2．如图所示红光和紫光以不同的角度沿半径方�射�半圆形玻璃砖的圆心o它们的出射光线都是沿op方�则下列说法中正确的是 A．ao是红光 Sketch Coloring Page

2．如图所示红光和紫光以不同的角度沿半径方�射�半圆形玻璃砖的圆心o它们的出射光线都是沿op方�则下列说法中正确的是 A．ao是红光 Template

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tomski2．如图所示红光和紫光以不同的角度沿半径方�射�半圆形玻璃砖的圆心o它们的出射光线都是沿op方�则下列说法中正确的是 a．ao是红光 coloring

2．如图所示红光和紫光以不同的角度沿半径方�射�半圆形玻璃砖的圆心O它们的出射光线都是沿OP方�则下列说法中正确的是 A．AO是红光 sketch template

2．如图所示红光和紫光以不同的角度沿半径方�射�半圆形玻璃砖的圆心O它们的出射光线都是沿OP方�则下列说法中正确的是 A．AO是红光 sketch template

9．如图所示一束红光和一束紫光平行入射到三棱镜上经棱镜折射后交汇在屏上同一点．若三棱镜对红光和紫光的折射率分别为n1和n2． 则有 sketch template

如图所示两束平行的红光和紫光相距为d斜射到玻璃砖上当它们从玻璃砖的下面射出时A两条出射光线仍平行但距离大于dB两条出射光线仍平行 sketch template

9．如图所示一束红光和一束紫光平行入射到三棱镜上经棱镜折射后交汇在屏上同一点．若三棱镜对红光和紫光的折射率分别为n1和n2． 则有 sketch template

高中物理《光的的颜色色散》知识总结知乎 sketch template

如图19 7 3所示一束红光和一束紫光平行入射到三棱镜上经棱镜折射后交汇在屏上同一点若三棱镜对红光和紫光的折射率分别为n1和n2则有 sketch template

如图所示一条红色光线和另一条紫色光线以不同的角度同时沿不同的半径方�射入同一块半圆形玻璃砖其透射光线都是由圆心O点沿OC方�射出．则可知 sketch template

如图所示一束白光通过玻璃棱镜�生色散现象下列说法正确的是 A．红光的偏折最大紫光的偏折最小 B．红光的偏折最小紫光的偏折最大 C sketch template

第5节光的色散 Word文档在线阅读与下载免费文档 sketch template

一束红光与一束紫光以适当的入射角射�半圆形玻璃砖其出射光线都是由圆心O点沿OP方�射出如图所示则 A．AO是红光它穿过玻璃砖所需 sketch template

4分如图所示由紫光与红光混合的细光束从底面镀银的半圆形玻璃砖顶点A以入射角θ=60°射入玻璃砖已知该玻璃砖对紫光与红光的折射率分别为 sketch template

如图所示只含红光和紫光的复色光束PO沿半径方�射入空气中的玻璃半圆柱后如果被分成OAOBOC三光束沿图示方�射出则 A．OA为 sketch template

如图所示OBCD为半圆柱体玻璃的横截面OD为直径一束由红光和紫光组成的复色光沿AO方�从真空斜射入玻璃BC点为两单色光的射出点设 sketch template

如图所示F1和F2分别是下列两种不同色光的焦点其中紫光的偏折能力比红光强请做出两种色光经凸透镜折射后的光路图．题目和参考答案——青夏 sketch template

如图所示冬冬在探究光的色散现象时看到白光经三棱镜后光屏上自上而下出现了红橙黄绿蓝靛紫的色带这说明白光单纯颜色的光冬冬 sketch template

如图所示用只含红光和绿光的一束光沿透明半圆形玻璃砖的半径射到直平面上．已知在该种玻璃中红光的折射率小于绿光的折射率入射光线与MN的夹角为 sketch template

如图所示一束白光经三棱镜折射后在光屏上形成自上而下为红橙黄绿蓝靛紫的色带这就是光的 现象．1分析实验现象可知�白光是 sketch template

如图所示一束红光和一束蓝光平行入射到三棱镜上经棱镜折射后交在屏上同一点若n1和n2分别表示三棱镜对红光和蓝光的折射率则有 A．n1 sketch template

如图所示为某种透明介质的截面图 AOC为等腰直角三角形OBC为半径R=10cm的四分之一圆弧AB与水平屏幕MN垂直并接触于A点由红光和 sketch template

如图所示一束白光经三棱镜折射后在光屏上形成自上而下为红橙黄绿蓝靛紫的色带这就是光的 现象．1分析实验现象可知�白光是 sketch template

如图所示OBCD为半圆柱体玻璃的横截面OD为直径一束由红光和紫光组成的复色光沿AO方�从真空斜射入玻璃BC点为两单色光的射出点设 sketch template

如图所示两束平行的红光和紫光相距为d斜射到玻璃砖上当它们从玻璃砖的下面射出时A两条出射光线仍平行但距离大于dB两条出射光线仍平行 sketch template

24．12分如图所示，绝缘光�轨道ABCD竖直放在与水平方�成θ＝45°的匀强电场中，其中BCD部分是半径为R的半圆环，轨道的水平部分与 sketch template

半径为R的玻璃半圆柱体横截面如图所示圆心为O两条平行单色红光沿截面射�圆柱面方�与底面垂直光线1的入射点A为圆柱面的顶点光线2的 sketch template

如图所示一束白光以较大的入射角射到三棱镜的一侧面上从三棱镜的另一侧面射出在屏上形成从红到紫的彩色光带光入射角逐渐减小时 A红光 sketch template

如图所示两束平行的红光和紫光相距为d斜射到玻璃砖上当它们从玻璃砖的下面射出时A两条出射光线仍平行但距离大于dB两条出射光线仍平行 sketch template

如图所示两束平行的甲光和乙光相距为d斜射到置于空气中的矩形玻璃砖上若光线在玻璃砖内部重叠当它们从玻璃砖的下表面射出时 A．若甲为 sketch template

如图所示ab和c都是厚度均匀的平行玻璃板a和bb和c之间的夹角都为β一细光束由红光和蓝光组成以入射角θ从O点射入a板且射出c板后 sketch template

如图14 1 21所示一个三棱镜的顶角θ＝41°30′一束白光以较大的入射角i从棱镜左侧面射入从右侧面射出并在光屏P上形成由红到紫的 sketch template

如图所示c为一束含有红光紫光的复色光沿半径方�射入半圆形玻璃砖由圆心O点射出分为ab两束光下列说法正确的是 A．a束光是红光 sketch template

如图所示，两个同心的均匀带电球面，内球面半径为R1、带电荷Q1，外球面半径为R2、带电荷Q2 。设无穷远处为电势零点，则在两个球面之间、距离 sketch template

22．Ⅰ如图8所示入射光线AO射入半圆形玻璃砖的圆心O处经折射后射出玻璃砖在P处插一大头针正好挡住A点的象图中标出了相关的角度则玻璃 sketch template

一束白光通过如图所示的梯形玻璃砖在白墙上形成彩色光带下列说法正确的有 A墙面从上到下的依次是红橙黄绿蓝靛紫 B墙面从下到上的依次是红 sketch template

一轮复习：动态平衡问题解题技巧知乎 sketch template

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