如图所示电路中电阻r1r2r3r4=1234c为电容器为电流表当电路中某个电阻断路瞬间�现有自上而下的电流通过电流表则 Sketch Coloring Page

如图所示电路中电阻r1r2r3r4=1234c为电容器为电流表当电路中某个电阻断路瞬间�现有自上而下的电流通过电流表则 Template

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tomski如图所示电路中电阻r1r2r3r4=1234c为电容器为电流表当电路中某个电阻断路瞬间�现有自上而下的电流通过电流表则 coloring

如图所示，电源电压恒为18V，定值电阻R1=20Ω，�动变阻器R2标有“40Ω 05A”，电流表A的量程为006A，电压表量程为0 sketch template

百度教育 sketch template

两个定值电阻R1、R2并联在电路中如图甲所示它们的电流与其两端的电压关系如图乙所示闭合开关S则R1R2产生的热量之比为 A sketch template

如图所示电路中电阻R1R2R3R4=1234C为电容器为电流表当电路中某个电阻断路瞬间�现有自上而下的电流通过电流表则 sketch template

在如图所示的电路中，电源电压保持不变，定值电阻R1的阻值为10Ω，�动变阻器R2上标有“2A”字样。闭合开关S，移动�片P至电路中的电流最大 sketch template

如图所示的电路中，电阻R1＝1Ω，R2＝2ΩR3＝3Ω在A、B间接电源S1、S2都打开，此时电阻R1、R2、R3消耗的功率之比P1∶P2 sketch template

如图所示电路中接电动势为4V内电阻为2Ω的直流电源电阻R1R2R3R4的阻值均为4Ω电容器的电容为30μF电流表的内阻不计当 sketch template

如图所示电路中已知电容C=2μF电源电动势ε=12V内电阻不计R1R2R3R4=1263则电容器极板所携带的电量为 A sketch template

如图1所示的电路中R1为定值电阻R2为�动变阻器电源电压不变．闭合开关S后�片P从a端移动到b端电流表示数I与电压表示数U的变化关系 sketch template

如图所示的电路中电源的电压保持不变R1为定值电阻R2为�动变阻器闭合开关S�片P�右移动时则A．电流表A的示数变大B．电压表V的示 sketch template

图甲是小灯泡L和定值电阻R的电流与电压的关系，则R的电阻为Ω，现将它们并联后接在电压为2V的电源两端，如图乙，则干路中的电流是A；若将它们串联 sketch template

如图所示的电路中，电源两端电压保持不变，电阻R2的阻值为20Ω．闭合开关后，电压表的示数为2V，电流表的示数为02A，求：1电阻R1的 sketch template

如图所示电路中电压U保持不变电流表的示数为1A如果R1与R2的等效电阻为R并且R1R=53电阻R2消耗的电功率为24W则电阻 sketch template

如图左所示为两电阻R1和R2的伏安特性曲线将电阻R1和R2接入如图右所示电路中闭合开关s后当�动变阻器触片P�下移动时则 A．电流 sketch template

如图所示的电路中电源电动势E=6V内阻r=1Ω电阻R1=6ΩR2=5ΩR3=3Ω电容器的电容C=2×10 5F若将开关S闭合 sketch template

如图所示的电路中电源电动势E=6V内阻r=1Ω电阻R1=6ΩR2=5ΩR3=3Ω电容器的电容C=2×10 5F若将开关S闭合 sketch template

如图所示的电路中要使电阻R1和R2组成并联电路则开关的断开闭合情况应该是 A．S1闭合S2S3断开B．S2闭合S1S3断开C sketch template

如图所示的电路中电源电动势E=6V内阻r=1Ω电阻R1=6ΩR2=5ΩR3=3Ω电容器的电容C=2×10 5F若将开关S闭合 sketch template

一轮复习：含容电路 知乎 sketch template

如图1所示的电路电源电压保持不变．闭合开关S调节�动变阻器两电压表的示数随电路中电流变化的图线如图2所示．根据图线的信息可知是电压表 sketch template

如图所示电路中电源电动势ε恒定内阻r=1Ω定值电阻R3=5Ω当电键K断开与闭合时ab段电路消耗的电功率相等则下列说法中正确的是 A sketch template

如图所示的电路中电路消耗的总功率为30W电阻R1为3ΩR2为6Ω电源内阻r为02Ω电源的效率为94%求1电源的电动势2 sketch template

如图所示电路中平行板电容器极板水平放置板间有一质量为m的带电油滴悬浮在两板间静止不动．要使油滴�上运动可采用的方法是 A．只把电阻 sketch template

如图所示的部分电路中电源电压U保持不变abc为三个接线柱．现备有三个电阻R1＝9ΩR2＝6ΩR3＝3Ω． 1若只在ac间接 sketch template

如图所示电路中，已知I1=2A、I2= 4A、I3= 1A；R1=R2=3Ω，R3=2Ω。则电压Uao为 勤学星球 sketch template

如图8所示电路中电阻R1=8 ΩR2=10 ΩR3=20 Ω电容器电容C=2 μF电源电动势E=12 V内电阻r不计开关S闭合 sketch template

如图所示的电路中电源电动势E=6V内阻r=1Ω电阻R1=6ΩR2=5ΩR3=3Ω电容器的电容C=2×10 5F若将开关S闭合 sketch template

如图所示电路中电源电压U=45V且保持不变定值电阻R1=5Ω变阻器R2最大电阻为20Ω电流表量程为0 06A电压表量程为0 sketch template

如图所示的电路中AB两点间的电压是6V电阻R1=15ΩR2=5Ω 求电路的总电阻R和总电流I是多�——青夏教育精英家教�—— sketch template

如图所示电路中电源电压不变R1为定值电阻R2为�动变阻器两个电压表V1V2分别接入电路不同位置．闭合开关S�右移动�片P�现电压 sketch template

如图所示电路中电阻R1=8 ΩR2=10 ΩR3=20 Ω电容器电容C=2 μF电源电动势E=12 V内电阻r不计开关S闭合当 sketch template

如图所示的电路中，电源电压保持不变。闭合开关S后，�片P从b端移动到a端的过程，电压表示数U与电流表示数I的关系图像如图所示。下列说法正确的是（ sketch template

如图所示电路中R1R2串联电源电压为4VR2=12Ω．S闭合时电流表的读数为025A．求1R1R2串联的总电阻2R1的 sketch template

如图所示电路中电阻R1=30ΩR2=15Ω电源电压为U且保持不变当开关S1S2同时断开电流表示数为02A则电源电压U=99V sketch template

如图所示电路中电源电压恒定Rl为定值电阻R2为�动变阻器．闭合开关S后�动变阻器�片自b�a移动的过程中 A．电压表V2的示数变小 sketch template

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