已知正三棱柱abc A¹b²c³的底面边长为3，其外接球表面积为16π，则正三棱柱的体积是多�？ 知乎 Sketch Coloring Page

已知正三棱柱abc A¹b²c³的底面边长为3，其外接球表面积为16π，则正三棱柱的体积是多�？ 知乎 Template

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tomski已知正三棱柱abc a¹b²c³的底面边长为3，其外接球表面积为16π，则正三棱柱的体积是多�？ 知乎 coloring

如图，已知三棱柱ABC A1B1C1的底面是正三角形，侧面BB1C1C是矩形，M，N分别为BC，B1C1的中点，P为AM上一点，过B1C1和P sketch template

如图已知正三棱柱 的底面边长为2侧棱长为点E在侧棱上点F在侧棱上且 I 求证 II 求直线与平面的夹角题目和参考 sketch template

工具书式学习高中数学以及思维障碍的突破中国期刊� sketch template

如图，已知正三棱柱ABC A 1B 1C 1的所有棱长都为2，D为CC 1中点，E为BC的中点（1）求证：BD⊥ 平面AB 1E；（2）求三 sketch template

一个正三棱柱的三视图如图所示则这个正三棱柱的高和底面边长分别为 A13B21C21D12 题目和参考答案——青夏教育 sketch template

如图已知正三棱柱ABC A1B1C1的各条棱长均为2M是BC的中点．Ⅰ求证A1C∥平面AB1MⅡ求证在棱CC1上找一点N使得 sketch template

19． 已知斜三棱柱ABC A1B1C1的高考资^源�侧面A1ACC1与底面ABC垂直∠ABC＝90°BC＝2AC＝2且AC sketch template

D 18——青夏教育精英家教�—— sketch template

斜三棱柱ABC A1B1C1的底面是边长为2的正三角形顶点A1在底面的射影O是 ABC的中心异面直线AB与CC1所成的角为45° 1 sketch template

如图已知正三棱柱ABC A1B1C1的各条棱长均为2M是BC的中点．Ⅰ求证A1C∥平面AB1MⅡ求证在棱CC1上找一点N使得 sketch template

已知正三棱柱底面边长是2外接球的表面积是16π则该三棱柱的体积为 A．2$sqrt{2}$B．2$sqrt{3}$C．4 sketch template

已知直三棱柱ABC A1B1C1中，侧面AA1B1B为正方形 sketch template

如图正三棱柱ABC A1B1C1的所有棱长都为2D为CC1中点．Ⅰ求证AB1⊥A1DⅡ求点C到平面A1BD的距离．题目和参考 sketch template

如图在正三棱柱ABC 中AB=1点D在棱上BD=1若AD与平面BC所成的角为a则sina= ——青夏教育精英家教�—— sketch template

斜三棱柱ABC A1B1C1的底面是边长为2的正三角形侧棱长为2侧棱AA1和底面相邻两边ABAC都成45°角求全面积和体积 题目和 sketch template

已知斜三棱柱ABC A1B1C1各条棱长都是且一个顶点A1在另一底面的射影恰好是这底面正三角形的中心求此三棱柱的全面积．——青夏教育精英家教�—— sketch template

三棱柱ABC A1B1C1的底面是边长为4的正三角形侧面AA1C1C是菱形 PA⊥BC点P是A1C1的中点∠C1CA=60° 1 sketch template

已知三棱柱ABC A1B1C1的直观图和三视图如图所示E是棱CC1上一点．1若CE=2EC1求三棱锥E ACB1的体积．2若E是 sketch template

如图已知三棱柱ABC A1B1C1的侧棱与底面垂直 AA1=AB=AC=1AB⊥AC M是CC1的中点 N是BC的中点点P在线段 sketch template

4．如图在斜三棱柱ABC A1B1C1中侧面AA1B1B⊥底面ABC侧棱AA1与底面ABC成60°的角AA1=2底面ABC是边长为2 sketch template

已知三棱柱ABC A1B1C1的侧棱与底面边长都相等A1在底面ABC上的射影为BC的中点则异面直线AB与CC1所成的角的余弦值为 AB sketch template

正三棱柱内切球（球与上下底面和侧面都相切）的半径是 高途 sketch template

已知斜三棱柱ABC A1B1C1的底面为正三角形侧面A1ACC1为菱形∠A1AC=60°且平面A1ACC1⊥平面ABCM是C1C的中点 sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

已知斜三棱柱ABC A1B1C1的底面ABC中AB=10BC=6AC=8A1到ABC三点的距离相等AA1=13求棱柱的体积 sketch template

已知斜三棱柱ABC A1B1C1的底面为正三角形侧面A1ACC1为菱形∠A1AC=60°且平面A1ACC1⊥平面ABCM是C1C的中点 sketch template

19．已知在三棱柱ABC A1B1C1中侧棱与底面成60°角AB⊥ACBC1⊥A1C1AB=4AC=3 1求证面ABC1⊥面 sketch template

已知正三棱柱ABC A¹B²C³的底面边长为3，其外接球表面积为16π，则正三棱柱的体积是多�？ 知乎 sketch template

18．如图在斜三棱柱ABC A1B1C1中侧面AA1B1B⊥底面ABC侧棱AA1与底面ABC成60°的角AA1=2底面ABC是边长 sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

已知三棱柱ABC A1B1C1的侧棱与底面边长都相等A1在底面ABC上的射影为BC的中点则异面直线AB与CC1所成的角的余弦值为 AB sketch template

已知直三棱柱ABC A1B1C1的6个顶点都在球O的球面上．若AB=3AC=4AB⊥ACAA1=12则球O的直径为1313．题目和 sketch template

已知正三棱柱ABC A1B1C1的每条棱长均为aM为棱A1C1上的动点．1当M在何处时BC1∥平面MB1A并证明之下求平面 sketch template

如图在斜棱柱ABC A1B1C1中底面为正三角形侧棱长等于底面边长且侧棱与底面所成的角为60°顶点B1在底面ABC上的射影O恰好是 sketch template

18．如图已知斜三棱柱ABC A1B1C1中∠BCA=90°AC=BC=a点A1在底面ABC上的射影恰为AC的中点DBA1⊥AC1 sketch template

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