如图1已知菱形abcd的边长为23点a在x轴负半轴上点b在坐标原点．点d的坐标为 33抛物线y=ax2 B经过abcd两边的 Sketch Coloring Page

如图1已知菱形abcd的边长为23点a在x轴负半轴上点b在坐标原点．点d的坐标为 33抛物线y=ax2 B经过abcd两边的 Template

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sketch #4774 Banksy&#;s Wall and Piece by Ameli Cedeño Barcia

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sketch #3359 &#;In love and lonely&#; by Irul Ventura

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sketch #3359 &#;In love and lonely&#; by Irul Ventura

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sketch #2678 Portrait by Jocelyn Alejandra Rantul

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sketch #2628 Black haired women

sketchmaster
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sketch #5135 &#;Hypno Colorfull&#; by Lars Tunebo

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anonymous
sketch #5135 &#;Hypno Colorfull&#; by Lars Tunebo

sketch #3242 Jolteon by Välë Chäpärrö Järämïllö

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sketch #3242 Jolteon by Välë Chäpärrö Järämïllö

sketch #5211

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sketch #4093 freefree

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sketch #4093 freefree

sketch #1671

Saifa Mahmud
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sketch #3118 Joker Hernan Da Costa Marquez

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anonymous
sketch #3118 Joker Hernan Da Costa Marquez

sketch #5219 Zayn Malik by Amila Madhushanaka

anonymous

anonymous
sketch #5219 Zayn Malik by Amila Madhushanaka

sketch #5313 Katy Perry by Monalisa Theresia

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anonymous
sketch #5313 Katy Perry by Monalisa Theresia

sketch #4640 Serj Tankian by Dav Guzman Mendoza

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sketch #4640 Serj Tankian by Dav Guzman Mendoza

sketch #2486 Face by sketchmaster

sketchmaster
sketch #2486 Face by sketchmaster

sketch #5314

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sketch #4979 Luffy

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sketch #4979 Luffy

sketch #3431 Jimi Hendrix by Konvicted Rohit

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sketch #3431 Jimi Hendrix by Konvicted Rohit

sketch #4895 Cat by Gaurav Patel

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sketch #4895 Cat by Gaurav Patel

sketch #3510 Edward from FMA by Raman Chauhan

anonymous

anonymous
sketch #3510 Edward from FMA by Raman Chauhan

tomski如图1已知菱形abcd的边长为23点a在x轴负半轴上点b在坐标原点．点d的坐标为 33抛物线y=ax2 b经过abcd两边的 coloring

如图1已知菱形ABCD的边长为23点A在x轴负半轴上点B在坐标原点．点D的坐标为 33抛物线y=ax2 b经过ABCD两边的 sketch template

已知菱形ABCD中∠A=72°如图�可以用3条直线将菱形ABCD分割成4个等腰三角形．你能在图��中再作出符合条件的两种分割方法吗 sketch template

如图，在边长为10的菱形ABCD中，对角线BD=16，点O是线段BD上的动点，OE⊥ AB于E，OF⊥ AD于F（1）对角线AC的长是 sketch template

$1如图1已知正方形ABCD的边长为4圆B的半径为2点P是圆B上的一个动点求PD $frac{1}{2}PC$的最小值和PC sketch template$

如图已知正方形ABCD的边长为4点EF分别在边ABBC上且AE=BF=1CEDF交于点O．下列结论�∠DOC=90°�OC sketch template

如图已知菱形ABCD的对角线ACBD的长分别为6cm8cmAE⊥BC于点E求AE的长．题目和参考答案——青夏教育精英家教�—— sketch template

如图1边长为a的正方形�生形变后成为边长为a的菱形如果这个菱形的一组对边之间的距离为h�们把a与h的比值叫做这个菱形的“形变度．1 sketch template

已知菱形ABCD的边长为2∠BAD=60°．将三角形ABD沿对角线BD折到ABD使得二面角A BD C的大小为60°则AD与平面 sketch template

如图已知菱形ABCD的两条对角线分别6cm和8cm则这个菱形的�长是A 40cm B 28cm C 24cm D 20cm——青夏 sketch template

