template

如图所示，三棱锥P ABC中，PA⊥平面ABC，AB⊥BC，平面α经过棱PC的中点E，与梭PB，AC分别交于点F、D，且BC∥平面α，PA∥ sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

百度教育 sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

18． 如图在三棱锥P ABC中AB⊥BCAB＝BC＝kPA点OD分别是ACPC的中点OP⊥底面ABC． Ⅰ求证OD∥平面 sketch template

百度教育 sketch template

如图所示在三棱锥P ABC中PA⊥平面ABC E为AC的中点 1求异面直线BE与PC所成角的余弦值 2求二面角P BE C sketch template

如图所示在三棱台A′B′C′ ABC中沿A′BC截去三棱锥A′ ABC则剩余的部分是 A．三棱锥B．四棱锥C．三棱柱D．组合体题目 sketch template

如图在三棱锥PABC中AC = BC 2∠ACB 90°AP BP ABPC⊥AC． 1 求证PC⊥AB sketch template

如图在三棱锥P ABC中PA垂直于平面ABCAC⊥BC．求证BC⊥平面PAC．题目和参考答案——青夏教育精英家教�—— sketch template

四棱锥P ABCD的三视图如下E是侧棱PC上的动点． 1求四棱锥P ABCD的体积 2是否不论点E在何位置都有BD⊥AE证明你 sketch template

如图在三棱柱ABC A1B1C1中侧面AA1C1C⊥底面ABCAA1=A1C=AC=2AB=BCAB⊥BCO为AC的中点1 sketch template

如图所示在三棱台A′B′C′ ABC中沿A′BC截去三棱锥A′ ABC则剩余的部分是 A．三棱锥B．四棱锥C．三棱柱D．组合体题目 sketch template

在三棱锥P ABC中 PAC和 PBC是边长为2的等边三角形AB=2O是AB中点．1在棱PA上求一点M使得OM∥平面PBC2 sketch template

如图所示，在三棱锥中，平面，，，，，高途 sketch template

9．在正三棱锥中为的中点且求异面直线与所成的角的余弦值．反思回顾——青夏教育精英家教�—— sketch template

19．如图所示四棱锥P ABCD中底面ABCD为直角梯形点E在棱PA上且PE=2EA 1 求异面直线PA与CD所成的角 2 sketch template

18．如图所示在四棱锥P ABCD中底面ABCD是一直角梯形∠BAD=90° AD∥BC AB = BC A AD 2a sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

2．如图正三棱锥P ABC顶点P在底面上的射影在ΔABC内部M是侧面PAB上的点且M到点P的距离等于M到底面的距离则点M的轨迹是 sketch template

一个四棱锥的底面为正方形其直观图与三视图如图所示则二面角P DC A的正弦值为 ABCD——青夏教育精英家教�—— sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图所示在四棱锥P ABCD中底面ABCD为菱形且∠DAB=60°PA=PDM为CD的中点BD⊥PM．1求证平面PAD⊥平面 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图在三棱柱ABC A1B1C1中四边形A1ABB1是菱形四边形BCC1B1是矩形AB⊥BCCB=3AB=4∠A1AB=60 sketch template

如图所示，在三棱锥中，与所成的角为，且．在线段上分高途 sketch template

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