如图1rt abc中∠c=90°按题目所给条件及要求将相应的直角三角形分割成若干个全等的并且分别与原三角形相似的三角形．画出图形并简要 Sketch Coloring Page

如图1rt abc中∠c=90°按题目所给条件及要求将相应的直角三角形分割成若干个全等的并且分别与原三角形相似的三角形．画出图形并简要 Template

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tomski如图1rt abc中∠c=90°按题目所给条件及要求将相应的直角三角形分割成若干个全等的并且分别与原三角形相似的三角形．画出图形并简要 coloring

如图1Rt ABC中∠C=90°按题目所给条件及要求将相应的直角三角形分割成若干个全等的并且分别与原三角形相似的三角形．画出图形并简要 sketch template

题目如图Rt ABC中∠BAC=90°AB=3AC=6点DE分别是边BCAC上的动点则DA DE的最小值为． 题目和参考 sketch template

题目如图已知Rt ABC中∠ACB＝90°∠BAC＝30°延长BC至D使CD＝BC连接AD且AD＝4点P为线段AC上一动点 sketch template

如图在Rt ABC中∠C=90°点O在AB上经过点A的⊙O与BC相切于点D与ACAB分别相交于点EF连接AD与EF相交于点G sketch template

如图Rt ABC中∠ACB=90°分别以边ABACBC为边分别�外作等边三角形其面积分别为S1S2S3若S1=6S2=2 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图在Rt ABC中∠C=90°．1根据要求用尺规作图过点C作斜边AB边上的高CD垂足为D不写作法只保留作图痕迹2证明 sketch template

如图在Rt ABC中∠BAC=90°AB=AC=2点D在BC所在的直线上运动作∠ADE=45°．若点D在线段BC上运动DE交AC于 sketch template

如图Rt ABC中∠C=90°⊙O为 ABC的内切圆若AC=6BC=8求⊙O半径． 题目和参考答案——青夏教育精英家教�—— sketch template

如图在 ABC中∠C=90°BE是角平分线DE⊥BE交AB于D⊙O是 BDE的外接圆 1求证AC是⊙O的切线2若AD sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

如图，在Rt ABC中，∠ ACB=90°，∠ ABC=30°，AC=2，点P是边AB上的一动点 ABC≌ ABC，将 A sketch template

如图在 ABC中∠C=90°DE是AB的中垂线分别交ABBC于点DE若∠B=30°BC=10则CE= ． 题目和参考答案 sketch template

将一副三角尺如图�放其中在Rt ABC中∠ACB=90°∠B=60°在Rt EDF中∠EDF=90°∠E=45°．点D为边AB的 sketch template

如图在Rt ABC中∠ACB=90°∠ABC=30°将 ABC绕点C顺时针旋转至 A′B′C使得点A′恰好落在AB上则旋转角度为 sketch template

如图在 ABC中∠C=90°点M在BC上且BM=ACN在AC上且AN=MCAM与BN相交于P求证∠BPM=45°． 题目和 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=4将 ABC绕点A逆时针旋转得到 AB′C′AB′与BC相交于点D当B′C′∥ sketch template

已知在Rt ABC中∠C=90°∠B=30°把∠B沿AB边对折使B点与A点重合折痕为DE若AC=求DE的长． 题目和参考答案 sketch template

如图Rt ABC中∠BAC=90°AD⊥BC于DBG平分∠ABCEF∥BC交AC于F求证AE=CF． 题目和参考答案——青夏 sketch template

如图1Rt ABC中∠ACB=Rt∠AC=8BC=6点D为AB的中点动点P从点A出�沿AC方�以每秒1个单位的速度�终点C运动 sketch template

如图在Rt ABC中∠ACB=90°AB的垂直平分线DE交AC于E交BC的延长线于F若∠A=30°DE=1则DF的长是． 题目 sketch template

如图 ABC中∠C=90°∠B=60°AO=xO在AB上且⊙O的半径为1．问当x在什么范围内取值时AC与⊙O相离相切相交 sketch template

5．如图在Rt ABC中∠C=90°∠A=30°BD是∠ABC的平分线若BD=10则CD=——青夏教育精英家教�—— sketch template

题目如图在直线l上�放着三个三角形 ABC HFG DCE已知BC=CEFG分别是BCCE的中点FM∥AC∥HG∥DE sketch template

在Rt ABC中∠ACB=90°∠A=30°点D是AB的中点连接CD．1如图1AB与BC的数量关系是． 2如图2若P是 sketch template

如图等腰Rt ABC中∠BAC=90°AB=ACBE平分∠ABC交AC于E过C作CD⊥BE于D点写出ATCD与BD之间的数量关系 sketch template

如图所示在 ABC中∠A=α ABC的内角平分线和外角平分线交于点P且∠P=β试探求下列图中α与β的关系并选择一个加以说明——青 sketch template

如图在Rt ABC中∠ACB=90°AB的垂直平分线DE交AC于E交BC的延长线于F若∠F=30°DE=1则BE的长是． 题目 sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

在Rt ABC中∠C=90°AB=12BDAE是中线且BD和AE相交于G点则CG=4． 题目和参考答案——青夏教育精英家教�—— sketch template

如图在Rt ABC中∠BAC=90°AB=ACBD是AC边上的中线AE⊥BD于F交BC于E．1证明∠ABD=∠DAF2 sketch template

如图在Rt ABC中∠ACB=90°AC=BC∠ABC=45°点D为BC的中点CE⊥AD于点E其延长线交AB于点F连接DF sketch template

如图Rt ABC中∠A=60°将 ABC绕点C顺时针旋转得到 A1B1C斜边A1B1与CB相交于点D且DC=AC则旋转角∠ACA1 sketch template

百度教育 sketch template

15．如图Rt ABC中∠C=90°∠ABC=30°AB=6．点D在AB边上点E是BC边上一点不与点BC重合且DA=DE则 sketch template

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