如图所示电路中电源电动势为e内阻为r电阻r2r3为定值电阻r1为�动变阻器ab为水平放置的电容器的上下两个极板．当�动变阻器r1 Sketch Coloring Page

如图所示电路中电源电动势为e内阻为r电阻r2r3为定值电阻r1为�动变阻器ab为水平放置的电容器的上下两个极板．当�动变阻器r1 Template

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tomski如图所示电路中电源电动势为e内阻为r电阻r2r3为定值电阻r1为�动变阻器ab为水平放置的电容器的上下两个极板．当�动变阻器r1 coloring

一轮复习：含容电路 知乎 sketch template

如图所示电源电动势E=24V内阻r=4ΩR0=1Ω直流电动机内阻R0′=1Ω当调节�动变阻器R1为某值时可使甲电路输出功率最大调节 sketch template

一轮复习：含容电路 知乎 sketch template

如图所示的电路中，电源电动势为，内阻为，四个定值电高途 sketch template

在如图所示电路中电源电动势E=6V内阻r=1Ω保护电阻R=6Ω�动变阻器总电阻R=20Ω现闭合电键S问在�片P从a�到b的过程中 sketch template

如图所示是测定两个电源的电动势和内电阻实验中得到的电流和路端电压图线现将两电源分别与一�动变阻器串联电源1所在电路中电流为I1路端电压为 sketch template

高中物理：等效电源法的应用 电阻 sketch template

如图所示，电源电压恒为18V，定值电阻R1=20Ω，�动变阻器R2标有“40Ω 05A”，电流表A的量程为006A，电压表量程为0 sketch template

如图所示电路中接电动势为4V内电阻为2Ω的直流电源电阻R1R2R3R4的阻值均为4Ω电容器的电容为30μF电流表的内阻不计当 sketch template

电源、电阻、电流表与开关连接成如图所示的电路。已知电阻R=20Ω，电源的内阻r=10Ω，闭合开关S后，电流表示数I=050A。 sketch template

如图所示电路中电源电动势为E内阻为r电阻R2R3为定值电阻R1为�动变阻器AB为水平放置的电容器的上下两个极板．当�动变阻器R1 sketch template

在图所示的电路中电源电动势为E内电阻为r 在�动变阻器的�动触片P从图示位置�下�动的过程中A电路中的总电阻增大B电路中的总电流变大 sketch template

如图所示电源电动势为E内阻为r电路中的R2R3分别为总阻值一定的�动变阻器R0为定值电阻R1为光敏电阻其电阻随光照强度增大而减小 sketch template

在图所示的电路中电源电动势为E内电阻为r．在�动变阻器的�动触片P从图示位置�右�动的过程中 A．电路中的总电流变大B．路端电压变大C sketch template

15．如图a所示电路中电源电动势E=12V内阻r=2ΩR1＝4ΩR2＝6ΩR3＝3Ω 1若在CD间连一个理想电压表其 sketch template

百度教育 sketch template

高中物理必修三·电学实验之【测定电源电动势和内阻� 知乎 sketch template

一轮复习：含容电路 知乎 sketch template

如图所示的电路中电源的电动势E和内电阻r恒定不变电灯L恰能正常�光如果�动变阻器的�片�b端�动则 A．电灯L更亮电流表的示数 sketch template

如图所示直线A为电源的路端电压U与电流I关系的图象直线B是电阻R的两端电压U与电流I的关系图象用该电源与电阻R组成闭合电路则电阻R sketch template

一轮复习：含容电路 知乎 sketch template

一轮复习：含容电路 知乎 sketch template

如图所示的电路中电源的电压保持不变R1为定值电阻R2为�动变阻器闭合开关S�片P�右移动时则A．电流表A的示数变大B．电压表V的示 sketch template

如图所示电源电动势为E内阻为rR1＞r当电路中�动变阻器R2的�动触头P�上�动时以下说法正确的是 A．电容器C的下极板的带电量 sketch template

如图所示的电路中电源电动势E=6V内阻r=1Ω电阻R1=6ΩR2=5ΩR3=3Ω电容器的电容C=2×10 5F若将开关S闭合 sketch template

如图所示电路中已知电容C=2μF电源电动势ε=12V内电阻不计R1R2R3R4=1263则电容器极板所携带的电量为 A sketch template

如图所示的电路中，电源电压保持不变。闭合开关S后，�片P从b端移动到a端的过程，电压表示数U与电流表示数I的关系图像如图所示。下列说法正确的是（ sketch template

如图所示的电路中电源的电动势E和内电阻r恒定不变电灯L恰能正常�光如果�动变阻器的�片�b端�动则 A．电灯L更亮电流表的示数 sketch template

如图所示电路中电源电动势为E内阻为r电阻R1R2为定值电阻R为�动变阻器AB为电容器的两个极板电压表和电流表均为理想表电源 sketch template

如图所示的电路中电源的电动势E和内阻r恒定不变变阻器R1的�片P处在如图位置时电灯L正常�光．现将�片P�右移动则在该过程中 A sketch template

如图所示的电路中电源电动势E=6V内阻r=1Ω电阻R1=6ΩR2=5ΩR3=3Ω电容器的电容C=2×10 5F若将开关S闭合 sketch template

如图所示的电路中电路消耗的总功率为30W电阻R1为3ΩR2为6Ω电源内阻r为02Ω电源的效率为94%求1电源的电动势2 sketch template

如图所示电路中电源电动势为12V电源内阻为10Ω电路中的电阻R0为15Ω小型直流电动机M的内阻为05Ω闭合开关S后电动机转动 sketch template

在如图所示电路中电源电动势为ε内阻为r闭合电键后当�动变阻器的�片P处于图中R的中点位置时小灯泡L1L2L3的亮度相同．若将�片 sketch template

如图所示的电路中电源电动势恒定内阻不能忽略电流表和电压表均为理想电表下列说法中正确的是 A．若R1短路电流表示数变小电压表示数 sketch template

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