如图，已知点a、b、c在同一直线上， Abd和 Bce都是等边三角形．则在下列结论中：�ap=dq，�ep=ec，�pq=pb，�∠aob=∠ Sketch Coloring Page

如图，已知点a、b、c在同一直线上， Abd和 Bce都是等边三角形．则在下列结论中：�ap=dq，�ep=ec，�pq=pb，�∠aob=∠ Template

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tomski如图，已知点a、b、c在同一直线上， abd和 bce都是等边三角形．则在下列结论中：�ap=dq，�ep=ec，�pq=pb，�∠aob=∠ coloring

如图ABC三点在同一直线上1用上述字母表示的不同线段共有条2用上述字母表示的不同射线共有条——青夏教育精英家教�—— sketch template

如图已知点ABC是数轴上三点O为原点．点C对应的数为6BC=4AB=12．1求点AB对应的数2动点PQ分别同时从A sketch template

如图已知点BFCE在同一直线上AB∥DEAB=DEBF=EC请说明 ABC与 DEF全等的理由．题目和参考答案——青夏教育 sketch template

28．如图已知点BCD在同一条直线上 ABC和 CDE 都是等边三角形．BE交AC于FAD交CE于H �求证 BCE≌ ACD sketch template

6．如图已知ΔABC和ΔABD都是⊙O的内接三角形AC和BD相交于点E则与ΔADE相似的三角形是 A．ΔBCE B．ΔABC C sketch template

如图，已知点A、B、C在同一直线上， ABD和 BCE都是等边三角形．则在下列结论中：�AP=DQ，�EP=EC，�PQ=PB，�∠AOB=∠ sketch template

几何模型 “8”字模型知乎 sketch template

如图已知点ABCD在一条直线上EC∥FD∠F=∠E求证AE∥BF．请在下列空格内填写结论和理由完成证明过程∵EC∥FD∴ sketch template

10．如图所示已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点OAE与CD交于点GAC与BD交于点F sketch template

本题满分12分每小题满分各4分已知平面直角坐标系xOy一次函数的图像与y轴交于点A点M在正比例函数的图像上且MO＝MA．二次函数y sketch template

已知如图把长方形纸片ABCD沿EF折叠后．点D与点B重合点C落在点C′的位置上．若∠1＝60°AE=1． 1求∠2∠3的度数 sketch template

如图已知点ABCD均在已知圆上AD∥BCCA平分∠BCD∠ADC=120°四边形ABCD的�长为10图中阴影部分的面积为A sketch template

如图已知 ABC和 DCE均是等边三角形点BCE在同一条直线上AE与BD交于点O与CD交于点GAC与BD交于点F连接OC．求证 sketch template

如图．已知点BCD在同一条直线上． ABC和 CDE都是等边三角形BE交AC于FAD交CE于H1求证 BCE≌ ACD2 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

理解证明如图1∠MAN=90°射线AE在这个角的内部点BC在∠MAN的边AMAN上且AB=ACCF⊥AE于点FBD⊥AE于点 sketch template

如图在 ABC中∠C=90°AE平分∠BAC交BC于E点O在AB上以OA为半径的圆交AB于D交AC于C且点E在⊙O上连接DE sketch template

题目如图已知二次函数 Y＝ax2 Bx ca≠0的图象与 X 轴交于点 A对称轴为直线 X＝1与 Y 轴的交点 B 在之间下列 sketch template

21如图，已知等腰直角三角形ABC，点P是斜边BC上一点不与B，C重合，PE是 ABP的外接圆⊙O的直径．1求证： APE是等腰直角 sketch template

【平面�量�从等和线到等差线及等商线知乎 sketch template

如图已知点ABCD顺次在圆O上AB=BDBM⊥AC垂足为M．证明AM=DC CM．题目和参考答案——青夏教育精英家教�—— sketch template

如图已知点AFEC在同一直线上AB∥CD∠ABE=∠CDFAF=CE．1从图中任找两组全等三角形中任选一组进行证明．题目 sketch template

题目某区域平面示意图如图点O在河的一侧AC和BC表示两条互相垂直的公路．甲勘测�在A处测得点O位于北偏东45°乙勘测�在B处测得点O sketch template

浅谈完全四边形性质知乎 sketch template

如图，已知 ABC为等腰直角三角形，AC=BC且∠ACB=90°，D为AB上一动点，连接CD，把CD绕点D旋转90°得到ED，连接CE；（1 sketch template

如图1已知抛物线y=x2 2x 3与x轴交于点A和点B与y轴相交于点C．1求ABC三点的坐标2点D为射线CB上的一动点过点 sketch template

如图已知在四边形ABCD中∠BAD=∠BCD=90°BC=CDE是AD延长线上一点若DE=AB=3cmCE=42cm．1试证明 sketch template

如图直线l过等腰直角三角形ABC顶点BAC两点到直线l的距离分别是2和3则AB的长是 A．5B．5C．11D．13 题目和参考答案 sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图已知 ABC和 ADE均为等边三角形D在BC上DE与AC相交于点FAB＝9BD＝3则CF等于A．1 B．2 C．3 D．4 sketch template

如图，在三角形ABC中已知∠ A = 90° ∠ C 60° 。把三角形ABC绕点B按顺时针方�旋转一定的角度后，得到三角形A B sketch template

如图已知AB=BC=CD弦AC和BD交于点E∠AED=70°则∠B= 度．题目和参考答案——青夏教育精英家教�—— sketch template

题目如图在Rt ABC中∠C=90°BC=2AC=2点D是BC的中点点E是边AB上一动点沿DE所在直线把 BDE翻折到 B sketch template

如图已知AD是 ABC的角平分线AD的垂直平分线交AB于点F交BC的延长线于点E连接AEDF．试说明1∠EAD=∠EDA2 sketch template

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