如图，rt Abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 Ade沿de折叠，点a恰好落在bc上的点f处，若点f为 Sketch Coloring Page

如图，rt Abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 Ade沿de折叠，点a恰好落在bc上的点f处，若点f为 Template

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anonymous

anonymous
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anonymous

anonymous
sketch #4948 Snow White by George Lucaz

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anonymous

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sketch #5258 Adventure Time by Kheith Ryan Lubiano

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anonymous

anonymous
sketch #3506 Goku by Saul Mansanares

sketch #4493 Jimi Hendrix by Alex Stoun

anonymous

anonymous
sketch #4493 Jimi Hendrix by Alex Stoun

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anonymous

anonymous
sketch #2901 Smurf by Ronny Alexander Nikolaevich

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sketch #4997 Rafael Leite Jose Rondon

anonymous

anonymous
sketch #4997 Rafael Leite Jose Rondon

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anonymous

anonymous
sketch #5086 Lion by Z Ionut Ady

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anonymous

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sketchmaster
sketch #2486 Face by sketchmaster

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anonymous

anonymous
sketch #3455 Enya by Georai Shahar

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anonymous

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anonymous

anonymous
sketch #3575 Stitch by Laura Gutierrez Hinojosa

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anonymous

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sketch #5218 Marshall Lee Dj-ionut Manelomania

anonymous

anonymous
sketch #5218 Marshall Lee Dj-ionut Manelomania

sketch #5272

anonymous

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sketch #5272

tomski如图，rt abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 ade沿de折叠，点a恰好落在bc上的点f处，若点f为 coloring

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

题目如图Rt ABC中∠BAC=90°AB=3AC=6点DE分别是边BCAC上的动点则DA DE的最小值为 ．题目和参考 sketch template

如图，在 ABC中，∠ABC＝90°，AB＝BC，三角形的顶点在相互平行的三条直线l1，l2，l3上，且l1，l2的距离为2，l2，l3的距离 sketch template

如图在Rt ABC中∠BAC=90°AB=AC分别过点BC坐过点A的直线的垂线BDCE若BD=4CE=3则DE=A1B sketch template

如图，已知在Rt ABC中，∠ACB=90°，AC=BC=4，点D为边BC上一动点（与点B、C不重合），点E为AB上一点，∠EDB=∠ADC sketch template

如图，Rt ABC中，∠ACB=90°，AC=BC，点D为AB边上的一个动点（不与点A，B及AB中点重合），连接CD，点A关于直线CD的对称点 sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

如图Rt ABC中∠C=90°O为AB上一点以O为圆心OB长为半径的圆交BC边于点D与AC边相切于点E．1求证BE平分∠ sketch template

如图，在Rt ABC中，∠ABC=90°，AB=3，BC=4，在Rt MPN中，∠MPN=90°，点P在AC上，PM交AB于点E，PN交BC于 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

如图在Rt ABC中∠ACB=90°AC=BC点D是AB的中点将一块直角三角形板的直角顶点放在点D处旋转两直角边分别交AC于点E sketch template

如图在Rt ABC 中∠C=90°AC=BCAB=8点D为AB的中点若直角MDN绕点D旋转分别交AC于点E交BC于点M则下列 sketch template

如图，在Rt ABC中，∠ ACB=90°，∠ ABC=30°，AC=2，点P是边AB上的一动点 ABC≌ ABC，将 A sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠C=90°AC=6BC=8点F在边AC上并且CF=2点E为边BC上的动点将 CEF沿直线EF翻折点C落 sketch template

如图在Rt ABC中∠B=90°BC=6∠C=30°点D从点C出�沿CA方�以每秒2个单位长的速度�点A匀速运动同时点E从点A出� sketch template

题目如图 在Rt ABC中∠ACB＝90°AC＝6BC＝8将边AC沿CE翻折使点A落在AB上的点D处再将边BC沿CF翻折使 sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

如图Rt ABC中∠ACB=90°∠B=30°AC=2将 ABC绕点C逆时针旋转至 A′B′C使得点A′恰好落在AB上A′B′与 sketch template

如图3在Rt ABC中∠C=90°CA=CB=2分别以ABC为圆心以AC为半径画弧三条弧与边AB所围成的阴影部分的面积是 sketch template

在Rt ABC中∠C=90°AB的垂直平分线交BC边于D∠B=2∠DAC则∠B的度数为 A．18°B．54°C．36°D．72 sketch template

如图在Rt ABC中∠ACB=90°∠A=60°AC=1将 ABC绕点C顺时针旋转得 A1B1C1且点A1落在边AB边上取BB1 sketch template

如图Rt ABC中∠BAC=90°以AB为直径作⊙O交BC于点DOE∥BC交AC于点E连接AD交OE于点F连接DE．1判断 sketch template

如图在Rt ABC中∠C=90°∠BAC的角平分线AD交BC于点D若AC=5BC=12．求点D到AB的距离．题目和参考答案——青夏 sketch template

如图．在Rt ABC中．∠ACB=90°．∠ABC=30°AB=6．点D是BC边上一动点连接AD．将 ACD沿AD折叠．点C落在点C1处 sketch template

如图在Rt ABC中∠BAC=90°∠C=30°以边AC上一点O为圆心OA为半径作圆恰好经过边BC的中点D并与边AC相交于另一点 sketch template

如图Rt ABC中∠ABC=90°BA=BC=2分别过AC作平面ABC的垂线AA′和CC′AA′=h1CC′=h2且h1＞h2 sketch template

如图在Rt ABC中∠ACB=90°∠A=30°点O为AB中点点P为直线BC上的动点连接OCOP将线段OP绕点P顺时针旋转60 sketch template

百度教育 sketch template

如图Rt ABC中∠D=90°∠B=45°∠ACD=60°BC=10cm求AD的长．题目和参考答案——青夏教育精英家教�—— sketch template

在Rt ABC中∠ACB等于90°∠ABC等于30°AC=1将 ABC绕点A逆时针旋转至 AB′C′使得点AC′恰好落在斜边AB上 sketch template

如图在等腰Rt ABC中∠BAC=90°BC=2点E为线段AB上任意一点以CE为斜边作等腰Rt CDE连接AD下列结论�∠ sketch template

Rt ABC中∠C=90°若sinA和sinB是方程x2 2x K=0的两个根则k= ．题目和参考答案——青夏教育精英家教�—— sketch template

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