7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Sketch Coloring Page

7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Template

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tomski7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— coloring

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

平面几何定理及证明（1）知乎 sketch template

小明遇到一个问题如图1正方形ABCD中EFGH分别是ABBCCD和DA边上靠�ABCD的n等分点连接AFBGCH sketch template

如图在 ABC中点DEF分别在边ABACBC上且DE∥BCEF∥AB若AD＝2BD则的值为 A B C D sketch template

如图在正方形ABCD中点EF分别是ADBC中点连接EF将矩形CDEF绕着点C逆时针旋转一定角度得到矩形CD′E′F′点E′恰好落 sketch template

题目如图在ABCD中EF分别为边ADBC的中点对角线AC分别交BEDF于点GH．求证AG=CH．题目和参考答案——青夏 sketch template

如图1，D、E、F分别是 ABC各边上的点，四边形ADEF是平行四边形，有三个选项：�D是AB的中点，�E是BC的中点，�F是AC的中点． sketch template

如图 ABC中点DEF分别在边BCABCA上且DE∥CADF∥BA则�如果∠BAC=90°那么四边形AEDF是矩形�如果 sketch template

14．如图点DEF分别是 ABC三边上的中点．若 ABC 的面积为12则 DEF的面积为．——青夏教育精英家教�—— sketch template

题目如图已知正方形ABCD的边长为6EF分别是ABBC边上的点且∠EDF=45°将 DAE绕点D逆时针旋转90°得到 DCM sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图所示在等边 ABC中点DE分别在边BCAB上且BD=AEAD与CE交于点F则∠DFC的度数为 A．60°B．45°C sketch template

如图1在 ABC中DEF分别为三边的中点G点在边AB上 BDG与四边形ACDG的�长相等设BC=aAC=bAB=c．1求 sketch template

在 ABC中已知∠A=60°∠C=75°AB=10点DEF分别在边ABBCCA上则 DEF�长的最小值．题目和参考答案 sketch template

20．如图点DEF分别在ABBCAC上且DE∥ACEF∥AB下面写出了说明“∠A ∠B ∠C＝180° 的过程请填空因为 sketch template

题目如图所示 ABC是直角三角形∠A=90°D是斜边BC的中点EF分别是ABAC边上的动点且DE⊥DF．1如图1AB sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图 ABC中DEF分别足BCCAAB边上的点BDDC=12CEEA=13AFFB=11ADBECF围成 sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

如图在 ABC中∠A=90°AB=ACD 是BC的中点点EF分别是ABAC上的点并且BE=AF1猜想并写出AD与BC所满足 sketch template

如图已知长方体ABCD A1B1C1D1中AB=BC=2AA1=1点EF分别是A1B1B1C1的中点点O是AB与BD的交点．1 sketch template

如图 ABC是等腰三角形∠C=90°D是AB的中点点EF分别在ACBC边上运动且保持AE=CF连接DEDFEF．在此运动 sketch template

题目如图AB=4cmAC=BD=3cm．∠CAB=∠DBA=60°点P在线段AB上以1cm/s的速度由点A�点B运动同时点Q在线 sketch template

如图在 ABC中点DEF分别在BCABAC上且DE∥ACDF∥AB．1如果∠BAC=90°那么四边形AEDF是 形2 sketch template

如图点EF分别是菱形ABCD的边BCCD上的点且 ∠EAF=∠D=60°∠FAD=45°则∠CFE= A60B45C sketch template

题目如图在 ABC中E是BC上的一点EC=2BE点D是AC的中点设 ABC ADF BEF的面积分别为S S sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

在正方形ABCD中动点EF分别从DC两点同时出�以相同的速度在直线DCCB上移动．1如图�当点E自D�C点F自C�B移动时 sketch template

如图�，已知 ABC的内切圆⊙O与AB、BC、AC分别相切于点D、E、F，且EF=DE（1）判断 ABC的形状，并证明你的结论；（2 sketch template

如图点EF分别是菱形ABCD的边BCCD上的点且 ∠EAF=∠D=60°∠FAD=45°则∠CFE= A60B45C sketch template

如图在等腰直角三角形ABC中∠ACB=90°AC=BC=4D是AB的中点EF分别是ACBC上的点且AE=CF连接EF并取EF sketch template

如图点DEFB在同一直线上AB∥CDAE∥CF且AE=CF若BD=10BF=2则EF= ——青夏教育精英家教�—— sketch template

如图点DEF分别在等边三角形ABC的边ABBCCA的延长线上且BD=CE=AF说明 DEF为等边三角形．题目和参考答案——青夏 sketch template

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