如图所示三棱锥a Bcd其中ab=cd=5ac=bd=6ad=bc=7则该三棱锥外接球的表面积为55π．题目和参考答案——青夏教育 Sketch Coloring Page

如图所示三棱锥a Bcd其中ab=cd=5ac=bd=6ad=bc=7则该三棱锥外接球的表面积为55π．题目和参考答案——青夏教育 Template

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tomski如图所示三棱锥a bcd其中ab=cd=5ac=bd=6ad=bc=7则该三棱锥外接球的表面积为55π．题目和参考答案——青夏教育 coloring

如图所示三棱锥A BCD其中AB=CD=5AC=BD=6AD=BC=7则该三棱锥外接球的表面积为55π． 题目和参考答案——青夏教育 sketch template

如图，在三棱锥A BCD中，平面ABD⊥ 平面BCD，AB=AD，O为BD的中点1证明：OA⊥ CD；2若 OCD是边长为1的等边 sketch template

【步步高学案导学设计�2014 2015学年高中人教B版数学必修二课时作业：第1章 122 第3课时 Word文档在线阅读与下载无忧文档 sketch template

如图，在三棱锥A BCD中，AB=AC=BD=CD=3，AD=BC=2，M，N分别是AD，BC的中点求异面直线AN，CM所成角的余弦值百度教育 sketch template

18． 如图三棱锥P ABC中 PC平面ABCPC=AC=2AB=BCD是PB上一点且CD平面PAB． I 求证AB平面 sketch template

一个三棱锥的各个面均为正三角形以每个面的中心为顶点构成一个新三棱锥若新三棱锥体积为2求原三棱锥体百度知道 sketch template

百度教育 sketch template

如图在三棱锥A BCD中BC=CD=DBAB=AC=ADEF为棱BDAD的中点若EF⊥CF则直线BD与平面ACD所成的角为 sketch template

如图三棱锥A BCD中AB=AC=BD=CD=3AD=BC=2点MN分别是ADBC的中点则异面直线ANCM所成的角的余弦值为 sketch template

如图，三棱锥A BCD中，DA=DB=DC，BD⊥CD，∠ADB=∠ADC=60°，E为BC中点．（1）证明BC⊥DA；（2）点F满足，求 sketch template

16．如图三棱锥P ABC中 PC平面ABCPC=AC=2AB=BCD是PB上一点且CD平面PAB． I 求证AB平面PCB sketch template

在四棱锥P ABCD中，PD⊥底面ABCD，CD∥AB，AD=DC=CB=1，AB=2，DP=．（1）证明：BD⊥PA；（2）求PD与平面 sketch template

如图在四棱锥P ABCD中底面ABCD是以AC为直径的圆的内接四边形AC⊥BDF是PC的中点∠BAC=60°PD⊥平面ABC．1 sketch template

为什么正四面体顶点在底面的投影在底面三角形的中心�？知乎 sketch template

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如图在四棱锥P—ABCD中PA⊥底面ABCDAB⊥ADAC⊥CD∠ABC=60°PA=AB=BCE是PC的中点1证明AE sketch template

下面有四个�题1各个侧面都是等腰三角形的棱锥是正棱锥2三条侧棱都相等的棱锥是正棱锥3底面是正三角形的棱锥是正三棱锥4 sketch template

如图，在四棱锥P ABCD中，PA⊥ 平面ABCD，AD⊥ AB，AB∥ CD，AB=AD=AP= 1 2CD=2，E为PC的中点 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图在四棱锥P ABCD中底面ABCD是矩形侧棱PA垂直于底面EF分别是ABPC的中点 1求证CD⊥PD 2求证 sketch template

怎么快速求多面体外接球半径？知乎 sketch template

19．如图所示四棱锥P ABCD中底面ABCD为直角梯形点E在棱PA上且PE=2EA 1 求异面直线PA与CD所成的角 2 sketch template

19． 如图在五棱锥S ABCDE中SA⊥底面ABCDE SA=AB=AE=2BC=DE=∠BAE=∠BCD=∠CDE=120 sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图在底面是菱形的四棱锥 P ABCD中∠ABC=60°PA⊥平面ABCD点EFG分别为CDPDPB的中点．PA=AD=2 sketch template

15．三棱锥P ABC的四个顶点在同一球面上若PA⊥底面ABC底面ABC是直角三角形PA＝2AC＝BC＝1则此球的表面积为——青夏 sketch template

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如图所示在四棱锥P ABCD中底面ABCD为菱形且∠DAB=60°PA=PDM为CD的中点BD⊥PM．1求证平面PAD⊥平面 sketch template

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如图在四棱锥P ABCD中平面PAD⊥平面ABCDPA⊥PDPA=PDAB⊥ADAB=1AD=2AC=CD=$sqrt{5 sketch template

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如图所示的四边形ABCD是边长为2的正方形，对角线AC ， BD相交于点O 将 BDA沿BD折起到 BDA的位置，使平面ABD⊥平面BCD sketch template

精选高考数学二轮复习第1部分专题五立体几何1 5 1空间几何体的三视图表面积及体积限时规范训练文 Word文档在线阅读与下载无忧文档 sketch template

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