如图∠bca=90°pc⊥面abc则在三角形abc三角形pac的边所在的直线中 1与pc垂直的直线有acabbc 2与 Sketch Coloring Page

如图∠bca=90°pc⊥面abc则在三角形abc三角形pac的边所在的直线中 1与pc垂直的直线有acabbc 2与 Template

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sketch #3538

anonymous

anonymous
sketch #3538

sketch #3517 Scratch from Ice Age by VlAd Craciun

anonymous

anonymous
sketch #3517 Scratch from Ice Age by VlAd Craciun

sketch #978

anonymous

anonymous
sketch #978

sketch #5037 Dolphin by Meen Suksoi

anonymous

anonymous
sketch #5037 Dolphin by Meen Suksoi

sketch #2678 Portrait by Jocelyn Alejandra Rantul

Jocelyn Alejandra Rantul
sketch #2678 Portrait by Jocelyn Alejandra Rantul

sketch #3473 Finn by Luana Santos

anonymous

anonymous
sketch #3473 Finn by Luana Santos

sketch #4546 Misaki Mei by Wanis Khelifa

anonymous

anonymous
sketch #4546 Misaki Mei by Wanis Khelifa

sketch #4751 Ruko by Rodrigo Marcos

anonymous

anonymous
sketch #4751 Ruko by Rodrigo Marcos

sketch #5009 Elen Jager from Attack on Titan

anonymous

anonymous
sketch #5009 Elen Jager from Attack on Titan

sketch #2729 Luffy by Jayme Sousa

Jayme Sousa
sketch #2729 Luffy by Jayme Sousa

sketch #2393

anonymous

anonymous
sketch #2393

sketch #2464 Spongebob by sketchmaster

sketchmaster
sketch #2464 Spongebob by sketchmaster

sketch #2699 Girl in shades Ashok Kumar Chaturvedi

Ashok Kumar Chaturvedi
sketch #2699 Girl in shades Ashok Kumar Chaturvedi

sketch #4386 Freddie Mercury by Павел Павлов

anonymous

anonymous
sketch #4386 Freddie Mercury by Павел Павлов

sketch #4704 Slash

anonymous

anonymous
sketch #4704 Slash

sketch #5204

anonymous

anonymous
sketch #5204

sketch #5224

anonymous

anonymous
sketch #5224

sketch #4830

anonymous

anonymous
sketch #4830

sketch #5091 The Red Lady by অনন্ত জলিল

anonymous

anonymous
sketch #5091 The Red Lady by অনন্ত জলিল

sketch #3359 &#;In love and lonely&#; by Irul Ventura

anonymous

anonymous
sketch #3359 &#;In love and lonely&#; by Irul Ventura

sketch #5069 Mad Hatter by Ahmed Mostafa

anonymous

anonymous
sketch #5069 Mad Hatter by Ahmed Mostafa

sketch #2910 Harley Quinn Germaine Hoens

anonymous

anonymous
sketch #2910 Harley Quinn Germaine Hoens

sketch #933 mts

anonymous

anonymous
sketch #933 mts

sketch #3259

anonymous

anonymous
sketch #3259

sketch #20690

anonymous

anonymous
sketch #20690

sketch #5315

anonymous

anonymous
sketch #5315

sketch #5258 Adventure Time by Kheith Ryan Lubiano

anonymous

anonymous
sketch #5258 Adventure Time by Kheith Ryan Lubiano

sketch #5100 Shadow by An Nguyen

anonymous

anonymous
sketch #5100 Shadow by An Nguyen

sketch #2765 Kratos by Nassim Nouri

Nassim Nouri
sketch #2765 Kratos by Nassim Nouri

sketch #5350

anonymous

anonymous
sketch #5350

tomski如图∠bca=90°pc⊥面abc则在三角形abc三角形pac的边所在的直线中 1与pc垂直的直线有acabbc 2与 coloring

如图∠BCA=90°PC⊥面ABC则在三角形ABC三角形PAC的边所在的直线中 1与PC垂直的直线有ACABBC 2与 sketch template

如图∠BCA=90°PC⊥面ABC则在三角形ABC三角形PAC的边所在的直线中 1与PC垂直的直线有ACABBC 2与 sketch template

如图在四边形ABCD中∠ABC=∠ADC=90°AB=BC=10AD=2DC连对角线ACBD相交于点E1�求证BD平分∠ sketch template

如图三棱锥P ABC中PB⊥底面ABC∠BCA=90°PB=BC=CA=4E为PC的中点M为AB的中点点F在PA上且AF sketch template

如图在底面为直角梯形的四棱锥P ABCD中AD∥BC∠ABC＝90°PA⊥面ABCDPA=2AD=2AB=BC=6 1 求证 sketch template

题目：如图，在三角形ABC中，点D是AB的中点，∠DAC=2∠DCA，∠DCB=30度，求∠B的度数知乎 sketch template

如图在 ABC中∠ACB=90°CA=CB点P在 ABC内且PA=3PB=1PC=2求 CPB的度数．小东同学尝试在CP的右侧 sketch template

在 ABC和 DEC中，AC=BC，DC=EC，∠ACB=∠ECD=90°（1）如图1，当点A、C、D在同一条直线上时，求证：AF⊥BD sketch template

