7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Sketch Coloring Page

7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Template

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sketch #2029 GOD 'S PROMISE ...

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tomski7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— coloring

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

14．如图点DEF分别是 ABC三边上的中点．若 ABC 的面积为12则 DEF的面积为．——青夏教育精英家教�—— sketch template

20．如图点DEF分别在ABBCAC上且DE∥ACEF∥AB下面写出了说明“∠A ∠B ∠C＝180° 的过程请填空因为 sketch template

如图在平行四边形ABCD中AB=6BC=4∠B=60°点E是边AB上的一点点F是边CD上一点将平行四边形ABCD沿EF折叠得到 sketch template

如图在等边 ABC 中DEF分别为ABBCCA上一点且AD=BE=CF若每三个三角形两两全等为一组则图中全等的三角形组数为 sketch template

23． 如图 ABC中点DE分别在边ABAC上连接DE并延长交BC的延长线于点F连接DCBE．若∠BDE ∠BCE=180 sketch template

【问题情境�（1）如图1，正方形ABCD中，E、F分别是边AB和对角线AC上的点，∠EDF=45°．易证 DBE∽ DCF（不需写出证明过程 sketch template

$如图在 ABC中点D是AB的中点连接CDCD=BDtan∠CDB=$frac{24}{7}$在BC上取一点F使BF sketch template$

【方法引领�如图1，点E、F分别是正方形ABCD的BC、CD边上的动点，连接AE、AF和EF，∠EAF=45°．若BE=2，DF=3，求EF的 sketch template

如图点DE分别在 ABC的边上ABAC上且若DE=3BC=6AB=8则AE的长为——青夏教育精英家教�—— sketch template

初中生都能看懂的九点共圆的证明知乎 sketch template

题目如图已知正方形ABCD的边长为6EF分别是ABBC边上的点且∠EDF=45°将 DAE绕点D逆时针旋转90°得到 DCM sketch template

题目如图矩形ABCD中AD=5AB=7点E为DC上一个动点把 ADE沿AE折叠当点D的对应点D′落在∠ABC的角平分线上时DE sketch template

如图点DE分别是 ABC的边ABAC的中点若DE=6则BC=12．题目和参考答案——青夏教育精英家教�—— sketch template

如图在 ABC中点DEF分别在BCABAC上且DE∥ACDF∥AB．1如果∠BAC=90°那么四边形AEDF是 形2 sketch template

矩形ABCD中，AB= 3 ，BC= 4．点E，F在对角线AC上，点M，N分别在边AD，BC上．1如图1，若AE=CF=1，M，N分别是 sketch template

题目如图圆内接四边形ABCD两组对边的延长线分别相交于点EF且∠A=55°∠E=30°则∠F= ．答案40°解析试题分析 sketch template

20．28 如图EF分别是矩形ABCD的对角线AC和BD上的点且AE=DF求证BE=CF 答案证明∵四边形ABCD为矩形 sketch template

如图在 ABC中CE是中线CD是角平分线AF⊥CD交CD延长线于点FAC=7BC=4则EF的长为 A 15 B 2 sketch template

如图，AB为⊙O的直径，C、D为⊙O上的两点，且AC平分∠BAD，过点C作直线EF⊥AD，交AD的延长线于点E． sketch template

如图点EF分别是菱形ABCD的边BCCD上的点且 ∠EAF=∠D=60°∠FAD=45°则∠CFE= A60B45C sketch template

如图点EF分别是菱形ABCD的边BCCD上的点且 ∠EAF=∠D=60°∠FAD=45°则∠CFE= A60B45C sketch template

例1如图所示空间四边形ABCD中EFG分别在ABBCCD上且满足AE∶EB=CF∶FB=2∶1 CG∶GD=3∶1过EF sketch template

题目如图�所示将直尺�放在三角板上使直尺与三角板的边分别交于点DEFG已知∠CGD=42°1求∠CEF的度数2将直尺 sketch template

如图等边三角形ABC中DE分别为ABBC边上的两动点且总使AD=BEAE与CD交于点FAG⊥CD于点G则FGAF= A sketch template

3分爱动�筋的小亮同学设计了一种“幻圆”游戏将﹣1、2、﹣3、4、﹣5、6、﹣7、8分别填入图中的圆圈内使横、竖以及内外两圈上的4个 sketch template

如图在 ABC中正方形EDCF的三个顶点EDF都在三角形的边长另一个顶点C与三角形的顶点重合且AC=4BC=6求ED的长 sketch template

如图在 ABC中∠BAC=90°AB=AC点DE在BC上且∠DAE=45°若DE=$sqrt{15}$CD=$sqrt sketch template

如图等边 ABC中点D在AB上点E在BC上AD=BE．AE和CD相交于点P求证∠CPE=60°．题目和参考答案——青夏教育精英家教�—— sketch template

已知 ABC是边长为1的等边三角形点DE分别是边ABBC的中点连接DE并延长到点F使得DE=2EF则 sketch template

已知在 ABC中内切圆I和边BCCAAB分别相切于点DEF．1若∠A=60°求∠FDE的度数2若∠A=130°求∠ sketch template

如图平面直角坐标系中在边长为1的正方形的边上有一动点沿运动一�则的纵坐标与点走过的路程之间的函数关系用图象表示大致是 题目和参考答案 sketch template

如图点DE分别在 ABC的边上ABAC上且若DE=3BC=6AB=8则AE的长为——青夏教育精英家教�—— sketch template

如图1图2 ABC是等边三角形DE分别是ABBC边上的两个动点始终保持BD=CE．1当点DE运动到如图1所示的位置时求证 sketch template

如图在矩形纸片ABCD中已知AB=1BC=$sqrt{3}$点E在边CD上移动连接AE将多边形ABCE沿直线AE翻折得到多边形 sketch template

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