11．如图正四面体a Bcd的棱长为a点ef分别是棱bdbc的中点则平面aef截该正四面体的内切球所得截面的面积为 A． B Sketch Coloring Page

11．如图正四面体a Bcd的棱长为a点ef分别是棱bdbc的中点则平面aef截该正四面体的内切球所得截面的面积为 A． B Template

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sketch #5114 Doraemon by Carrieann Benthem

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sketch #5114 Doraemon by Carrieann Benthem

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sketch #5018 Owl by Komlós László

sketch #4269 dragón

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sketch #4901 Adventure Time by Louisette Alain

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sketch #3367 Ichigo by Szymon Broszczak

sketch #4975 Orange by Marcos Roberto Molina

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sketch #4975 Orange by Marcos Roberto Molina

sketch #120 a pretty flower

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sketch #5265 Shir Erika Ishikawa

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sketch #5020 Stitch by Hina Ali

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sketch #5074

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sketch #5324 Angelina Jolie - Maleficent by Lucas Fajardo

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sketch #5324 Angelina Jolie - Maleficent by Lucas Fajardo

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Gaurav Patel
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sketch #1114 fire flame camping bonfire

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sketch #1114 fire flame camping bonfire

sketch #3448 Treba mi bolji

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sketch #3448 Treba mi bolji "mish " ;)

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sketch #2899 Snoopy by Rhemzkian Esturco

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sketch #2899 Snoopy by Rhemzkian Esturco

sketch #5069 Mad Hatter by Ahmed Mostafa

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sketch #5069 Mad Hatter by Ahmed Mostafa

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sketch #4446 EDDIE by يآآسر محمد

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sketch #4446 EDDIE by يآآسر محمد

sketch #4774 Banksy&#;s Wall and Piece by Ameli Cedeño Barcia

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sketch #4774 Banksy&#;s Wall and Piece by Ameli Cedeño Barcia

sketch #4682 Elvis Presley by Nassim Nouri

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sketch #4682 Elvis Presley by Nassim Nouri

tomski11．如图正四面体a bcd的棱长为a点ef分别是棱bdbc的中点则平面aef截该正四面体的内切球所得截面的面积为 a． coloring

深入浅出数学系列立体几何（3）：正四面体的性质知乎 sketch template

15．如图2正四面体ABCD的棱长为1H是顶点D的底面 ABC上的射影M在DH上且使得∠ABC=90°则DM的长 为 ——青夏教育 sketch template

如图，正四面体的长为1，， 则． sketch template

一个正四面体的各条棱长都是a那么这个正四面体的高百度经验 sketch template

正四面体ABCD棱长为2，E、F分别为BC、AD中点，则EF的长为 百度教育 sketch template

如图已知正四面体A BCD的棱长为1EF分别为棱ABCD的中点 1建立适当的空间直角坐标系写出顶点ABCD的坐标 2 sketch template

求棱长为a的正四面体的内切球、棱切球的半径百度教育 sketch template

已知正四面体ABCD的棱长为1求1该四面体的内切球的表面积2与该四面体各条棱均相切的球的体积3该四面体的外接球上AB两点间 sketch template

正四面体 中心到顶点距离为a，求四个顶点坐标百度知道 sketch template

任意四面体的外接球半径公式知乎 sketch template

15．如图2正四面体ABCD的棱长为1H是顶点D的底面 ABC上的射影M在DH上且使得∠ABC=90°则DM的长 为 ——青夏教育 sketch template

5．如图A BCD是一体积为的正四面体连结两个面的重心EF则线段EF的长是 ——青夏教育精英家教�—— sketch template

截角四面体是一种半正八面体可由四面体经过适当的截角即截去四面体的四个顶点所产生的多面体如图将棱长为3的正四面体沿棱的三等分点作平行于底 sketch template

由四个全等的等边三角形的封面几何体称为正四面体如图正四面体ABCD中EF分别是棱BCAD的中点CF与DE是一对异面直线在图形中 sketch template

7．如图正四面体的棱长均为且平面于A点BCD均在平面外且在平面同一侧则点B到平面的距离是 A． B． C． D．——青夏教育精英 sketch template

在棱长为a的正四面体中，相对两条棱间的距离为 百度教育 sketch template

11．如图正四面体A BCD的棱长为a点EF分别是棱BDBC的中点则平面AEF截该正四面体的内切球所得截面的面积为 A． B sketch template

已知菱形的边长为2，将沿折起，使得点至点的位置，得到四面体当二面角的大小为120°时，四面体的体积为；当四面体的体积为1时，以为球心，的长 sketch template

2．求棱长为a的正四面体外接球的半径．百度教育 sketch template

$如图已知正四面体D ABC所有棱长均相等的三棱锥PQR分别为ABBCCA上的点AP=PB$frac{BQ}{QC sketch template$

如图所示正四面体的棱长为aABCD是其四个顶点现在BD两点分别固定电荷量均为q的异种点电荷静电力常量为k下列说法正确的是 sketch template

求棱长为a的正四面体的外接球和内切球的半径解析如图作AH⊥底面BCD于H则AH＝a设内切球的球心为O半径为rO点与ABC sketch template

正四面体 360百� sketch template

如图是一个正四面体它的四个面都是正三角形现沿它的三条棱ACBCCD剪开展成平面图形则所得的展开图是 ——青夏教育精英家教�—— sketch template

求棱长为a的正四面体的外接球和内切球的半径解析如图作AH⊥底面BCD于H则AH＝a设内切球的球心为O半径为rO点与ABC sketch template

设四面体的各条棱长都为1若该四面体的各个顶点都在同一个球面上求该球的表面积．题目和参考答案——青夏教育精英家教�—— sketch template

两相同的正四棱锥组成如图所示的几何体可放棱长为1的正方体内使正四棱锥的底面ABCD与正方体的某一个平面平行且各顶点均在正方体的面上则 sketch template

本题满分12分如图在正四棱台中上底面边长为1下底面边长为3侧棱长为21求此正四棱台的侧面积2求此正四棱台的体积百度教育 sketch template

如图，已知正四面体的棱长为，，分别为棱，的中点．若高途 sketch template

如图，棱长为的正四面体中，，分别为棱，的中点，为线高途 sketch template

如图，已知正三棱柱ABC A 1B 1C 1的所有棱长都为2，D为CC 1中点，E为BC的中点（1）求证：BD⊥ 平面AB 1E；（2）求三 sketch template

1如图对于任一给定的四面体A1A2A3A4找出依次排列的四个相互平行的平面α1α2α3α4使得Ai∈αi且其中每相邻两个平面 sketch template

正三棱锥的高为1，底面边长为2√6，内有一个球与它的四个面都相切，求：三棱锥的表面积．内切球的半径．百度教育 sketch template

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA=PD=AD=2EF分别为PCBD的中点．Ⅰ sketch template

如图在斜棱柱ABC A1B1C1中底面为正三角形侧棱长等于底面边长且侧棱与底面所成的角为60°顶点B1在底面ABC上的射影O恰好是 sketch template

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