三棱锥p abc中∠abc=90°pa=pb=pc则下列说法正确的是 A平面pac⊥平面abcb平面pab⊥平面pbccpb⊥ Sketch Coloring Page

三棱锥p abc中∠abc=90°pa=pb=pc则下列说法正确的是 A平面pac⊥平面abcb平面pab⊥平面pbccpb⊥ Template

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anonymous
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anonymous
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anonymous
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tomski三棱锥p abc中∠abc=90°pa=pb=pc则下列说法正确的是 a平面pac⊥平面abcb平面pab⊥平面pbccpb⊥ coloring

如图，在三棱锥P−ABC中，AB=BC=2√2，PA=PB=PC=AC=4，O为AC的中点．证明：PO⊥平面ABC．百度教育 sketch template

如图，在三棱锥P ABC中，AB=BC=2√ 2，PA=PB=PC=AC=4，O为AC的中点（1）证明：PO⊥ 平面ABC；（2）若点M在棱 sketch template

在三棱锥P ABC中PA⊥平面ABC∠BAC=90°DEF分别是棱ABBCCP的中点AB=AC=1PA=2则直线PA与平面 sketch template

正三棱锥的高是多� 百度经验 sketch template

三棱锥P ABC中PA=PB=PC=AC=1 ABC是等腰直角三角形∠ABC=90°E为PC中点则BE与PAC平面所成的角的大小等于 sketch template

三棱锥P ABC中∠ABC=90°PA=PB=PC则下列说法正确的是 A平面PAC⊥平面ABCB平面PAB⊥平面PBCCPB⊥ sketch template

如图三棱锥P ABC中PB⊥底面ABC∠BCA=90°PB=BC=CA=4E为PC的中点M为AB的中点点F在PA上且AF sketch template

如图，在三棱锥P ABC中，平面PAC⊥ 平面ABC，∠ PCA=90°， ABC是边长为4的正三角形，PC=3，M是AB边上的一动点，则PM sketch template

如图在三棱锥P ABC中AC＝BC＝2∠ACB＝90°AP＝BP＝ABPC⊥AC． Ⅰ求证PC⊥AB Ⅱ求直线BC与平面 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

9．如图在三棱锥P – ABC中PA = PB PC BC 2且则PA与底面ABC所成角为 A．30° B．60 sketch template

如图在三棱锥P ABC中PA=PB=PC=AC=4AB=BC=2．1若点P在底面ABC内的射影是点O试指出点O的位置并说明理由 sketch template

20．依题意四面体P ABC中∠APB=∠BPC=∠CPA=90°设PA=xPB=yPC=z 则AC=BC=AB= 2分 sketch template

三棱锥P ABC中底面 ABC是边长为2的正三角形PA⊥底面ABC且PA=2则此三棱锥外接球的半径为 A．B．C．2D．题目和 sketch template

18．如图三棱锥P ABC中 PC平面ABCPC=AC=2AB=BCD是PB上一点且CD平面PAB． I 求证AB平面 sketch template

解1PA＝AB＝2PB＝PA2 AB2＝PB2∠PAB＝90O即PA⊥AB同理PA⊥AE又AB∩AE＝APA⊥平面 sketch template

18．从三棱锥P ABC的顶点沿着三条侧棱PAPBPC剪开成平面图形得到 P1P2P3且P1P2=P2P3 图1 图2 1在 sketch template

已知三棱锥P ABC中顶点P在底面的射影O是三角形ABC的内心关于这个三棱锥有三个�题�侧棱PA=PB=PC�侧棱PAPBPC两两 sketch template

在三棱锥P ABC中 PAC和 PBC是边长为$sqrt{2}$的等边三角形AB=2O是AB中点E是BC中点．Ⅰ求证平面PAB sketch template

15．三棱锥P ABC的四个顶点在同一球面上若PA⊥底面ABC底面ABC是直角三角形PA＝2AC＝BC＝1则此球的表面积为——青夏 sketch template

在三棱锥P ABC中 PAC和 PBC是边长为2的等边三角形AB=2O是AB中点．1在棱PA上求一点M使得OM∥平面PBC2 sketch template

如图在三棱锥P ABC中PA垂直于平面ABCAC⊥BC．求证BC⊥平面PAC．题目和参考答案——青夏教育精英家教�—— sketch template

三棱锥P ABC中，D，E分别为PB，PC的中点，记三棱锥D ABE的体积为V1，P ABC的体积为V2，则V1V2=1414 百度知道 sketch template

如图，在 ABC中，∠ACB=90°，AC=BC，P是 ABC内的一点，且PB=1，PC=2，PA=3，则∠BPC的度数为百度教育 sketch template

9．在三棱锥P ABC中PA⊥ACPB⊥BCAC⊥BCPAPB与平面ABC成角为30°和45°． 1若P到底面ABC的距离为h sketch template

百度教育 sketch template

$三棱锥P ABCPA=PB=PC=2∠APC=∠APB=∠BPC=$frac{π}{6}$一只蚂蚁从A处出�沿三棱锥的侧面爬一�最短 sketch template$

已知三棱锥P ABC中顶点P在底面的射影O是三角形ABC的内心关于这个三棱锥有三个�题�侧棱PA=PB=PC�侧棱PAPBPC两两 sketch template

7．三棱锥P ABC中 ABC为等边三角形PA⊥面ABCPA=AB则二面角A PB C 的平面角的正切值为 A． B．——青夏 sketch template

如图三棱锥P ABC的底面ABC是以AC为斜边的直角三角形且顶点P在底面的射影是 ABC外心设PB=AB=1BC=2．1求证面 sketch template

如图三棱锥P ABC的三条棱PCCACB两两互相垂直并且∠PAC=30PB=BC=3 �求二面角B PA C的大小 �设点C在 sketch template

如图，在四棱锥P ABCD中，平面PAB⊥平面ABCD，AD∥BC，∠ABC=90°，PA=PB=3，BC=1，AB=2，AD=3，O是AB sketch template

22．在五棱锥P ABCDE中PA=AB=AE=2aPB=PE=aBC=DE=a∠EAB=∠ABC=∠DEA=90°． 1求证 sketch template

5．如图PA上平面ABC ABC中BC⊥AC则 PBC是 A．锐角三角形 B．直角三角形 C．钝角三角形 D．以上都有可能——青夏教育 sketch template

百度教育 sketch template

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