一带电粒子从电场中的a点运动到b点径迹如图中虚线所示不计粒子所受重力则下列说法正确的是 A．粒子带正电b．粒子的速度逐渐减小c．粒子 Sketch Coloring Page

一带电粒子从电场中的a点运动到b点径迹如图中虚线所示不计粒子所受重力则下列说法正确的是 A．粒子带正电b．粒子的速度逐渐减小c．粒子 Template

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tomski一带电粒子从电场中的a点运动到b点径迹如图中虚线所示不计粒子所受重力则下列说法正确的是 a．粒子带正电b．粒子的速度逐渐减小c．粒子 coloring

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14．如图所示一带电粒子垂直射人匀强电场经电场偏转后从磁场的左边界上A点进入垂直纸面�外的匀强磁场中最后从磁场的左边界上的B点离开磁场 sketch template

某电场的电场线的分布如图所示一个带电粒子只在电场力作用下由M点沿图中虚线所示的路径运动通过N点则下列判断正确的是A．粒子带正电B．粒子在M sketch template

题目如图所示虚线 Abc 代表电场中三条电场线实线为一带正电的粒子仅在电场力作用下通过该区域的运动轨迹PQ 是这条轨迹上的两点 sketch template

图中的实线表示电场线虚线表示只受电场力作用的带电粒子的运动轨迹．粒子先经过M点再经过N点．可以判定 A．M点的电势大于N点的电势B．M sketch template

等量异种点电荷和等量同种点电荷连线上和中垂线上场强及电势的变化规律 1如图所示等量异种点电荷的连线上从正电荷到负电荷电势越来越低 sketch template

图中的实线表示电场线虚线表示只受电场力作用的带电粒子的运动轨迹．粒子先经过M点再经过N点．可以判定 A．M点的电势大于N点的电势B．M sketch template

5．一负电荷从电场中A点静止释放只受电场力作用沿电场线运动到B点它运动的v T图象如图甲所示则两点AB所在区域的电场线分布情况 sketch template

将一电荷量为 Q的小球放在不带电的�属球附�所形成的电场线分布如图所示�属球表面的电势处处相等ab为电场中的两点则Aa点的电场强度 sketch template

经过探究，某同学�现：点电荷和无限大的接地�属平板间的电场（如图甲所示）与等量异种点电荷之间的电场分布（如图乙所示）完全相同。图丙中点电荷 Q sketch template

10．一带电粒子从电场中的A点运动到B点径迹如图中虚线所示不计粒子所受重力则 A．粒子带正电 B．粒子加速度逐渐减小 C．A点的场强大于 sketch template

如图所示仅在电场力作用下一带电粒子沿图中虚线从A运动到B则 A．电场力做正功B．加速度减小C．电势能增加D．加速度增大题目和参考 sketch template

如下图为一匀强电场某带电粒子从A点运动到B点．在这一运动过程中克服重力做的功为20 J电场力做的功为15 J．则下列说法正确的是 sketch template

三个点电荷电荷量分别为 2q Q Q它们�围的电场线如图所示其中一条电场线上有AB两点．下列说法正确的是AA点的场强小于B点场强B sketch template

两个点电荷形成电场的电场线分布如图所示PQ是电场中的两个点则 A．在两个点电荷中正电荷的电荷量较大 B．将一个带正电的试探电荷从 sketch template

有一个带电量为的点电荷从某电场中的A点移到B点电荷克服电场力做的功从B点移到C点电场力对电荷做的功其中下列说法正确的是A．ABC sketch template

一带电粒子仅在电场力的作用下从电场中的A点运动到B点运动轨迹如图中虚线所示则正确的是 A．粒子带正电 B 粒子在A处的电势能大于在 sketch template

一带电粒子射入固定在O点的点电荷电场中图中实线同心圆表示电场的等势面虚线abc表示粒子仅受电场力作用的运动轨迹．则可断定 A．带电粒子 sketch template

如图所示某带电粒子在一个匀强电场中从A点运动到B点在这一运动过程中克服重力做的功为20 J电场力做的功为15 J．则下列说法中正确的 sketch template

10．一带电粒子从电场中的A点运动到B点径迹如图中虚线所示不计粒子所受重力则 A．粒子带正电 B．粒子加速度逐渐减小 C．A点的场强大于 sketch template

某带电粒子仅在电场力作用下由A点运动到B点电场线粒子在A点的初速度以及运动轨迹如图所示能够判定正确的是 A．该粒子在AB两点的受力方� sketch template

一带电粒子沿图中AB曲线穿过匀强电场中的一组等势面等势面的电势关系满足φa>φb>φc>φd若不计粒子所受重力则 A．粒子一定带正电 sketch template

一带电粒子从电场中的A点运动到B点径迹如图中虚线所示不计粒子所受重力则下列说法正确的是 A．粒子带正电B．粒子的速度逐渐减小C．粒子 sketch template

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