如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Sketch Coloring Page

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 Template

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tomski如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是abcd——青夏教育 coloring

如图已知三棱锥的底面是直角三角形直角边长分别为3和4过直角顶点的侧棱长为4且垂直于底面该三棱锥的主视图是ABCD——青夏教育 sketch template

正三棱锥的高是多� 百度经验 sketch template

4．如图已知三棱锥的底面是直角三角形直角边长分别为3和4 过直角顶点的侧棱长为4且垂直于底面该三棱锥的正视图是 ——青夏教育精英 sketch template

初学讲义之高中数学二十：简单几何体知乎 sketch template

已知三棱锥的三视图如右图所示其中侧视图为直角三角形俯视图为等腰直角三角形则此三棱锥的体积等于 A． B． C． D．题目和参考 sketch template

高中数学第一册上棱锥 Word文档在线阅读与下载无忧文档 sketch template

一个三棱锥的各个面均为正三角形以每个面的中心为顶点构成一个新三棱锥若新三棱锥体积为2求原三棱锥体百度知道 sketch template

已知三棱锥P ABC中顶点P在底面的射影O是三角形ABC的内心关于这个三棱锥有三个�题�侧棱PA=PB=PC�侧棱PAPBPC两两 sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

下面有四个�题1各个侧面都是等腰三角形的棱锥是正棱锥2三条侧棱都相等的棱锥是正棱锥3底面是正三角形的棱锥是正三棱锥4 sketch template

四棱锥图片直观图三棱锥和四棱锥图片四棱锥图片素描图片大山谷图库 sketch template

如图三棱锥P ABC的底面ABC是以AC为斜边的直角三角形且顶点P在底面的射影是 ABC外心设PB=AB=1BC=2．1求证面 sketch template

如图，在四棱锥中，底面是梯形，，侧面是等边三角形，侧面是等腰直角三角形， sketch template

已知正三棱柱ABC A1B1C1的底面边长为2高为4过BC作一截面截面与底面ABC成600角则截面面积是 A．4 B． C． D sketch template

侧面是全等的等腰三角形的棱锥是 A．正棱锥 B．侧棱长相等的棱锥 C．斜高长相等的棱锥 D．以上均不对——青夏教育精英家教�—— sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图已知四棱锥P ABCDPA⊥平面ABCD底面ABCD为直角梯形∠A=90°且AB//CDAB=CD 1点F在线段PC上运动 sketch template

如图，在四棱锥P ABCD中，底面ABCD是平行四边形，∠BCD=120°，侧面PAB⊥底面ABCD，PB=2√6，AB=AC=PA=2√3 sketch template

如图在底面为直角梯形的四棱锥P ABCD中AD∥BC∠ABC＝90°PA⊥面ABCDPA=2AD=2AB=BC=6 1 求证 sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图，四棱锥的底面是直角梯形，，平面是的中点，与平面交于点 sketch template

如图已知四棱锥S ABCD的侧面SCD⊥底面ABCDBC∥ADBC⊥SC且SC=SD=CD=BC=2AD =2P为SB的中点求 sketch template

已知四棱锥如图5 1所示，其三视图如图5 2所示，其中正视图和侧视图都是直角三角形，俯视图是矩形 1求此四棱锥的体积； 2若E是PD sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

如图已知四棱锥P ABCD的底面为直角梯形AB∥CD∠DAB=90°PA⊥底面ABCD且PA=AD=DC=12AB=1M是PB的 sketch template

如图斜三棱柱ABC A1B1C1的底面是Rt ABC∠A＝90 °且BC1⊥AC作C1 H⊥底面ABC垂足为H�试判断H点的位置 sketch template

如图，已知六棱锥的底面是正六边形，则下列结论正确的是 A． B． C．直线∥ D．直线所成的角为45°——青夏教育精英家教�—— sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图在底面是直角梯形的四棱锥S ABCD中面ABCD SA=AB=BC=1AD= Ⅰ求四棱锥S ABCD的体积 Ⅱ求面SCD sketch template

如图在斜棱柱ABC A1B1C1中底面为正三角形侧棱长等于底面边长且侧棱与底面所成的角为60°顶点B1在底面ABC上的射影O恰好是 sketch template

如图已知四棱锥S ABCD的底面是直角梯形AB∥DC∠DAB=90°SA⊥底面ABCD且SA=AD=DC=12AB=1M是SB的中点 sketch template

练题本立体几何9 副本 Word文档在线阅读与下载免费文档 sketch template

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA=PD=AD=2EF分别为PCBD的中点．Ⅰ sketch template

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