如图在四棱锥p abcd中pa⊥平面abcd底面abcd为平行四边形且ab=1bc=2ef分别为adbc的中点．i求证 Sketch Coloring Page

如图在四棱锥p abcd中pa⊥平面abcd底面abcd为平行四边形且ab=1bc=2ef分别为adbc的中点．i求证 Template

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anonymous
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tomski如图在四棱锥p abcd中pa⊥平面abcd底面abcd为平行四边形且ab=1bc=2ef分别为adbc的中点．i求证 coloring

如图在四棱锥P ABCD中PA⊥平面ABCD底面ABCD为平行四边形且AB=1BC=2EF分别为ADBC的中点．I求证 sketch template

20．（12分）如图，四棱锥P ABCD的底面为正方形，PD⊥底面ABCD．设平面PAD与平面PBC的交线为l．（1）证明：l⊥平面PDC sketch template

如图在四棱锥P—ABCD中PA⊥底面ABCDAB⊥ADAC⊥CD∠ABC=60°PA=AB=BCE是PC的中点1证明AE sketch template

$如图所示四棱锥P ABCD中PA⊥平面ABCDPB与底面所成的角为$frac{π}{4}$底面ABCD为直角梯形∠ABC=∠BAD sketch template$

如图，在四棱锥P ABCD中，底面ABCD是平行四边形，∠BCD=120°，侧面PAB⊥底面ABCD，PB=2√6，AB=AC=PA=2√3 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图，在四棱锥P ABCD中，PAperp 平面ABCD，PA= AB= AD= 2，四边形ABCD满足ABperp AD，BC sketch template

如图在四棱锥P ABCD中侧面底面ABCD底面ABCD是菱形侧面PAD是等边三角形且PB与面PAD所成角为1求四棱锥P sketch template

如图在底面是菱形的四棱锥 P ABCD中∠ABC=60°PA⊥平面ABCD点EFG分别为CDPDPB的中点．PA=AD=2 sketch template

如图在四棱锥中 BC⊥ABCD⊥ADBC=CD=PA=a Ⅰ求证平面PBD⊥平面PAC Ⅱ求四棱锥P ABCD的体积 sketch template

如图在四棱锥P ABCD中ABCD是菱形PA⊥平面ABCD1求证BD⊥PC2若平面PBC与平面PAD的交线为l求证BC∥ sketch template

在正四棱锥P ABCD中PA＝2直线PA与平面ABCD所成的角为60°求正四棱锥P ABCD的体积V．题目和参考答案——青夏教育精英家教�—— sketch template

如图在四棱锥P ABCD中PD⊥平面ABCD底面ABCD是菱形∠BAD=60°AB=2PD=6O为AC与BD的交点E为棱PB上 sketch template

百度教育 sketch template

如图在四棱锥P ABCD中底面ABCD是矩形侧棱PA垂直于底面EF分别是ABPC的中点 1求证CD⊥PD 2求证 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

如图在正四棱锥P ABCD中AB=PA=21求直线PA与底面ABCD所成角的大小2求点A到平面PBC的距离．题目和参考答案 sketch template

12．如图在四棱锥P ABCD中PD⊥平面ABCDAD⊥DCAD∥BCPD=DC=1BC= I 求PB与平面PDC所成角的大小 sketch template

如图在四棱锥P ABCD中PA⊥底面ABCDAD∥BCAB⊥ADAC与BD交于点OPA=3AD=2AB=23BC=6．Ⅰ sketch template

2019年高考真题理�数学北京卷百度题库 sketch template

如图所示在四棱锥P ABCD中底面ABCD为菱形且∠DAB=60°PA=PDM为CD的中点BD⊥PM．1求证平面PAD⊥平面 sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

如图四棱锥P ABCD中PD⊥平面ABCD底面ABCD是正方形PD=AB=2E为PC中点．1求证DE⊥平面PCB2求点C sketch template

如图已知在四棱锥P ABCD中底面ABCD是边长为4的正方形 PAD是正三角形EFG分别是PDPCBC的中点．1求证直线 sketch template

19．如图所示四棱锥P ABCD中底面ABCD为直角梯形点E在棱PA上且PE=2EA 1 求异面直线PA与CD所成的角 2 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

19．如图在四棱锥P ABCD中底面ABCD是矩形MN分别为PABC的中点 PD⊥平面ABCD且PD=AD=CD=1 1 sketch template

四棱锥的直观图正四棱锥的直观图画正四棱锥直观图第2页大山谷图库 sketch template

如图四棱锥P ABCD中底面ABCD是边长为2的正方形PB⊥BCPD⊥CD且PA=2E为PD中点．1求二面角B EC A的正弦 sketch template

19．已知四棱锥P ABCD的底面ABCD的边长为1的正方形 PD⊥底面ABCD且PD=1 1求证BC//平面PAD 2若 sketch template

如图在三棱柱ABC A1B1C1中侧面AA1C1C⊥底面ABCAA1=A1C=AC=2AB=BCAB⊥BCO为AC的中点1 sketch template

百度教育 sketch template

百度教育 sketch template

如图在长方体ABCD A1B1C1D1中AD=AA1=1AB=2P为线段AD1上的动点1当P为AD1中点时求证PD⊥平面 sketch template

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