在棱长为1的正方体上分别用过共顶点的三条棱中点的平面截该正方体则截去8个三棱锥后剩下的凸多面体的体积是 A B C D Sketch Coloring Page

在棱长为1的正方体上分别用过共顶点的三条棱中点的平面截该正方体则截去8个三棱锥后剩下的凸多面体的体积是 A B C D Template

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tomski在棱长为1的正方体上分别用过共顶点的三条棱中点的平面截该正方体则截去8个三棱锥后剩下的凸多面体的体积是 a b coloring

PPT 空间�量之应用 3 PowerPoint Presentation Free Download ID3685573 sketch template

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15．如图正方体ABCD A1B1C1D1的棱长为1点M在AB上且AM=AB点P在平面ABCD上且动点P到直线A1D1的距离的平方与 sketch template

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百度教育 sketch template

两相同的正四棱锥组成如图所示的几何体可放棱长为1的正方体内使正四棱锥的底面ABCD与正方体的某一个平面平行且各顶点均在正方体的面上则 sketch template

在棱长为1的正方体上分别用过共顶点的三条棱中点的平面截该正方体则截去8个三棱锥后剩下的凸多面体的体积是 A B C D sketch template

如图正方体的棱长为2试建立适当的空间直角坐标系写出正方体各顶点的坐标及各边中点的坐标．题目和参考答案——青夏教育精英家教�—— sketch template

正方体的棱长为1画过正方体AC1棱AA1B1C1A1B1上三个中点NLR的截面并求截面面积．题目和参考答案——青夏教育精英家教�—— sketch template

18．已知棱长为1的正方体AC1EF分别是B1C1C1D的中点． 1求证EFDB共面 2求点A1到平面的BDEF的距离 sketch template

如图1大正方体上截去一个小正方体后可得到图2的几何体．设原大正方体的表面积为S图2中几何体的表面积为S′那么S′与S的大小 sketch template

如图已知正方体ABCD A1B1C1D1的棱长为1EF分别在棱ABBC上G在对角线BD1上且AE＝BF＝D1G∶GB＝1∶2 sketch template

如图在一个棱长为20cm的正方体密闭容器的下底固定了一个实心的小长方体容器内盛有mL水时水面恰好经过小长方体的上底面。如果将容器倒置小 sketch template

长方体和正方体的体积长方体和正方体的体积资料新学语文� sketch template

如图，在棱长为a的正方体ABCD A1B1C1D1中，P、Q分别是AD1、BD的中点．（1）求证：PQ∥平面DCC1D1．（2）求证：平面 sketch template

如图所示在一个木制的棱长为3的正方体表面涂上颜色将它的棱三等分然后从每个等分点把正方体锯开得到27棱长为1的小正方体将这些小正方体 sketch template

两个相同的正四棱锥底面重合组成一个八面体可放于棱长为1的正方体中重合的底面与正方体的某一个面平行各顶点均在正方体的表面上把满足上述条件 sketch template

如图是由若干个完全相同的小正方体堆成的几何体，请你画出这个几何体的三种视图． sketch template

用大小相同的小正方体搭成的一个几何体从正面左面上面看都是“田字则最�用66个小正方体．题目和参考答案——青夏教育精英家教�—— sketch template

在棱长为2的正方体ABCD A1B1C1D1中正方形BCC1B1所在平面内的动点P到直线D1C1DC的距离之和为22∠CPC1=60°则 sketch template

百度教育 sketch template

已知正方体棱长为2，以正方体的一个顶点为球心，以2√2为半径作球面，则该球面被正方体表面所截得的所有的弧长和为 百度教育 sketch template

如图1大正方体上截去一个小正方体后可得到图2的几何体．1设原大正方体的表面积为S图2中几何体的表面积为S′那么S′与S的大小关系是 sketch template

如图所示在正方体ABCD A1B1C1D1中棱长为aMN分别为A1B和AC上的点A1M=AN=则MN与平面BB1C1C的位置关系是 sketch template

有一个棱长为20厘米的大正方体在它的每个顶点处按图所示的方法各作一个小正方体图中表示的是在一个顶点处作小正方体的方法于是得到8个小正方 sketch template

正方体ABCD A1B1C1D1的棱长为1点PQR分别是棱A1AA1B1A1D1的中点以 PQR为底面作正三棱柱若此三棱柱另一底 sketch template

如图所示一个棱长为5厘米的正方体分别在它的前后左右上下各面的中心挖一个横截面是边长为2厘米的正方形的长方体．求这物体的表面积 sketch template

棱长为a的正方体ABCD A1B1C1D1中AB的中点为MDD1的中点为N则异面直线A1M与C1N所成角的大小为 A30° B45 sketch template

在棱长为a的正方体ABCD A1B1C1D1中 O1O2分别为正方形AB B1A1 BCC1B1的中心则四棱锥B1 A1O1O2C1的 sketch template

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