已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数 知乎 Sketch Coloring Page

已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数 知乎 Template

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tomski已知：在三角形abc中，ab=ac角bac=20度，d点在ab上且ad=bc求角acd的度数 知乎 coloring

已知在三角形abc中知识要点北京爱智康 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数 知乎 sketch template

【中考提升�初中数学平面几何压轴题6大模型及解题方法 知乎 sketch template

在三角形ABC中∠B＝60°BA＝24cmBC＝16cm现有动点P从点A出�沿射线AB�点B方�运动动点Q从点C出�沿射线CB sketch template

题目1操作如图在已知内角度数的三个三角形中请用直尺从某一顶点画一条线段把原三角形分割成两个等腰三角形并在图中标注相应的角的 sketch template

百度教育 sketch template

如图等腰三角形ABC中AB=AC顶角∠A=20°在边AB上取一点D使AD=BC求∠BDC的度数 题目和参考答案——青夏教育精英家教�—— sketch template

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百度教育 sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数．题目和参考答案——青夏 sketch template

已知在等边三角形ABC中DE分别为ABAC上的点且BD=AEEB与CD相交于点OEF⊥CD于点F．求证OE=2OF．题目和参考 sketch template

如图在 ABC中AB＞AC＞BCP为三角形内任意一点连接AP并延长交BC于D．求证1AB AC＞AD BC2AB AC sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

百度教育 sketch template

23．已知直角三角形ABC中∠C=90°D是AC上一点CD=CB AD=BD则∠A等于 28﹒5° 15——青夏教育精英家教�—— sketch template

19．在直角三角形ABC中∠ABC=90°以AB为直径作圆以BC为直径作圆以AC为直径作圆设圆的面积为圆的面积为圆的面积为若 sketch template

已知三角形ABC中AB≠AC求证∠B≠∠C要用反证法证明此�题第一步应假设——青夏教育精英家教�—— sketch template

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已知如图在等边三角形ABC中DE分别为BCAC上的点且AE＝CD连结ADBE交于点P作BQ⊥AD垂足为Q．求证BP sketch template

已知 ABC中AB=AC∠BAC=α DBC为等边三角形．1如图1∠ABD= 2如图2若∠BCE=150°∠ABE=60 sketch template

百度教育 sketch template

如图在不等边 ABC中AB＞ACAC≠BC过AC上一点D作一条直线使截得的三角形与原三角形相似这样的直线可作 A2条 B3条 sketch template

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已知，在三角形ABC中，CA=CB，已知点O是AB的中点，MN分别在直线ACBC上，角MON=角A=45度。百度知道 sketch template

在三角形ABC中点O是AC边上一个动点过点O作MN∥BC设MN交∠BCA的平分线于点E交 ABC的外角∠ACD平分线于点E．1求证 sketch template

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已知如图在 ABC中AB=AC点DEF分别在边BCBACA上且BE=CDBD=CF．求证点D在线段EF的垂直平分线上 sketch template

如图在三角形ABC中AB＞ACDE分别是ABAC上的点 ADE沿线段DE翻折使点A落在边BC上记为A′．若四边形ADA′E是 sketch template

如图 ABC中AB=AC．∠A=36°AB的中垂线DE交AC于D交AB于E下述结论AD=BD=BC3 BDC的�长等于AB sketch template

如图在 ABC中已知点DE分别在ABAC上BE与CD相交于点O依据下列各个选项中所列举的条件不能说明AB=AC的是 A．BE sketch template

连结三角形两边中点的线段叫做三角形的中位线如图�，在 ABC 中，D，E分别是AB，AC的中点，DE 就是 的一条中位线 �们可 sketch template

百度教育 sketch template

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