如图在等边 abc中de分别是bcac上的点且bd=cead与be相交于点p则∠1 ∠2的度数是 A．45°b．55°c Sketch Coloring Page

如图在等边 abc中de分别是bcac上的点且bd=cead与be相交于点p则∠1 ∠2的度数是 A．45°b．55°c Template

Background image: Hide Show

View Larger Image Image Credit: 1010jiajiao.com

please wait, the page is loading...

More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

sketch #3523 My World My Way by Elena Artene

anonymous

anonymous
sketch #3523 My World My Way by Elena Artene

sketch #1614 uncle bun

Renjith Raj
sketch #1614 uncle bun

sketch #5092 Silvers Rayleigh by Wasim Khan

anonymous

anonymous
sketch #5092 Silvers Rayleigh by Wasim Khan

sketch #1119 crimson

anonymous

anonymous
sketch #1119 crimson

sketch #3439 Aralé by Malyi Link

anonymous

anonymous
sketch #3439 Aralé by Malyi Link

sketch #5370 Requiem for the Phantom by Marita Amaya

anonymous

anonymous
sketch #5370 Requiem for the Phantom by Marita Amaya

sketch #4370 Breaking Bad

anonymous

anonymous
sketch #4370 Breaking Bad

sketch #2593 Tweety by sketchmaster

sketchmaster
sketch #2593 Tweety by sketchmaster

sketch #2645 Flowers in window

Rachel Roe
sketch #2645 Flowers in window

sketch #4975 Orange by Marcos Roberto Molina

anonymous

anonymous
sketch #4975 Orange by Marcos Roberto Molina

sketch #5037 Dolphin by Meen Suksoi

anonymous

anonymous
sketch #5037 Dolphin by Meen Suksoi

sketch #878

Laura Agapi Asnicar
sketch #878

sketch #3506 Goku by Saul Mansanares

anonymous

anonymous
sketch #3506 Goku by Saul Mansanares

sketch #5008

anonymous

anonymous
sketch #5008

sketch #4209 bushy

anonymous

anonymous
sketch #4209 bushy

sketch #654

anonymous

anonymous
sketch #654

sketch #2536

anonymous

anonymous
sketch #2536

sketch #4232 Tobirama by Kadi Kader

anonymous

anonymous
sketch #4232 Tobirama by Kadi Kader

sketch #5339

anonymous

anonymous
sketch #5339

sketch #2477 hhhh

anonymous

anonymous
sketch #2477 hhhh

sketch #2070

anonymous

anonymous
sketch #2070

sketch #3052

anonymous

anonymous
sketch #3052

sketch #1923 12

anonymous

anonymous
sketch #1923 12

sketch #5217

anonymous

anonymous
sketch #5217

sketch #3310 Link by Cxsar Alvarez

anonymous

anonymous
sketch #3310 Link by Cxsar Alvarez

sketch #1449 donara

Donara Smbatyan
sketch #1449 donara

sketch #4698

anonymous

anonymous
sketch #4698

sketch #4471 Brother Bear by Samuel Roberto

anonymous

anonymous
sketch #4471 Brother Bear by Samuel Roberto

sketch #2582

anonymous

anonymous
sketch #2582

sketch #5350

anonymous

anonymous
sketch #5350

tomski如图在等边 abc中de分别是bcac上的点且bd=cead与be相交于点p则∠1 ∠2的度数是 coloring

如图在等边 ABC中DE分别是BCAC上的点且BD=CEAD与BE相交于点P则∠1 ∠2的度数是 A．45°B．55°C sketch template

如图在 ABC中DE分别是边ABAC的中点BC=8则DE=．题目和参考答案——青夏教育精英家教�—— sketch template

如图在等边 ABC中DE分别是BCAC上的点且BD=CEAD与BE相交于点P则∠1 ∠2的度数是 A．45°B．55°C sketch template

如图所示在等边 ABC中点DE分别在边BCAB上且BD=AEAD与CE交于点F则∠DFC的度数为 A．60°B．45°C sketch template

$如图在等边 ABC中点DE分别在边BCAC上且AE=CDBE与AD相交于点PBQ⊥AD于点Q．求证PQ=$frac{1}{2 sketch template$

已知如图在等边三角形ABC中DE分别为BCAC上的点且AE＝CD连结ADBE交于点P作BQ⊥AD垂足为Q．求证BP sketch template

如图1已知 ABC是等边三角形DE分别是ABBC上的点且BD=CEAECD交于点F．1求证 ACE≌ CBD2过A作 sketch template

如图，在等边三角形ABC中，点D，E分别是边BC，CA上的点，且BD=CE，连结AD，BE交于点P．（1）求证： ABE≌ CAD；（2）连接 sketch template

