已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若e是pd Sketch Coloring Page

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若e是pd Template

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tomski已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 coloring

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

四棱锥图片直观图三棱锥和四棱锥图片四棱锥图片素描图片大山谷图库 sketch template

四棱锥的直观图正四棱锥的直观图画正四棱锥直观图第2页大山谷图库 sketch template

7．一个四棱锥的底面为正方形其三视图如图所示则这个四棱锥的体积是 A． B． C． D．——青夏教育精英家教�—— sketch template

百度教育 sketch template

如图所示正四棱锥P ABCD的各棱长均为13MN分别为PABD上的点且PM∶MA=BN∶ND=5∶8 1求证直线MN∥平面 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

如图，已知四棱锥中，平面，，，是边长为的正三角形，高途 sketch template

四棱锥的侧视图四棱锥的三视图正视图侧视图俯视图第7页大山谷图库 sketch template

如图所示侧面是全等的等腰三角形的棱锥是 A正棱锥 B侧棱长相等的棱锥C斜高长相等的棱锥 D以上均不对题目和参考答案——青夏教育精英 sketch template

如图1由正四棱锥P ABCD和正四棱柱ABCD A1B1C1D1所组成的几何体的三视图如图2．1求证PC⊥平面A1BD2求点P到 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

一个三棱锥的三视图如图所示则该三棱锥的体积是 A4 B C D8——青夏教育精英家教�—— sketch template

4．如图已知四边形ABCD是平行四边形点P是平面 ABCD外的一点则在四棱锥P ABCD中M是PC 的中点在DM上取一点G过G和 sketch template

如图所示四棱锥P ABCD的底面ABCD是边长为a的正方形侧棱PA=a PB=PD=a则它的5个面中互相垂直的面有对——青夏教育 sketch template

如图已知四棱锥S ABCD的底面是直角梯形AB∥DC∠DAB=90°SA⊥底面ABCD且SA=AD=DC=12AB=1M是SB的中点 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

三棱锥及其侧视图、俯视图如图所示设，分别为线段，的中点，为线段上的点，且（1）证明：为线段的中点；（2）求二面角的余弦值 – 新东方在线�络课堂 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

人教A版高中数学必修二《81 基本立体图形》优质课公开课课件、教案知乎 sketch template

9．如图已知正四棱锥S ABCD的侧棱长为底面边长为E是SA的中点则异面直线BE与SC所成角的大小是 A．90° B．60° C．45 sketch template

已知正四棱锥的底边和侧棱长均为32则该正四棱锥的外接球的表面积为．题目和参考答案——青夏教育精英家教�—— sketch template

如图已知在四棱锥P ABCD中底面ABCD是边长为4的正方形 PAD是正三角形EFG分别是PDPCBC的中点．1求证直线 sketch template

如图正四棱锥S ABCD的所有棱长都相等过底面对角线 AC作平行于侧棱SB的截面交SD于E 1求AB与SC所成角的大小 2求 sketch template

19．如图所示四棱锥P ABCD中底面ABCD为直角梯形点E在棱PA上且PE=2EA 1 求异面直线PA与CD所成的角 2 sketch template

如图在四棱锥P ABCD中PA⊥平面ABCD底面ABCD为平行四边形且AB=1BC=2EF分别为ADBC的中点．I求证 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图已知两个正四棱锥P ABCD与Q ABCD的高分别为1和2AB=4 � 证明PQ⊥平面ABCD � 求异面直线AQ与PB所成的角 sketch template

已知，如图四棱锥中，，为平行四边形，，平面，，分别高途 sketch template

已知四棱锥P ABCD的正视图是一个底边长为4腰长为3的等腰三角形如图分别是四棱锥P ABCD的侧视图和俯视图．1求证AD⊥PC sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图所示在三棱锥P ABC中PA⊥平面ABC E为AC的中点 1求异面直线BE与PC所成角的余弦值 2求二面角P BE C sketch template

如图所示正四棱锥，，，为侧棱上的点，且．高途 sketch template

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