半径为r的半圆形玻璃砖截面如图所示o点为圆心光线a沿半径方�进入玻璃后恰好在o点�生全反射光线b平行于光线a从最高点进入玻璃后折射到 Sketch Coloring Page

半径为r的半圆形玻璃砖截面如图所示o点为圆心光线a沿半径方�进入玻璃后恰好在o点�生全反射光线b平行于光线a从最高点进入玻璃后折射到 Template

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tomski半径为r的半圆形玻璃砖截面如图所示o点为圆心光线a沿半径方�进入玻璃后恰好在o点�生全反射光线b平行于光线a从最高点进入玻璃后折射到 coloring

20．半径为R的半圆形玻璃砖截面如图所示O为圆心光线甲沿半径aO方�射入恰好在O点�生全反射另一条平行于甲的光线乙从最高点射入玻璃砖 sketch template

半径为R的玻璃半圆柱体横截面如图所示圆心为O两条平行单色红光沿截面射�圆柱面方�与底面垂直光线1的入射点A为圆柱面的顶点光线2的 sketch template

半径为R的半圆形玻璃砖，横截面如图所示，圆心为O．两条平行单色红光垂直直径MN射入玻璃砖，光线l正对圆心O入射，光线2的入射点为B，∠AOB sketch template

用“插针法测定透明半圆柱玻璃砖的折射率O为玻璃截面的圆心使入射光线跟玻璃砖的平面垂直如图所示的4个图中P1P2P3和P4是4个学生 sketch template

一半径为R的半圆柱形玻璃砖横截面如图所示．已知玻璃的全反射临界角为γ．与玻璃砖的底平面成角度且与玻璃砖横截面平行的平行光射到玻璃砖的半圆柱 sketch template

如图所示半圆玻璃砖的半径R=10cm折射率为n=直径AB与屏幕垂直并接触于A点．激光a以入射角i=30°射�半圆玻璃砖的圆心O结果在 sketch template

16．如图所示一束截面为圆形半径为R的平行单色光垂直射�一玻璃半球的上表面经折射后在屏幕S上形成一个圆形亮区已知玻璃半球的半径为R sketch template

如图13 7 15半圆形玻璃砖置于光屏PQ的左下方．一束白光沿半径方�从A点射入玻璃砖在O点�生反射和折射折射光在光屏上�现七色光带．若 sketch template

如图为一个半圆形玻璃砖的截面图O为圆心MM′⊥AB．一束单色光沿NO方�射入折射光线为ON′ON与OM的夹角为30°ON′与OM′的 sketch template

如图所示横截面为半径为R的四分之一圆柱玻璃砖放在水平面上其横截面圆心为O点．一束单色光水平射�圆弧面入射点为P入射角为i=60°经 sketch template

半径为R的玻璃半圆柱体横截面如图所示圆心为O一束单色红光沿截面射�圆柱面方�与底面垂直AO为与底面垂直的半径光线的入射点为B∠ sketch template

一个半圆柱形玻璃砖其横截面是半径为R的半圆AB为半圆的直径O为圆心如图所示．一束足够宽的平行光垂直射�玻璃砖的下表面光线到达上表面后 sketch template

如图半圆形玻璃砖置于光屏PQ的左下方一束白光沿半径方�从A点射入玻璃砖在O点�生反射和折射折射光在光屏上�七色光带ab是其中的两单 sketch template

如图所示半径R=10cm的半圆形玻璃砖放在水平桌面上O1为圆心O2为圆弧顶点P1P2面与桌面平行现让一很细的激光束垂直P1P2面射入 sketch template

一束红光从AO射进半圆玻璃砖的表面如图所示．1在图中画出光在玻璃砖上表面的反射光并标出反射角r且∠r的大小等于60°．2在图中标 sketch template

欲测一块半圆形玻璃砖折射率实验装置如图所示的主要步骤如下A．将半圆形玻璃砖放在白纸上用铅笔画出它的直径AB移走玻璃砖并且刻度尺找出 sketch template

如图所示一玻璃砖的横截面为半圆形MN为截面的直径Q是MN上的一点且与M点的距离R为半圆形截面的半径一束与截面平行的白光由Q点沿 sketch template

如图所示为一半圆形的玻璃砖C为AB的中点ab两束不同�率的单色可见细光束垂直AB边从空气射入玻璃砖且两束光在AB面上入射点到C点的距离 sketch template

8分一半径为R的半圆形玻璃砖横截面如图所示。已知玻璃的全反射临界角rr 百度教育 sketch template

如图所示两束不同的单色光P和Q以适当的角度射�半圆形的玻璃砖然后均由O点沿OF方�射出则下列说法中正确的是 A．P在真空中的波长比Q sketch template

如图19 4 10两束不同的光A和B分别沿半径方�射入半圆形玻璃砖出射光都是OP方�下面正确的是 AA穿过玻璃砖所需的时间较长B光由 sketch template

10．一束红光与一束紫光以适当的入射角射�半圆形玻璃砖其出射光线都是由圆心O点沿OP方�射出如图所示则 A．AO是红光它穿过玻璃砖所需 sketch template

如图所示半圆形玻璃砖置于光屏PQ的左下方一束白光沿半径方�从A点射入玻璃砖在O点�生反射和折射折射光在光屏上�现七色光带若入射点由A sketch template

如图所示两束单色光AB分别沿半径方�由空气射入半圆形玻璃砖出射光合成一束复光P下列说法正确的是 A．A光的�率大于B光的�率B．在玻璃 sketch template

如图所示是一透明的圆柱体的横截面其半径R=20 Cm折射率为AB是一条直径今有一束平行光沿AB方�射�圆柱体试求1光在圆柱体中 sketch template

如图所示一玻璃柱体的横截面为半圆形让太阳光或白炽灯光通过狭缝S形成细光束从空气射�柱体的O点产生反射光束1和透射光束2．现保持入射光不变 sketch template

半圆柱形玻璃砖截面如图所示O为圆心已知光线从a处进入玻璃砖后在O点恰好�生全反射 1试计算这块玻璃砖的折射率 2如果另一条从 sketch template

如图所示有一细束红色光线和另一细束紫色光线沿不同的半径方�射入同一块半圆形玻璃砖其透射光线都是由圆心O点沿OC方�射出则下列判断正确的 sketch template

$如图所示一玻璃砖的横截面为半圆形MN为截面的直径Q是MN上的一点且与M点的距离QM=$frac{R}{2}$．MN与水平光屏P平行 sketch template$

如图所示cde半圆形玻璃砖O为圆心一束很细的复色光沿fO方�从O点射入玻璃砖 经半圆形玻璃砖折射后照射到右边的光屏上形成ab两束光 sketch template

一半径为R的半圆柱形玻璃砖横截面如图所示．已知玻璃的全反射临界角为γ．与玻璃砖的底平面成角度且与玻璃砖横截面平行的平行光射到玻璃砖的半圆柱 sketch template

一块半圆形玻璃砖放在空气中如图所示一束白光沿通过圆心O的方�射�玻璃砖经玻璃砖折射后在光屏P上形成由红到紫的彩色光带若逐渐减小α彩色 sketch template

2．如图所示红光和紫光以不同的角度沿半径方�射�半圆形玻璃砖的圆心O它们的出射光线都是沿OP方�则下列说法中正确的是 A．AO是红光 sketch template

11．如图所示在白纸上画一直线CD在CD上取一点O过O点画一垂线OE垂直CD放上半圆形玻璃砖使其直径与直线CD重合圆心与O点重合在 sketch template

高考物理光学试题真题赏析知乎 sketch template

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