19．如图所示abcd是倾角为θ的光�斜面已知abdcadbc均与ab垂直在斜面上的a点将甲球以速度v0沿ab方�射入的同时在 Sketch Coloring Page

19．如图所示abcd是倾角为θ的光�斜面已知abdcadbc均与ab垂直在斜面上的a点将甲球以速度v0沿ab方�射入的同时在 Template

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tomski19．如图所示abcd是倾角为θ的光�斜面已知abdcadbc均与ab垂直在斜面上的a点将甲球以速度v0沿ab方�射入的同时在 coloring

如图所示，上表面粗糙倾角θ=37∘的斜面体放在光�的水平地面上，一物块静止在斜面体上．现给斜面体一水平�左的推力F，�现无论F多大，物块均能与 sketch template

19．如图所示在水平倾角为θ的圆锥面边缘上放着一质量为m的物体它和轴 的距离为R若圆锥绕轴以角速度ω转动试求物体不致掉下所需的最小 sketch template

19．如图所示abcd是倾角为θ的光�斜面已知ab//dcadbc均与ab垂直在斜面上的a点将甲球以速度v0沿ab方�射入的同时在 sketch template

如图，矩形ABCD中，AB=2AD=2√2，E为边AB的中点，将 ADE沿直线DE翻折成 A 1DE在翻折过程中，直线A 1C与平面ABCD sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图所示，矩形平板ABCD的AD边固定在水平面上，平板与水平面夹角为θ，AC与AB的夹角也为θ。质量为m的物块在平行于平板的拉力作用下，沿AC sketch template

如图所示，矩形平板ABCD的AD边固定在水平面上，平板与水平面夹角为θ，AC与AB的夹角也为θ。质量为m的物块在平行于平板的拉力作用下，沿AC sketch template

题目如图甲所示间距为L=05m的两条平行�属导轨ABCD和A′B′C′D′由倾斜部分与圆弧部分平�连接组成倾斜部分导轨的倾角θ=37 sketch template

如图所示AB是倾角θ为45°的直轨道CD是半径R=04m圆弧轨道它们通过一段曲面BC平�相接整个轨道处于竖直平面内且处处光�．一个 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图所示AB是倾角θ为45°的直轨道CD是半径R=04m圆弧轨道它们通过一段曲面BC平�相接整个轨道处于竖直平面内且处处光�．一个 sketch template

19． 如图所示PD垂直于正方形ABCD所在的平面AB =2 E是PB的中点与夹角的余弦值为 Ⅰ建立适当的坐标系写出点E的坐标 sketch template

如图所示AB为一倾角为θ=30°的斜面小球从A处以v0水平抛出落地点恰在B点已知斜面长为L=1m求 1平抛的初速度 2何时 sketch template

如图所示正方体ABCD A1B1C1D1中E是C1C的中点则BE与平面B1BD所成角的余弦值为 题目和参考答案——青夏教育精英家教�—— sketch template

如图所示地面上有一固定的斜面体ABCD其AB边的长度S=2m斜面倾角为37°．光�水平地面上有一块质量M=3Kg的足够长的木板紧挨着斜面 sketch template

19．如图所示质量为m的物体恰好能在倾角为α的斜面上匀速下�如在物体上施加一个力F使物体沿斜面匀速上�为了使得力F取最小值这个力与斜面 sketch template

如图所示相对的两个斜面倾角分别为37°和53°在顶点两个小球AB以同样大小的初速度分别�左�右水平抛出小球都落在斜面上若不计空气 sketch template

如图所示固定斜面倾角为整个斜面长分为ABBC两段AB=2BC．小物块P与ABBC两段斜面间的动�擦因数分别为．已知P由静止开始从A sketch template

如图所示，凸四边形ABCD中，对角线AC、BD相交于0点．若三角形AOD的面积是2，三角形COD的面积是1，三角形COB的面积是4，则四边形 sketch template

如图所示在正方体ABCD A1B1C1D1中棱长为aMN分别为A1B和AC上的点A1M=AN=则MN与平面BB1C1C的位置关系是 sketch template

如图所示在一个很长的斜面上的某处A水平抛出一个物体已知物体抛出时的动能为15 J斜面的倾角θ＝30°空气阻力不计它落到斜面上B点 sketch template

如图所示小球ab的质量分别是2m和ma从倾角为30°的光�固定斜面的顶端无初速下�b从斜面等高处以初速度v0平抛比较ab落地的运动 sketch template

百度教育 sketch template

百度教育 sketch template

如图所示正方体ABCD A1B1C1D1中E是C1C的中点则BE与平面B1BD所成角的余弦值为 题目和参考答案——青夏教育精英家教�—— sketch template

如图所示在四边形ABCD中EFGH分别是四边形ABCD各边的中点已知阴影部分的面积是10求四边形SRPQ的面积．题目和参考答案 sketch template

如图所示ABCD是一条长轨道其中AB段是倾角为θ光�斜面A点离地高h=20mCD段是水平的物块与水平面间的动�擦因数为μ=04 sketch template

如图所示在平面直角坐标系中正方形ABCD的边长为4点B在系原点上 P是BC上一动点QP⊥AP交DC于Q设PB=x ADQ的面积为 sketch template

如图所示四棱锥P ABCD的底面ABCD是边长为a的正方形侧棱PA=a PB=PD=a则它的5个面中互相垂直的面有对——青夏教育 sketch template

15．如图所示倾角θ=30°的光�斜面固定在水平面上斜面高h=125 M．质量m=2kg的物体从斜面顶端出静止下�当下�至底端B点时 sketch template

3．如图所示质量为m的物体由静止开始从倾角分别为αβ的两个光�固定斜面上�下两斜面的高度均为h则下列叙述正确的是 A．物体�到 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

百度教育 sketch template

12．如图所示在四棱锥P ABCD中底面ABCD是矩形PA＝AB＝2BC＝a又侧棱PA⊥底面ABCD 1当a为何值时BD⊥ sketch template

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