如图已知d是 abc的bc边的中点de⊥acdf⊥ab垂足分别为ef且df=de则 abc是等腰三角形吗请说明理由．——青夏 Sketch Coloring Page

如图已知d是 abc的bc边的中点de⊥acdf⊥ab垂足分别为ef且df=de则 abc是等腰三角形吗请说明理由．——青夏 Template

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sketch #4383 4383

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sketch #4900 Moonlight by Abdelwahab Haik

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tomski如图已知d是 abc的bc边的中点de⊥acdf⊥ab垂足分别为ef且df=de则 abc是等腰三角形吗请说明理由．——青夏 coloring

如图，在三角形 ABC 中， D 是 BC 的中点， E 、 F AC 的三等分点。已知三角形 的面积是 108 平方厘米。求三角 sketch template

如图D是 ABC的边BC上任意一点EF分别是线段ADCE的中点且 ABC的面积为40cm2则 BEF的面积是 Cm2．A．5B sketch template

如图1在 ABC中AC=BC∠ACB=90°点D为AB边中点以点D为顶点作∠PDQ=90°DPDQ分别交直线ACBC于EF sketch template

如图，已知 ABC中，∠B=∠C，AB=8厘米，BC=6厘米，点D为AB的中点，如果 60887 趣�几何数学天地 33IQ sketch template

如图已知D是 ABC的BC边的中点DE⊥ACDF⊥AB垂足分别为EF且DF=DE则 ABC是等腰三角形吗请说明理由．——青夏 sketch template

16．如图已知D E分别是 ABC的边BC和边AC的中点连接DEAD若S=24cm求 DEC的面积——青夏教育精英家教�—— sketch template

如图已知D是 ABC中的边BC上的一点∠BAD=∠C∠ABC的平分线交边AC于E交AD于F那么下列结论中错误的是 A BAC sketch template

如图已知 ABC中AB=ACM是BC的中点DE分别是ABAC边上的点且BD=CE1求证MD=ME．2若D为AB的 sketch template

21．已知如图3 48D是 ABC的边BC上的一点且CD=AB∠BDA=∠BADAE是 ABD的中线．求证 AC=2AE．——青夏 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图1，D、E、F分别是 ABC各边上的点，四边形ADEF是平行四边形，有三个选项：�D是AB的中点，�E是BC的中点，�F是AC的中点． sketch template

如图在Rt ABC中∠ABC=90°BA=BC点D是AB的中点连接CD过点B作BG⊥CD分别交CDCA于点EF与过点A且 sketch template

如图已知等边 ABC以边BC为直径的圆与ABAC分别交于点D点E．过点D作DF⊥AC垂足为F．1判断DF与⊙O的位置关系并证明 sketch template

如图已知 ABC中AB=AC=20cm∠ABC=∠ACBBC=16cm点D是AB的中点．点P在线段BC上以6厘米/秒的速度由B点�C sketch template

如图所示，已知边长为4的正三角形ABC中，E，F分别为BC和AC的中点，PA=2，且PA⊥平面ABC，设Q是CE的中点（1）求证：AE∥平面 sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

如图在边长为2的等边 ABC中AD⊥BC于点D且AD=$sqrt{3}$E为AC中点P为AD上一点则 PEC�长的最小值是 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图DEF分别是 ABC各边的中点1中线AD与中位线EF的关系是互相平分为什么2当 ABC满足什么条件时四边形ADEF是 sketch template

如图⊙O是 ABC的外接圆点D是弧ABC的中点过点D作DF⊥CB交CB的延长线于点F连接BD当DF=2BF=1AD=3时AB的 sketch template

百度教育 sketch template

如图已知等边 ABC以边BC为直径的圆与ABAC分别交于点D点E．过点D作DF⊥AC垂足为F．1判断DF与⊙O的位置关系并证明 sketch template

如图已知C是AB的中点D是AC的中点E是BC的中点 1若AB=18cm求DE的长2若CE=5cm求DB的长——青夏 sketch template

如图AB是半圆⊙O的直径 ABC的两边ACBC分别交半圆于DE且E为BC的中点已知∠BAC=50°则∠C= A 55 sketch template

如图D是等边 ABC的边AB上一点E是BC延长线上一点CE=DA连接DE交AC于F过D点作DG⊥AC于G点．证明下列结论1AG sketch template

如图，等腰三角形ABC的底边BC长为4，面积是12，腰AB的垂直平分线EF分别交AB，AC于点E、F，若点D为底边BC的中点，点M为线段EF上 sketch template

14．如图点DEF分别是 ABC三边上的中点．若 ABC 的面积为12则 DEF的面积为 ．——青夏教育精英家教�—— sketch template

如图1所示已知 ABC中∠BAC=90°AB=ACAE是过点A的一条直线且B点和C点在AE的同侧BD⊥AE于D点CE⊥AE于E点 sketch template

已知如图在等边三角形ABC中MN分别是ABAC的中点D是MN上任意一点CDBD的延长线分别与ABAC交于FE若1CE sketch template

如图1等边三角形ABC的边长为8点P由点B开始沿BC以每秒1个单位长的速度作匀速运动到点C后停止运动点Q由点C开始沿C A B以每 sketch template

如图点DE分别是 ABC的边ABAC的中点若DE=6则BC=12．题目和参考答案——青夏教育精英家教�—— sketch template

如图DE分别是ABC的ACAB边上的点BDCE相交于点O若S OCD=2 S OBE=3S OBC=4那么SADOE sketch template

百度教育 sketch template

如图所示已知 ABC的�长是21OBOC分别平分∠ABC和∠ACBOD⊥BC于D且OD=3则 ABC的面积是多� 题目和参考答案 sketch template

如图．已知 ABC的垂心为H．外接圆⊙OM为AB的中点．连接MH并延长交⊙O于D．求证HD⊥CD．题目和参考答案——青夏教育精英家教�—— sketch template

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