如图在等边 ABC中D是AC的中点延长BC到点E使CE=CDAB=10cm．1求BE的长2 BDE是什么三角形为什么 sketch template

如图等边 ABC中点DE分别是边ABAC的中点CDBE交于点O则∠BOC的度数是120度．题目和参考答案——青夏教育精英家教�—— sketch template

如图，在 ABC中，AB=AC，∠BAC=120°．D是AB边上一点，DE⊥AC交CA的延长线于点E．（1）用等式表示AD与AE的数量关系，并 sketch template

如图在等边 ABC中点DE分别为ABAC边的中点点F为BC边上一点CF=1连接DF以DF为边作等边 DFG连接AG且∠ sketch template

11．如图在等边 ABC中点DE分别在ABAC上如果 ADE∽ ABCAE∶AC＝1∶4BC＝8cm那么 ADE的�长等于 A sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图⊿ABC是等边三角形点DE分别在BCAC上且BD=CEAD与BE相交于点F 1试说明⊿ABD≌⊿BCE 2⊿AEF sketch template

已知在等边三角形ABC中DE分别为ABAC上的点且BD=AEEB与CD相交于点OEF⊥CD于点F．求证OE=2OF．题目和参考 sketch template

如图在等边 ABC中D为AC的中点E是AB上一点且则图中和 ADE相似的三角形有A．1个 B．2个 C．3个D．4个——青夏教育精英 sketch template

如图等边三角形ABC的两条角平分线BD和CE交于I则图中全等的三角形有对．题目和参考答案——青夏教育精英家教�—— sketch template

如图等边 ABC中DE分别为ABBC边的延长线上的点且BD=CEDC的延长线交AE于点FAG⊥CD于点G．1求证 ACE≌ sketch template

如图在 ABC中DE分别是边BCAB上的点BE=AEBD=2CD AEC的面积为S1 ADC的面积为S2若 ABC的面积为8 sketch template

如图，在 ABC中，AB=4，AC=3，BC=5，DE是BC的垂直平分线，DE分别交BC、AB于点D、E．1求证： ABC为直角三角形． 2求 sketch template

如图在 ABC中点DEF分别在ACABBC边上且四边形CDEF是正方形AC=3BC=2求 ADE EFB ACB的�长 sketch template

如图在 ABC中AB=ACAD⊥BCDE⊥ACM为DE的中点AM与BE相交于NAD与BE相交于F求证 BCE∽ ADM3 sketch template

25．如图在 ABC中 DE分别是ACAB上的点 BD与CE交于点O 给出下列三个条件�∠EBO＝∠DCO�∠BEO＝∠CDO sketch template

如图在 ABC中EF分别是ABAC的中点 则 ——青夏教育精英家教�—— sketch template

如图所示，边长为2的等边三角形中，D点在边上运动（不与B、C重合），点E在边的延长线上，点F在边的延长线上，． 点D在边上从B至C的运动过程 sketch template

如图已知在 ABC中AB=AC点D是 ABC内一点且∠ABD=∠ACD求证AD是∠BAC的平分线．题目和参考答案——青夏教育精英 sketch template

已知如图延长 ABC的各边使得BF=ACAE=CD=AB顺次连接DEF得到 DEF为等边三角形．求证 1 AEF≌ sketch template

如图在等边 ABC中P是BC上一点D是AC上的一点∠APD=60°BP=1CD=则 ABC的边长是A 3 B 4 C 5 sketch template

ABC中AB=ACABC＝36DE是BC上的点BAD＝DAE＝EAC则图中等腰三角形的个数是 A2个 B3个 C4个 sketch template

如图在等边 ABC中DEF分别为边ABBCCA上的点且满足∠DEF=60°．1求证BE•CE=BD•CF2若DE⊥ sketch template

如图等边三角形ABC中DE分别为ABBC边上的两个动点且总使BD=CEAE与CD交于点FAG⊥CD于点G则以下结论∠AFG sketch template

如图在 ABC中∠ACB=120°CD平分∠ACBAE∥DC交BC的延长线于点E试说明 ACE是等边三角形．题目和参考答案——青 sketch template

ABC中DE分别是ABAC边的中点若 ABC的�长等于8则 ADE的�长等于A4B6C8D16 题目和参考答案——青夏教育 sketch template

百度教育 sketch template

free web stats