如图在三角形abc中∠acb=90°∠b=50°将此三角形绕点c沿顺时针方�旋转后得到三角形a′b′c若点b′恰好落在线段ab上 Sketch Coloring Page

如图在三角形abc中∠acb=90°∠b=50°将此三角形绕点c沿顺时针方�旋转后得到三角形a′b′c若点b′恰好落在线段ab上 Template

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tomski如图在三角形abc中∠acb=90°∠b=50°将此三角形绕点c沿顺时针方�旋转后得到三角形a′b′c若点b′恰好落在线段ab上 coloring

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数知乎 sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数知乎 sketch template

如图在三角形ABC中∠ACB=90°∠B=50°将此三角形绕点C沿顺时针方�旋转后得到三角形A′B′C若点B′恰好落在线段AB上 sketch template

如图在三角形ABC中AB=ACD是BC上一点∠BAD=40°E是AC上一点AD=AE求∠EDC的度数．题目和参考答案——青夏 sketch template

如图，在直角三角形ABC中，∠ACB=90°，∠CBA=30°，请你设计三种不同的分法，把 ABC分割成两个三角形，且 ZOL问答 sketch template

如图，在直角三角形ABC中，∠ACB=90°，∠CBA=30°，请你设计三种不同的分法，把 ABC分割成两个三角形，且 ZOL问答 sketch template

在等边三角形ABC中，点D、E分别在AB、BC边上，连结CD，AE交于点P，且CD=AE，∠ BCD=20°，则∠ APD的度数为百度教育 sketch template

如图在 ABC中AB=AC∠A=36°BD平分∠ABC则∠1= 度图中有个等腰三角形．题目和参考答案——青夏教育精英家教�—— sketch template

如图�在 ABC中∠ABC与∠ACB的平分线相交于点P．1如果∠A=80°求∠BPC的度数2如图�作 ABC外角∠MBC∠ sketch template

百度教育 sketch template

如图，在三角形ABC中已知∠ A = 90° ∠ C 60° 。把三角形ABC绕点B按顺时针方�旋转一定的角度后，得到三角形A B sketch template

已知：在三角形ABC中，AB=AC角BAC=20度，D点在AB上且AD=BC求角ACD的度数知乎 sketch template

如图在 ABC中∠ABC和∠BAC的角平分线交于点OOD⊥BCOE⊥ACOF⊥AB垂足分别为DEF． OC平分∠ACB吗为 sketch template

2012•白下区一模如图直线l经过等边三角形ABC的顶点B在l上取点DE使∠ADB=∠CEB=120°．若AD=2cmCE sketch template

如图 ABC中∠B=42o∠C=72 OAD是 ABC的角平分线 �∠BAC等于多�度简要说明理由 �∠ADC等于多�度简要说明 sketch template

如图在三角形ABC中BDDC=12E为AD的中点若三角形ABC的面积为120平方厘米则阴影部分的面积是多�平方厘米题目和参考 sketch template

在三角形ABC中点O是AC边上一个动点过点O作MN∥BC设MN交∠BCA的平分线于点E交 ABC的外角∠ACD平分线于点E．1求证 sketch template

15．如图所示已知等腰直角三角形ABC中∠ACB=90°直线L经过点C AD ⊥LBE⊥L垂足分别为DE． 1证明 ACD sketch template

如图在 ABC中分别以ABAC为边�外作等腰直角三角形ABE等腰直角三角形ACD其中∠BAE=∠CAD=90°BD与CE相交于点O sketch template

如图在三角形ABC中∠BAC=∠BCACD平分∠ACBCE⊥AB交AB的延长线于E点若∠DCE=60°求∠BCE的度数．题目和 sketch template

如下图所示， ABC中，AC=BC，∠ACB=30°，∠ADB=45°，那么边长AB是河南华图教育 sketch template

如图在 ABC中BDCE分别为三角形的两条高交于点O �问图11中有个三角形与相似它们是 �连结DE ADE与 ABC是否相似 sketch template

如图在Rt ABC中∠ACB=90°AC=3BC=4将边AC沿CE翻折使点A落在AB上的点D处再将边BC沿CF翻折使点B落在 sketch template

17．如图 ABC中AB=AC∠A=36°BDCE分别为角平分线且交点为F则图中的等腰三角形 A．6个 B．7个 C．8个 D sketch template

如图所示在 ABC中AB=AC∠A=36°BDCE分别为∠ABC与∠ACB的角平分线且相交于点F则图中的等腰三角形有 A．6个 B sketch template

如图在三角形ABC中三角形AEO的面积是1三角形ABO的面积是2三角形BOD的面积是3则四边形DCEO的面积是多�——青夏教育精英 sketch template

如图．已知点BCD在同一条直线上． ABC和 CDE都是等边三角形BE交AC于FAD交CE于H1求证 BCE≌ ACD2 sketch template

如图 ABC为等边三角形以边BC为直径的半圆与边ABAC分别交于DF两点过点D作DE⊥AC垂足为点E．1判断DE与⊙O的位置 sketch template

如图，Rt ABC中，∠C＝90°，AC＝BC，点D、E分别是边AB、AC上的点，把 ADE沿DE折叠，点A恰好落在BC上的点F处，若点F为 sketch template

如图 ABC是边长为2的正三角形点D在 ABC内部且满足DB=DCDB⊥DC点E在边AC上延长ED交线段AB于点H．1若ED sketch template

如图在等腰三角形ABC中AB=1∠A=900点E为腰AC中点点F在底边BC上且FE⊥BE求 CEF的面积——青夏教育精英家教�—— sketch template

如图Rt ABC中∠ABC=90°以AB为直径的⊙O交AC于点DE为BC的中点连接DEOD．1求证DE是⊙O的切线2 sketch template

如图在 ABC中BDCE分别为三角形的两条高交于点O �问图11中有个三角形与相似它们是 �连结DE ADE与 ABC是否相似 sketch template

如图在Rt ABC中∠ACB=90°∠A=30°点O为AB中点点P为直线BC上的动点连接OCOP将线段OP绕点P顺时针旋转60 sketch template

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