已知菱形的边长为2，将沿折起，使得点至点的位置，得到四面体当二面角的大小为120°时，四面体的体积为；当四面体的体积为1时，以为球心，的长 sketch template

百度教育 sketch template

如图在菱形ABCD中AB=2∠A=120°过菱形ABCD的对称中心O分别作边ABBC的垂线交各边于点EFGH则四边形 sketch template

如图1，已知点A（a，0），B（0，b），且a、b满足（a b 3）2＝0，平行四边形ABCD的边AD与y轴交于点E，且E为AD中点，双曲线 sketch template

如图，在平行六面体ABCD A 1B 1C 1D 1中，底面是边长为2的正方形，若∠ 1AB=∠ 1AD=60^° ，且A 1A sketch template

如图1，已知O为正方形ABCD对角线的交点，点E在边CB的延长线上，连结EO，OF⊥OE交BA延长线于点F，连结EF．1求证：EO＝FO sketch template

如图已知菱形ABCD其顶点AB在数轴上对应的数分别为 4和1则BC= ．题目和参考答案——青夏教育精英家教�—— sketch template

如图，在菱形ABCD中，AB=AC=10，对角线AC、BD相交于点O，点M在线段AC上，且AM=3，点P为线段BD上的一个动点，则MP sketch template

如图1已知四边形ABCD是正方形对角线ACBD相交于点E以点E为顶点作正方形EFGH．1如图1点AD分别在EH和EF上连接 sketch template

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

如图1已知正方形ABCD的对角线ACBD相交于点OE是AC上一点连接EB过点A作AM⊥BE垂足为MAM交BD于点F．1求证 sketch template

如图1已知正方形ABCD的对角线ACBD相交于点OE是AC上一点连接EB过点A作AM⊥BE垂足为MAM交BD于点F．1求证 sketch template

如图1点O是正方形ABCD两对角线的交点分别延长OD到点GOC到点E使OG=2ODOE=2OC然后以OGOE为邻边作正方形 sketch template

如图正方形ABCD的边长为a分别以正方形的四个顶点为圆心边长为半径在正方形内画弧求图中阴影部分的面积．题目和参考答案——青夏教育 sketch template

如图已知两个正四棱锥P ABCD与Q ABCD的高分别为1和2AB=4 � 证明PQ⊥平面ABCD � 求异面直线AQ与PB所成的角 sketch template

如图1已知四边形ABCD是正方形对角线ACBD相交于点E以点E为顶点作正方形EFGH．1如图1点AD分别在EH和EF上连接 sketch template

百度教育 sketch template

如图在大房间一面墙壁上边长为15cm的正六边形横排20片和以其一部分所形成的梯形B三角形CDE菱形F等六种瓷砖毫无空隙地排列在一起 sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图所示已知四棱锥P ABCD的底面是菱形∠DAB=π3AC∩BD=OPO⊥平面ABCDEF分别在棱PCPA上CE=13CP sketch template

如图在四棱锥P ABCD中PA⊥平面ABCD底面ABCD为平行四边形且AB=1BC=2EF分别为ADBC的中点．I求证 sketch template

如图边长为2的菱形ABCD中BD=2EF分别是ADCD上的动点且AE CF=2则线段EF长的取值范围是$sqrt{3}$≤EF sketch template

如图边长为2的菱形ABCD中∠BAD=60°现有∠BFE=30°的三角板 BEF将 BEF绕B旋转得 BE′F′BE′BF′所在 sketch template

已知四棱锥P ABCD它的底面是边长为a的菱形且∠ABC＝120°PC⊥平面ABCD又PC＝aE为PA的中点． 1求证平面 sketch template

20．已知如图以正方形ABCD的对角线为边作菱形AEFCB在FE的延长线上．求证AEAF把∠BAC三等分．——青夏教育精英家教�—— sketch template

已知如图在圆内接四边形ABCD中∠B=30°则∠D= 150° ．考点圆内接四边形的性质分析根据圆内接四边形对角互补直接求出 sketch template

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