如图，rt abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 ade沿de折叠，点a恰好落在bc上的点f处，若点f为 Sketch Coloring Page

如图，rt abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 ade沿de折叠，点a恰好落在bc上的点f处，若点f为 Template

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More Sketches

Take a peek at some of the sketches created by our users, are you a sketchite?

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anonymous

anonymous
sketch #3670 Bugs Bunny by Jessica Column

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anonymous
sketch #5138 Monster by Leonie Cooper

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anonymous

anonymous
sketch #1418 Dylan Thomas. Chayrolfrypan

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anonymous
sketch #3662 Angel by Alexander Volodimirovich Danilchenko

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sketch #3749 Girl Ari Rainbow

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sketch #3897 dolphins playing over the sea

Rachel Christa Ibarrientos
sketch #3897 dolphins playing over the sea

sketch #3058 Marilyn Monroe by Adam Pyszny

anonymous

anonymous
sketch #3058 Marilyn Monroe by Adam Pyszny

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sketch #2770 Maggie by Shuvo Islam

Shuvo Islam
sketch #2770 Maggie by Shuvo Islam

sketch #4907

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tomski如图，rt abc中，∠c＝90°，ac＝bc，点d、e分别是边ab、ac上的点，把 ade沿de折叠，点a恰好落在bc上的点f处，若点f为 coloring

如图Rt ABC纸片中∠C=90°AC=6BC=8点D在边BC 上以AD为折痕将 ABD折叠得到 AB′DAB′与边BC交于点E sketch template

题目如图等腰Rt ABC中∠ABC＝90°AB＝BC点AB分别在坐标轴上．1如图1若点C的横坐标为5直接写出点B的坐标 sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

如图，在Rt ABC中，∠ C=90°，点D在AB上，以AD为直径的⊙ O与BC相交于点E，与AC相交于点F，AE平分∠ BAC1求证 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图1将两个完全相同的三角形纸片ABC和DEC重合放置其中∠C=90°∠B=∠E=30° 1操作�现如图1固定 ABC使 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径作⊙O交AB于点DE为BC的中点连接DE并延长交AC的延长线于点F．1求证DE sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在等腰Rt ABC中∠BAC=90°BC=2点E为线段AB上任意一点以CE为斜边作等腰Rt CDE连接AD下列结论�∠ sketch template

如图，Rt ABC中，∠ACB=90°，AC=BC，点D为AB边上的一个动点（不与点A，B及AB中点重合），连接CD，点A关于直线CD的对称点 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

题目如图 ABC中∠ACB=90°AC=BC点E是AC上一点连接BE． 1如图1若AB=4 BE=5求AE的长2 sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

问题如图1在Rt ABC中∠C=90°⊙O是Rt ABC的内切圆切点分别是DEF若三角形三边长分别记为BC=aAC=bAB sketch template

如图在 ABC中D是BC边上一点∠1=∠B∠2=∠C∠BAC=63°求∠CAD的度数．题目和参考答案——青夏教育精英家教�—— sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

已知Rt ABC中∠ACB=90°AC=6BC=8 Word文档免费下载文档大全 sketch template

如图在Rt ABC中∠C=90°DE⊥ABAC=BE=15BC=20则四边形ACED的面积为 75 96——青夏教育精英家教�—— sketch template

如图Rt ABC中∠C=90°⊙O为 ABC的内切圆若AC=6BC=8求⊙O半径．题目和参考答案——青夏教育精英家教�—— sketch template

如图Rt ABC中∠C=90°⊙O为 ABC的内切圆若AC=6BC=8求⊙O半径．题目和参考答案——青夏教育精英家教�—— sketch template

如图Rt ABC中∠ABC=90°BA=BC=2分别过AC作平面ABC的垂线AA′和CC′AA′=h1CC′=h2且h1＞h2 sketch template

如图在Rt ABC中∠BAC=90°∠C=30°以边AC上一点O为圆心OA为半径作圆恰好经过边BC的中点D并与边AC相交于另一点 sketch template

题目在Rt ABC中∠C=90°BC=3AC=4点P在以C为圆心5为半径的圆上连结PAPB．若PB=4则PA的长为 sketch template

如图Rt ABC中∠C=90°O为AB上一点以O为圆心OB长为半径的圆交BC边于点D与AC边相切于点E．1求证BE平分∠ sketch template

如图在 ABC中∠C=90°AC=BCAD是角平分线DE⊥AB．垂足为E．求证BE=DE=CD．题目和参考答案——青夏教育精英家教�—— sketch template

如图在等腰Rt ABC中∠BAC=90°AB=ACBC=2$sqrt{2}$点D是AC边上一动点连接BD以AD为直径的圆交BD sketch template

如图在Rt ABC中∠C=90°AC=8BC=6点DE分别在边ABAC上将 ADE沿直线DE翻折点A的对应点在边AB上联结 sketch template

如图所示在Rt ABC中∠ABC＝90°．将Rt ABC绕点C顺时针方�旋转60°得到 DEC点E在AC上再将Rt ABC沿着AB所在 sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

Rt ABC中∠C=90°若sinA和sinB是方程x2 2x K=0的两个根则k= ．题目和参考答案——青夏教育精英家教�—— sketch template

如图在 ABC中AC=BC∠C=90°AD是 ABC的角平分线DE⊥AB垂足为E．1若CD=5求AC的长．2求证AB sketch template

$如图在Rt ABC中∠C=90°以顶点A为圆心适当长为半径画弧分别交ACAB于点MN再分别以点MN为圆心大于$frac sketch template$

如图．在Rt ABC中．∠ACB=90°．∠ABC=30°AB=6．点D是BC边上一动点连接AD．将 ACD沿AD折叠．点C落在点C1处 sketch template

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