如图在四棱锥P ABCD中底面ABCD为直角梯形AD∥BC∠ADC=90°平面PAD⊥底面ABCDQ为AD的中点PA=PD=2 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

$如图四棱锥P ABCD中侧面PAD为等边三角形且垂直于底面ABCDAB=BC=$frac{1}{2}$AD∠BAD=∠ABC=90 sketch template$

如图所示在四棱锥S―ABCD中SA⊥底面ABCD∠BAD=∠ABC= 90°SA=AB=AD=BC=1E为SD中点． 1若F为底 sketch template

如图，在三棱锥P ABC中，平面PAC⊥ 平面ABC，∠ PCA=90°， ABC是边长为4的正三角形，PC=3，M是AB边上的一动点，则PM sketch template

三棱锥P ABC中∠ABC=90°PA=PB=PC则下列说法正确的是 A平面PAC⊥平面ABCB平面PAB⊥平面PBCCPB⊥ sketch template

如图，在三棱锥S－ABC中，∠SAB＝∠SAC＝∠ABC＝90°，SA＝AB，SB＝BC （Ⅰ）证明：平面SBC⊥平面SAB；（Ⅱ）求百度教育 sketch template

如图所示， ABC是等腰直角三角形，∠ACB=90°，AD是BC边上的中线，过C作AD的垂线，交AB于点E，交AD于点F．求证：（1）∠ADC sketch template

如图 ABC中∠ACB=90°AC=6cmBC=8cm．点P从A点出�沿A C路径�终点C运动点Q从B点出�沿B C A路径�终点A sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图所示在直角梯形BCEF中∠CBF=∠BCE=90°AD分别是BFCE上的点AD∥BC且AB=DE=2BC=2AF．将四边形 sketch template

在 ABC中AD平分∠BAC交BC于D．1如图1∠MDN的两边分别与ABAC相交于MN两点过D作DF⊥AC于FDM=DN证明 sketch template

18．如图已知斜三棱柱ABC A1B1C1中∠BCA=90°AC=BC=a点A1在底面ABC上的射影恰为AC的中点DBA1⊥AC1 sketch template

如图在四棱锥P ABCD中PA⊥平面ABCD四边形ABCD为直角梯形AD//BC且AD&gtBC∠DAB=∠ABC=90°PA=AB sketch template

18． 如图在三棱锥P ABC中AB⊥BCAB＝BC＝kPA点OD分别是ACPC的中点OP⊥底面ABC． Ⅰ求证OD∥平面 sketch template

如图在三棱锥PABC中AC = BC 2∠ACB 90°AP BP ABPC⊥AC． 1 求证PC⊥AB sketch template

20．如图在四棱锥P ABCD中底面ABCD是菱形∠BAD=600AB=2PA=1PA⊥平面ABCD E是PC的中点F是AB的 sketch template

在如图所示的几何体中四边形ABCD为矩形平面ABEF⊥平面ABCDEF∥AB∠BAF=90°AD=2AB=AF=2EF=1点P在 sketch template

如图点D在BC的延长线上DE⊥AB于E交于AC于F∠B＝50°∠CFD＝60°则∠ACB＝．题目和参考答案——青夏教育精英家教�—— sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

18．如图所示在四棱锥P ABCD中底面ABCD是一直角梯形∠BAD=90° AD∥BC AB = BC A AD 2a sketch template

如图，在四棱锥P—ABCD中，平面PAD⊥平面ABCD ， AD//BC AB＝BC＝PA＝1，AD＝2，∠PAD＝∠DAB＝90°，点E sketch template

如图所示在直角三角形ABC中∠BAC=90°AD⊥BCBE平分∠ABC交AD于EEF∥AC则下列结论不一定成立的是 A．∠1 sketch template

如图在底面是菱形的四棱锥 P ABCD中∠ABC=60°PA⊥平面ABCD点EFG分别为CDPDPB的中点．PA=AD=2 sketch template

如图在三棱柱ABC A1B1C1中∠BAC=90°AB=AC=2AA1=4A1在底面ABC的射影为BC的中点ED是B1C1的中点 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

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