7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Sketch Coloring Page

7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— Template

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tomski7．如图5点def分别是abbcca边的中点则图中的平行四边形一共有 3个 d4个——青夏教育精英家教�—— coloring

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

7．如图5点DEF分别是ABBCCA边的中点则图中的平行四边形一共有 3个 D4个——青夏教育精英家教�—— sketch template

14．如图点DEF分别是 ABC三边上的中点．若 ABC 的面积为12则 DEF的面积为．——青夏教育精英家教�—— sketch template

$如图在 ABC中点D是AB的中点连接CDCD=BDtan∠CDB=$frac{24}{7}$在BC上取一点F使BF sketch template$

如图点DE分别在 ABC的边上ABAC上且若DE=3BC=6AB=8则AE的长为——青夏教育精英家教�—— sketch template

题目如图圆内接四边形ABCD两组对边的延长线分别相交于点EF且∠A=55°∠E=30°则∠F= ．答案40°解析试题分析 sketch template

题目1如图1在四边形ABCD中FE分别是BCAD的中点连结EF并延长分别与BACD的延长线交于点MN则∠BME=∠ sketch template

如图在等边 ABC 中DEF分别为ABBCCA上一点且AD=BE=CF若每三个三角形两两全等为一组则图中全等的三角形组数为 sketch template

如图平面直角坐标系中在边长为1的正方形的边上有一动点沿运动一�则的纵坐标与点走过的路程之间的函数关系用图象表示大致是 题目和参考答案 sketch template

23． 如图 ABC中点DE分别在边ABAC上连接DE并延长交BC的延长线于点F连接DCBE．若∠BDE ∠BCE=180 sketch template

如图在平行四边形ABCD中AB=6BC=4∠B=60°点E是边AB上的一点点F是边CD上一点将平行四边形ABCD沿EF折叠得到 sketch template

题目已知如图 ABC中∠A＝90°AB＝ACD是BC边上的中点EF分别是ABAC上的点且∠EDF＝90°求证BE sketch template

如图已知长方体ABCD A1B1C1D1中AB=BC=2AA1=1点EF分别是A1B1B1C1的中点点O是AB与BD的交点．1 sketch template

已知在 ABC中内切圆I和边BCCAAB分别相切于点DEF．1若∠A=60°求∠FDE的度数2若∠A=130°求∠ sketch template

如图 ABC中点DEF分别在边BCABCA上且DE∥CADF∥BA则�如果∠BAC=90°那么四边形AEDF是矩形�如果 sketch template

如图已知 ABC中AB=AC∠BAC=90°点D为BC的中点点EF分别在直线ABAC上运动且始终保持AE=CF．1如图� sketch template

如图，在三角形ABC中，D、E、F分别是BC、CA、AB上的点，AD、BE、CF相交于一点O，这样三角形ABC被分成6个三角形，其中4个三角形 sketch template

如图1图2 ABC是等边三角形DE分别是ABBC边上的两个动点始终保持BD=CE．1当点DE运动到如图1所示的位置时求证 sketch template

20．28 如图EF分别是矩形ABCD的对角线AC和BD上的点且AE=DF求证BE=CF 答案证明∵四边形ABCD为矩形 sketch template

题目如图矩形ABCD中AD=5AB=7点E为DC上一个动点把 ADE沿AE折叠当点D的对应点D′落在∠ABC的角平分线上时DE sketch template

如图在 ABC中点DEF分别在BCABAC上且DE∥ACDF∥AB．1如果∠BAC=90°那么四边形AEDF是 形2 sketch template

如图点DE分别是 ABC的边ABAC的中点若DE=6则BC=12．题目和参考答案——青夏教育精英家教�—— sketch template

如图点DEFB在同一直线上AB∥CDAE∥CF且AE=CF若BD=10BF=2则EF= ——青夏教育精英家教�—— sketch template

如图，AB为⊙O的直径，C、D为⊙O上的两点，且AC平分∠BAD，过点C作直线EF⊥AD，交AD的延长线于点E． sketch template

题目如图在Rt ABC中AB=6 ∠BAC=30 ∠BAC的平分线交BC于点DEF分别是线段AD和AB上的动点则BE EF的 sketch template

百度教育 sketch template

如图等边三角形ABC中点DEF分别为边ABACBC的中点M为直线BC动点 DMN为等边三角形1如图1当点M在点B左侧时 sketch template

如图在 ABC中∠BAC=90°AB=AC点DE在BC上且∠DAE=45°若DE=$sqrt{15}$CD=$sqrt sketch template

如图等边 ABC中点D在AB上点E在BC上AD=BE．AE和CD相交于点P求证∠CPE=60°．题目和参考答案——青夏教育精英家教�—— sketch template

如图AB是半圆O的直径点C在半圆O上AB=5cmAC=4cm．D是弧BC上的一个动点连接AD过点C作CE⊥AD于E连接BE在点 sketch template

如图在矩形纸片ABCD中已知AB=1BC=$sqrt{3}$点E在边CD上移动连接AE将多边形ABCE沿直线AE翻折得到多边形 sketch template

如图AD是 ABC的角平分线DE⊥AB于点ES ABC=9DE=2AB=5则边AC的长是 A3B4C5D6 题目和 sketch template

如图在 ABC中正方形EDCF的三个顶点EDF都在三角形的边长另一个顶点C与三角形的顶点重合且AC=4BC=6求ED的长 sketch template

如图1在 ABC中AC=BC∠ACB=90°点D为AB边中点以点D为顶点作∠PDQ=90°DPDQ分别交直线ACBC于EF sketch template

如图点DE分别在 ABC的边上ABAC上且若DE=3BC=6AB=8则AE的长为——青夏教育精英家教�—— sketch template

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