如图在rt abc中∠acb=90°以ac为直径的⊙o与ab边交于点d过点d作⊙o的切线交bc于点e．1求证点e是边bc的中点 Sketch Coloring Page

如图在rt abc中∠acb=90°以ac为直径的⊙o与ab边交于点d过点d作⊙o的切线交bc于点e．1求证点e是边bc的中点 Template

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anonymous

anonymous
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anonymous

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sketch #4953 Bird by Ervin Haxhija

anonymous

anonymous
sketch #4953 Bird by Ervin Haxhija

sketch #2486 Face by sketchmaster

sketchmaster
sketch #2486 Face by sketchmaster

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anonymous

anonymous
sketch #4475 Daft Punk by Reggie Garcia

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sketch #4895 Cat by Gaurav Patel

anonymous

anonymous
sketch #4895 Cat by Gaurav Patel

sketch #2027

anonymous

anonymous
sketch #2027

sketch #2771 Naruto by Милен Тревата

Милен Тревата
sketch #2771 Naruto by Милен Тревата

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anonymous

anonymous
sketch #4728 Angry Toad by Geneval Mendes

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anonymous

anonymous
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anonymous

anonymous
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sketch #4933 Tobi by Abdelwahab Haik

anonymous

anonymous
sketch #4933 Tobi by Abdelwahab Haik

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anonymous

anonymous
sketch #4031

sketch #4915 Marshall Lee Gopal Gopi

anonymous

anonymous
sketch #4915 Marshall Lee Gopal Gopi

sketch #342 Forest scene

Chris Shrimp Lonsdale
sketch #342 Forest scene

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anonymous

anonymous
sketch #1724

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sketch #1551 donara

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sketch #1551 donara

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anonymous

anonymous
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sketch #3732 Michael Jackson by David Obando

anonymous

anonymous
sketch #3732 Michael Jackson by David Obando

sketch #5249 Adele - Skyfall by Mert Arda Yiğit

anonymous

anonymous
sketch #5249 Adele - Skyfall by Mert Arda Yiğit

sketch #2740 Monster by Gabriela Segura

Gabriela Segura
sketch #2740 Monster by Gabriela Segura

sketch #4902

anonymous

anonymous
sketch #4902

tomski如图在rt abc中∠acb=90°以ac为直径的⊙o与ab边交于点d过点d作⊙o的切线交bc于点e．1求证点e是边bc的中点 coloring

题目已知如图在Rt ABC中∠ACB=90°D是边AB的中点CE=CBCD=5求1BC的长．2tanE的值 sketch template

如图在Rt ABC中∠ACB=90°DE分别为ABAC边上的中点连接DE将 ADE绕点E旋转180°得到 CFE连接AFAC sketch template

如图在Rt ABC中∠ACB=90°以AC为直径作⊙O交AB于点DE为BC的中点连接DE并延长交AC的延长线于点F．1求证DE sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图在Rt ABC中∠ACB=90°D是AB边上一点以BD为直径的⊙O与AC交于点E连接DE并延长与BC的延长线交于点FBD sketch template

如图在Rt ABC中∠ACB=90°以AC为直径作⊙O交斜边AB于点E．1点F为BC的中点连接EF求证EF是⊙O的切线2 sketch template

如图已知在Rt ABC中∠ACB=90°AB=4分别以ACBC为直径作半圆面积分别记为S1S2则S1 S2的值等于 A sketch template

如图已知Rt ABC中∠ACB=90°BC=6AB=10以BC为直径的⊙O交AB于DACDO的延长线交于E点M为线段AC上一点 sketch template

如图Rt ABC中∠ACB=90°AC=3BC=1将Rt ABC绕C点旋转90°后为Rt A′B′C′再将Rt A′B′C′绕B点 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

已知如图在Rt ACB中∠C=90°AC=4cmBC=3cm．点P由B出�沿BA方��点A匀速运动点Q由A出�沿AC方��点C匀速 sketch template

如图在Rt ABC中∠A =90°AC =6cmAB=8cm把AB边翻折使AB边落在BC边上点A落在点E处折痕为BD则sin sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

题目如图在Rt ABC中∠C=90°以AC为直径作⊙O交AB于D过点O作OE∥AB交BC于E．1求证ED为⊙O的切线 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径作⊙O交AB于点DE为BC的中点连接DE并延长交AC的延长线于点F．1求证DE sketch template

题目如图等腰Rt ABC中∠ABC＝90°AB＝BC点AB分别在坐标轴上．1如图1若点C的横坐标为5直接写出点B的坐标 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图在Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点E点D是BC边上的中点连接DE．1求证DE与⊙O相切2 sketch template

4．如图在Rt ABC中∠C=90°． 1若AC=5BC=12则AB= TanA= ∠A≈ 2若AC=3AB=5则 sketch template

如图在Rt ABC中∠ACB=90°AC=4BC=3D是边AB上一点联结CD把 ACD沿CD所在的直线翻折点A落在点E的位置 sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

如图在Rt ABC中∠C=90°BD是∠ABC的平分线交AC于D若CD=mAB=n则 ABD的面积是 A．mnB．12mnC sketch template

如图，在Rt ABC中，∠ACB=90°，CB=4，CA=6， C半径为2，P为圆上一动点，连结AP，BP，则AP 12BP的最小值为（）A sketch template

如图Rt ABC中∠ABC＝90°以AB为直径的⊙O交AC于点DE是BC的中点连接DEOE．1判断DE与⊙O的位置关系并说明 sketch template

如图 Rt ABC绕O点旋转90°得Rt BDE其中∠ACB=∠E= 90°AC=3DE=5 则OC的长为 A． B． C sketch template

14．如图Rt ABC中AC=8BC=6∠C=90°⊙I分别切ACBCAB于DEF求Rt ABC的内心I与外心O之间的距离 sketch template

如图在Rt ABC中∠ACB=90°以AC为直径的⊙O与AB边交于点D过点D作⊙O的切线交BC于点E．1求证点E是边BC的中点 sketch template

如图在Rt ABC中∠C=90°以点C为圆心作⊙C与AB切于点D过点AB分别作⊙C的切线AFBE切点为FE点．求证AF∥ sketch template

如图在Rt ABC中∠ACB＝90°AB＝4cm AC＝2cm以B为圆心以BC为半径作弧交AB于D求阴影部分面积——青夏教育精英 sketch template

题目在Rt ABC中∠C=90°BC=3AC=4点P在以C为圆心5为半径的圆上连结PAPB．若PB=4则PA的长为 sketch template

如图在等腰Rt ABC中∠BAC=90°BC=2点E为线段AB上任意一点以CE为斜边作等腰Rt CDE连接AD下列结论�∠ sketch template

如图Rt ABC中∠BAC=90°以AB为直径作⊙O交BC于点DOE∥BC交AC于点E连接AD交OE于点F连接DE．1判断 sketch template

在Rt ABC中∠ACB=90°∠BAC=30°BC=6．I如图�将线段CA绕点C顺时针旋转30°所得到与AB交于点M则CM的 sketch template

如图AB是⊙O的直径∠ABC=30OA=2 则BC长为A．2 B．2 C．4D．——青夏教育精英家教�—— sketch template

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