四边形abcd是正方形点e是边bc上的任意一点∠aef=90°且ef交正方形外角的平分线cf于点f．1如图1求证ae=ef2 Sketch Coloring Page

四边形abcd是正方形点e是边bc上的任意一点∠aef=90°且ef交正方形外角的平分线cf于点f．1如图1求证ae=ef2 Template

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sketch #3448 Treba mi bolji "mish " ;)

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tomski四边形abcd是正方形点e是边bc上的任意一点∠aef=90°且ef交正方形外角的平分线cf于点f．1如图1求证ae=ef2 coloring

四边形ABCD为正方形，点E为线段AC上一点，连接DE，过点E作EF⊥ DE，交射线BC于点F，以DE、EF为邻边作矩形DEFG，连接CG sketch template

如图四边形ABCD是正方形E是边AB上一点连接DE直线DE绕着点D逆时针旋转90°交BC的延长线于点F．1如图1求证DE sketch template

四边形ABCD是边长为4的正方形点E在边AD所在直线上连接CE以CE为边作正方形CEFG点D点F在直线CE的同侧连接BF．1 sketch template

百度教育 sketch template

已知四边形ABCD是正方形点P在直线BC上点G在直线AD上PG不与正方形顶点重合且在CD的同侧PD=PGDF⊥PG于点H sketch template

四边形ABCD是正方形点E是边BC上的任意一点∠AEF=90°且EF交正方形外角的平分线CF于点F．1如图1求证AE=EF2 sketch template

题目如图�四边形ABCD为正方形点EF分别在AB与BC上且∠EDF=45°易证AE CF=EF．1如图�在四边形ABCD sketch template

百度教育 sketch template

如图1在正方形ABCD中点EF分别为边BCCD的点AFDE相交于点G．如图1若点EF不是正方形ABCD的边BCCD的中点但 sketch template

如图1点E是正方形ABCD的边CD上一点连结AE过点A作AF⊥AE交CB的延长线于点F1求证AE=AF2连结EFM为EF sketch template

题目如图1在正方形ABCD中点E是AB边上的一个动点点E与点AB不重合连接CE过点B作于点G交AD于点F．1求证 sketch template

题目如图在正方形ABCD中对角线AC与BD相交于点O点E是BC上的一个动点连接DE交AC于点F．1如图�当时求 的值 sketch template

百度教育 sketch template

题目如图1在正方形ABCD中点E是AB边上的一个动点点E与点AB不重合连接CE过点B作BF⊥CE于点G交AD于点F．1 sketch template

小明遇到一个问题如图1正方形ABCD中EFGH分别是ABBCCD和DA边上靠�ABCD的n等分点连接AFBGCH sketch template

如上右图四边形ABCD是正方形CE＝MN∠MCE＝35°那么∠ANM 等于 ——青夏教育精英家教�—— sketch template

点E在正方形ABCD的边BC上点F在AE上连接FBFD∠ABF=∠AFB．1如图1求证∠AFD=∠ADF2如图2过点F sketch template

如图在直角坐标系中四边形ABCD是正方形 AC 曲线AAAA 叫做“正方形的渐开线其中AA AAAA 的圆心依次是点BC sketch template

如图在正方形ABCD中点E为对角线AC上的一点连接BEDE．1如图1求证 BCE≌ DCE2如图2延长BE交直线CD于 sketch template

如图等腰梯形ABCD中AD∥CBAE∥CDAB=AD=CD=8cm∠C=60°则梯形ABCD的�长为cmA24B32C sketch template

如图，在四边形ABCD中，对角线AC与BD交于点O，已知OA =OC，OB=OD，过点O作EF⊥ BD，分别交AB、DC于点E，F，连接DE sketch template

如图EFGH分别是四边形ABCD的边ABBCCDDA的中点顺次连接EFGH所得的四边形EFGH显然是平行四边形．1当 sketch template

如图点E为正方形ABCD的边BC所在直线上的一点连接AE过点C作CF⊥AE于F连接BF．1如图1当点E在CB的延长线上且AC sketch template

矩形、菱形、正方形知识点汇总 5大题型解析例题知乎 sketch template

题目如图正方形ABCD的边长为12点E是射线BC上的一个动点连接AE并延长交射线DC于点F将 ABE沿直线AE翻折点B落在点B sketch template

初中数学20道经典几何难题！附答案详解 正方形 直线 四边形 sketch template

（1）问题探究：如图1，在正方形ABCD中，点E，Q分别在边BC、AB上，DQ⊥AE于点O，点G，F分别在边CD、AB上，GF⊥AE．�判断 sketch template

题目如图1在正方形ABCD中AD=6点P是对角线BD上任意一点连接PAPC过点P作PE⊥PC交直线AB于点E1求证 sketch template

18．四边形ABCD是正方形． 1如图12点G是BC边上任意一点不与BC两点重合连接AG作BF⊥AG于点FDE⊥AG于点E sketch template

初中数学说题范例（八篇）范文118 sketch template

如图已知正方形ABCD以CD为边�外作等边三角形CDEBE与AC相交于点F求证EF=CF BF 百度教育 sketch template

10．如图4所示正方形ABCD的对角线相交于点O点E是BC上任意一点EG⊥BD 于GEF⊥AC于F若AC=10则EG EF的值为 sketch template

如图EFGH分别是四边形ABCD四条边的中点则四边形EFGH一定是 A．平行四边形B．矩形C．菱形D．正方形 题目和参考答案 sketch template

百度教育 sketch template

顺次连接下列四边形各边的中点所得的四边形为矩形的是 A．等腰梯形B．矩形C．菱形D．平行四边形E．等腰梯形——青夏教育精英家教�—— sketch template

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